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Data Structures & Algorithms Tutorial

Doubly Linked List Data Structure



What is Doubly Linked List?

Doubly Linked List is a variation of Linked list in which navigation is possible in both ways, forward as well as backward easily as compared to Single Linked List. Following are the important terms to understand the concept of doubly linked list.

  • Link − Each link of a linked list can store a data called an element.

  • Next − Each link of a linked list contains a link to the next link called Next.

  • Prev − Each link of a linked list contains a link to the previous link called Prev.

  • Linked List − A Linked List contains the connection link to the first link called First and to the last link called Last.

Doubly Linked List Representation

Doubly Linked List Representation

As per the above illustration, following are the important points to be considered.

  • Doubly Linked List contains a link element called first and last.

  • Each link carries a data field(s) and a link field called next.

  • Each link is linked with its next link using its next link.

  • Each link is linked with its previous link using its previous link.

  • The last link carries a link as null to mark the end of the list.

Basic Operations in Doubly Linked List

Following are the basic operations supported by a list.

  • Insertion − Adds an element at the beginning of the list.

  • Insert Last − Adds an element at the end of the list.

  • Insert After − Adds an element after an item of the list.

  • Deletion − Deletes an element at the beginning of the list.

  • Delete Last − Deletes an element from the end of the list.

  • Delete − Deletes an element from the list using the key.

  • Display forward − Displays the complete list in a forward manner.

  • Display backward − Displays the complete list in a backward manner.

Doubly Linked List - Insertion at the Beginning

In this operation, we create a new node with three compartments, one containing the data, the others containing the address of its previous and next nodes in the list. This new node is inserted at the beginning of the list.

Algorithm

1. START2. Create a new node with three variables: prev, data, next.3. Store the new data in the data variable4. If the list is empty, make the new node as head.5. Otherwise, link the address of the existing first node to the next variable of the new node, and assign null to the prev variable.6. Point the head to the new node.7. END

Example

Following are the implementations of this operation in various programming languages −

#include <stdio.h>#include <string.h>#include <stdlib.h>#include <stdbool.h>struct node {   int data;   int key;   struct node *next;   struct node *prev;};//this link always point to first Linkstruct node *head = NULL;//this link always point to last Linkstruct node *last = NULL;struct node *current = NULL;//is list emptybool isEmpty(){   return head == NULL;}//display the doubly linked listvoid printList(){   struct node *ptr = head;   while(ptr != NULL) {      printf("(%d,%d) ",ptr->key,ptr->data);      ptr = ptr->next;   }}//insert link at the first locationvoid insertFirst(int key, int data){   //create a link   struct node *link = (struct node*) malloc(sizeof(struct node));   link->key = key;   link->data = data;   if(isEmpty()) {      //make it the last link      last = link;   } else {      //update first prev link      head->prev = link;   }   //point it to old first link   link->next = head;   //point first to new first link   head = link;}void main(){   insertFirst(1,10);   insertFirst(2,20);   insertFirst(3,30);   insertFirst(4,1);   insertFirst(5,40);   insertFirst(6,56);   printf("\nDoubly Linked List: ");   printList();}

Output

Doubly Linked List: (6,56) (5,40) (4,1) (3,30) (2,20) (1,10)
#include <iostream>#include <cstring>#include <cstdlib>#include <cstdbool>struct node {   int data;   int key;   struct node *next;   struct node *prev;};//this link always point to first Linkstruct node *head = NULL;//this link always point to last Linkstruct node *last = NULL;struct node *current = NULL;//is list emptybool isEmpty(){   return head == NULL;}//display the doubly linked listvoid printList(){   struct node *ptr = head;   while(ptr != NULL) {      printf("(%d,%d) ",ptr->key,ptr->data);      ptr = ptr->next;   }}//insert link at the first locationvoid insertFirst(int key, int data){   //create a link   struct node *link = (struct node*) malloc(sizeof(struct node));   link->key = key;   link->data = data;   if(isEmpty()) {      //make it the last link      last = link;   } else {      //update first prev link      head->prev = link;   }   //point it to old first link   link->next = head;   //point first to new first link   head = link;}int main(){   insertFirst(1,10);   insertFirst(2,20);   insertFirst(3,30);   insertFirst(4,1);   insertFirst(5,40);   insertFirst(6,56);   printf("Doubly Linked List: ");   printList();   return 0;}

