Python Math: Find the smallest multiple of the first n numbers
10.Smallest Multiple and Factors
Write a Python program to find the smallest multiple of the first n numbers. Also, display the factors.
Sample Solution:
Python Code:
def smallest_multiple(n): if (n<=2): return n i = n * 2 factors = [number for number in range(n, 1, -1) if number * 2 > n] print(factors) while True: for a in factors: if i % a != 0: i += n break if (a == factors[-1] and i % a == 0): return i print(smallest_multiple(13))print(smallest_multiple(11))print(smallest_multiple(2))print(smallest_multiple(1))Sample Output:
[13, 12, 11, 10, 9, 8, 7]360360[11, 10, 9, 8, 7, 6]2772021
Flowchart:
For more Practice: Solve these Related Problems:
- Write a Python program that finds the smallest common multiple of the first n natural numbers and prints the factors that contribute to it.
- Write a Python function to calculate the least common multiple (LCM) of numbers from 1 to n and display its prime factorization.
- Write a Python script to compute the smallest multiple for a given n, then list all factors of that multiple in descending order.
- Write a Python program to determine the smallest number divisible by all numbers from 1 to n and verify its divisibility using a loop.
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Previous: Write a Python program to calculate the discriminant value.
Next: Write a Python program to calculate the difference between the squared sum of first n natural numbers and the sum of squared first n natural numbers.(default value of number=2).
Python Code Editor:
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