Python math.isqrt() Method

The Pythonmath.isqrt() method is used to calculate the integer square root of a non-negative integer. Mathematically, it returns the largest integer "x" such that "x²" is less than or equal to "n".

Generally, for a non-negative integer "n", the integer square root "x", denoted as isqrt(n), satisfies the condition −

x = √⌊n⌋

Where, ⌊.⌋ denotes the floor method, which returns the largest integer less than or equal to the argument. For example, if n = 25, then isqrt(25) = √⌊25⌋ = 5, because 5² = 25.

Syntax

Following is the basic syntax of the Pythonmath.isqrt() method −

math.isqrt(n)

Parameters

This method accepts an integer as a parameter representing a non-negative number for which you want to calculate the integer square root.

Return Value

The method returns an integer, which represents the integer square root of the given value "n".

Example 1

In the following example, we are calculating the integer square root of "25" using themath.isqrt() method −

import mathresult = math.isqrt(25)print("The result obtained is:",result)

Output

The output obtained is as follows −

The result obtained is: 5

Example 2

Here, we calculate the square root of "0" using themath.isqrt() method −

import mathresult = math.isqrt(0)print("The result obtained is:",result)

Output

Following is the output of the above code −

The result obtained is: 0

Example 3

Now, we calculate the integer square root of "999999999". Since theisqrt() method returns an integer, it truncates the decimal part from the resultant value −

import mathresult = math.isqrt(999999999)print("The result is:",result)

Output

We get the output as shown below −

The result obtained is: 31622

Example 4

In this example, we use a variable "n" to store the number "144". We then calculate the integer square root of "n" using themath.isqrt() method −

import mathn = 144result = math.isqrt(n)print("The result obtained is:",result)

Output

The result produced is as shown below −

The result obtained is: 12