Output

Doubly Linked List: (6,56) (5,40) (4,1) (3,30) (2,20) (1,10)
//Java code for doubly linked listimport java.util.*;class Node {    public int data;    public int key;    public Node next;    public Node prev;    public Node(int data, int key) {        this.data = data;        this.key = key;        this.next = null;        this.prev = null;    }}public class Main {    //this link always point to first Link    static Node head = null;    //this link always point to last Link    static Node last = null;    static Node current = null;    // is list empty    public static boolean is_empty() {        return head == null;    }    //display the doubly linked list    public static void print_list() {        Node ptr = head;        while (ptr != null) {            System.out.println("(" + ptr.key + "," + ptr.data + ")");            ptr = ptr.next;        }    }    //insert link at the first location    public static void insert_first(int key, int data) {          //create a link        Node link = new Node(data, key);        if (is_empty()) {            //make it the last link            last = link;        } else {            //update first prev link            head.prev = link;        }        //point it to old first link        link.next = head;         //point first to new first link        head = link;    }    public static void main(String[] args) {        insert_first(1, 10);        insert_first(2, 20);        insert_first(3, 30);        insert_first(4, 1);        insert_first(5, 40);        insert_first(6, 56);        System.out.println("Doubly Linked List: ");        print_list();    }}

Output

Doubly Linked List: (6,56)(5,40)(4,1)(3,30)(2,20)(1,10)
#Python code for doubly linked listclass Node:    def __init__(self, data=None, key=None):        self.data = data        self.key = key        self.next = None        self.prev = None#this link always point to first Linkhead = None#this link always point to last Linklast = Nonecurrent = None#is list emptydef is_empty():    return head == None#display the doubly linked listdef print_list():    ptr = head    while ptr != None:        print(f"({ptr.key},{ptr.data})")        ptr = ptr.next#insert link at the first locationdef insert_first(key, data):    global head, last    #create a link    link = Node(data, key)    if is_empty():        #make it the last link        last = link    else:        #update first prev link        head.prev = link    #point it to old first link    link.next = head    #point first to new first link    head = linkinsert_first(1,10)insert_first(2,20)insert_first(3,30)insert_first(4,1)insert_first(5,40)insert_first(6,56)print("Doubly Linked List: ")print_list()

Output

Doubly Linked List: (6,56) (5,40) (4,1) (3,30) (2,20) (1,10)

Doubly Linked List - Insertion at the End

In this insertion operation, the new input node is added at the end of the doubly linked list; if the list is not empty. The head will be pointed to the new node, if the list is empty.

Algorithm

1. START2. If the list is empty, add the node to the list and point    the head to it.3. If the list is not empty, find the last node of the list.4. Create a link between the last node in the list and the    new node.5. The new node will point to NULL as it is the new last node.6. END

Example

Following are the implementations of this operation in various programming languages −

#include <stdio.h>#include <string.h>#include <stdlib.h>#include <stdbool.h>struct node {   int data;   int key;   struct node *next;   struct node *prev;};//this link always point to first Linkstruct node *head = NULL;//this link always point to last Linkstruct node *last = NULL;struct node *current = NULL;//is list emptybool isEmpty(){   return head == NULL;}//display the doubly linked listvoid printList(){   struct node *ptr = head;   while(ptr != NULL) {      printf("(%d,%d) ",ptr->key,ptr->data);      ptr = ptr->next;   }}//insert link at the first locationvoid insertFirst(int key, int data){   //create a link   struct node *link = (struct node*) malloc(sizeof(struct node));   link->key = key;   link->data = data;   if(isEmpty()) {      //make it the last link      last = link;   } else {      //update first prev link      head->prev = link;   }   //point it to old first link   link->next = head;   //point first to new first link   head = link;}//insert link at the last locationvoid insertLast(int key, int data){      //create a link   struct node *link = (struct node*) malloc(sizeof(struct node));   link->key = key;   link->data = data;   if(isEmpty()) {      //make it the last link      last = link;   } else {      //make link a new last link      last->next = link;      //mark old last node as prev of new link      link->prev = last;   }   //point last to new last node   last = link;}void main(){   insertFirst(1,10);   insertFirst(2,20);   insertFirst(3,30);   insertFirst(4,1);   insertLast(5,40);   insertLast(6,56);   printf("Doubly Linked List: ");   printList();}

