MS AccessDateDiff() Function
Example
Return the difference between two dates, in years:
SELECT DateDiff("yyyy", #13/01/1998#, #09/05/2017#);
Try it Yourself »Definition and Usage
The DateDiff() function returns the difference between two dates.
Syntax
DateDiff(datepart,date1,date2,firstdayofweek, firstweekofyear)
Parameter Values
| Parameter | Description |
|---|---|
| datepart | Required. The part to return. Can be one of the following values:
|
| date1 anddate2 | Required. The two dates to calculate the difference between |
| firstdayofweek | Optional. Specifies the first day of the week. Can be one of the following values:
|
| firstdayofyear | Optional. Specifies the first week of the year. Can be one of the following values:
|
Technical Details
| Works in: | From Access 2000 |
|---|
More Examples
Example
Return the difference between two dates, in months:
SELECT DateDiff("m", #13/01/1998#, #09/05/2017#);
Try it Yourself »Example
Return the difference between a specified date and today's date, in days:
SELECT DateDiff("d", #13/01/1998#, Date());
Try it Yourself »