Output

Doubly Linked List: (4,1) (3,30) (2,20) (1,10) (5,40) (6,56)
#include <iostream>#include <cstring>#include <cstdlib>#include <cstdbool>struct node {   int data;   int key;   struct node *next;   struct node *prev;};//this link always point to first Linkstruct node *head = NULL;//this link always point to last Linkstruct node *last = NULL;struct node *current = NULL;//is list emptybool isEmpty(){   return head == NULL;}//display the doubly linked listvoid printList(){   struct node *ptr = head;   while(ptr != NULL) {      printf("(%d,%d) ",ptr->key,ptr->data);      ptr = ptr->next;   }}//insert link at the first locationvoid insertFirst(int key, int data){   //create a link   struct node *link = (struct node*) malloc(sizeof(struct node));   link->key = key;   link->data = data;   if(isEmpty()) {      //make it the last link      last = link;   } else {      //update first prev link      head->prev = link;   }   //point it to old first link   link->next = head;   //point first to new first link   head = link;}//insert link at the last locationvoid insertLast(int key, int data){   //create a link   struct node *link = (struct node*) malloc(sizeof(struct node));   link->key = key;   link->data = data;   if(isEmpty()) {      //make it the last link      last = link;   } else {      //make link a new last link      last->next = link;      //mark old last node as prev of new link      link->prev = last;   }   //point last to new last node   last = link;}int main(){   insertFirst(1,10);   insertFirst(2,20);   insertFirst(3,30);   insertFirst(4,1);   insertLast(5,40);   insertLast(6,56);   printf("Doubly Linked List: ");   printList();   return 0;}

Output

Doubly Linked List: (4,1) (3,30) (2,20) (1,10) (5,40) (6,56)
import java.util.*;class Node {    public int data;    public int key;    public Node next;    public Node prev;    public Node(int data, int key) {        this.data = data;        this.key = key;        this.next = null;        this.prev = null;    }}public class Main {    static Node head = null;    static Node last = null;    static Node current = null;    public static boolean isEmpty() {        return head == null;    }     public static void printList() {        Node ptr = head;        while (ptr != null) {            System.out.print("(" + ptr.key + "," + ptr.data + ") ");            ptr = ptr.next;        }    }    public static void insertFirst(int key, int data) {        Node link = new Node(data, key);        if (isEmpty()) {            last = link;        } else {            head.prev = link;        }        link.next = head;        head = link;    }    public static void insertLast(int key, int data) {        Node link = new Node(data, key);        if (isEmpty()) {            last = link;        } else {            last.next = link;            link.prev = last;        }        last = link;    }        public static void main(String[] args) {        insertFirst(1,10);        insertFirst(2,20);        insertFirst(3,30);        insertFirst(4,1);        insertLast(5,40);        insertLast(6,56);        System.out.print("Doubly Linked List: ");        printList();    }}

Output

Doubly Linked List: (4,1) (3,30) (2,20) (1,10) (5,40) (6,56)
class Node:    def __init__(self, data=None, key=None):        self.data = data        self.key = key        self.next = None        self.prev = Nonehead = Nonelast = Nonecurrent = Nonedef isEmpty():    return head == Nonedef printList():    ptr = head    while ptr != None:        print(f"({ptr.key},{ptr.data})", end=" ")        ptr = ptr.nextdef insertFirst(key, data):    global head, last    link = Node(data, key)    if isEmpty():        last = link    else:        head.prev = link    link.next = head    head = linkdef insertLast(key, data):    global head, last    link = Node(data, key)    if isEmpty():        last = link    else:        last.next = link        link.prev = last    last = linkinsertFirst(1,10)insertFirst(2,20)insertFirst(3,30)insertFirst(4,1)insertLast(5,40)insertLast(6,56)print("Doubly Linked List: ", end="")printList()

Output

Doubly Linked List: (4,1) (3,30) (2,20) (1,10) (5,40) (6,56)

Doubly Linked List - Deletion at the Beginning

This deletion operation deletes the existing first nodes in the doubly linked list. The head is shifted to the next node and the link is removed.

Algorithm

1. START2. Check the status of the doubly linked list3. If the list is empty, deletion is not possible4. If the list is not empty, the head pointer is    shifted to the next node.5. END

Example

Following are the implementations of this operation in various programming languages −

#include <stdio.h>#include <string.h>#include <stdlib.h>#include <stdbool.h>struct node {   int data;   int key;   struct node *next;   struct node *prev;};//this link always point to first Linkstruct node *head = NULL;//this link always point to last Linkstruct node *last = NULL;struct node *current = NULL;//is list emptybool isEmpty(){   return head == NULL;}//display the doubly linked listvoid printList(){   struct node *ptr = head;   while(ptr != NULL) {      printf("(%d,%d) ",ptr->key,ptr->data);      ptr = ptr->next;   }}//insert link at the first locationvoid insertFirst(int key, int data){   //create a link   struct node *link = (struct node*) malloc(sizeof(struct node));   link->key = key;   link->data = data;   if(isEmpty()) {      //make it the last link      last = link;   } else {      //update first prev link      head->prev = link;   }   //point it to old first link   link->next = head;   //point first to new first link   head = link;}//delete first itemstruct node* deleteFirst(){   //save reference to first link   struct node *tempLink = head;   //if only one link   if(head->next == NULL) {      last = NULL;   } else {      head->next->prev = NULL;   }   head = head->next;   //return the deleted link   return tempLink;}void main(){   insertFirst(1,10);   insertFirst(2,20);   insertFirst(3,30);   insertFirst(4,1);   insertFirst(5,40);   insertFirst(6,56);   printf("Doubly Linked List: \n");   printList();   printf("\nList after deleting first record: \n");   deleteFirst();   printList();}

Output

Doubly Linked List: (6,56) (5,40) (4,1) (3,30) (2,20) (1,10) List after deleting first record: (5,40) (4,1) (3,30) (2,20) (1,10)
#include <iostream>#include <cstring>#include <cstdlib>#include <cstdbool>struct node {   int data;   int key;   struct node *next;   struct node *prev;};//this link always point to first Linkstruct node *head = NULL;//this link always point to last Linkstruct node *last = NULL;struct node *current = NULL;//is list emptybool isEmpty(){   return head == NULL;}//display the doubly linked listvoid printList(){   struct node *ptr = head;   while(ptr != NULL) {      printf("(%d,%d) ",ptr->key,ptr->data);      ptr = ptr->next;   }}//insert link at the first locationvoid insertFirst(int key, int data){   //create a link   struct node *link = (struct node*) malloc(sizeof(struct node));   link->key = key;   link->data = data;   if(isEmpty()) {      //make it the last link      last = link;   } else {      //update first prev link      head->prev = link;   }   //point it to old first link   link->next = head;   //point first to new first link   head = link;}//delete first itemstruct node* deleteFirst(){   //save reference to first link   struct node *tempLink = head;   //if only one link   if(head->next == NULL) {      last = NULL;   } else {      head->next->prev = NULL;   }   head = head->next;   //return the deleted link   return tempLink;}int main(){   insertFirst(1,10);   insertFirst(2,20);   insertFirst(3,30);   insertFirst(4,1);   insertFirst(5,40);   insertFirst(6,56);   printf("Doubly Linked List: \n");   printList();   printf("\nList after deleting first record: \n");   deleteFirst();   printList();   return 0;}

Output

Doubly Linked List: (6,56) (5,40) (4,1) (3,30) (2,20) (1,10) List after deleting first record: (5,40) (4,1) (3,30) (2,20) (1,10)
//Java code for doubly linked listimport java.util.*;class Node {    public int data;    public int key;    public Node next;    public Node prev;    public Node(int data, int key) {        this.data = data;        this.key = key;        this.next = null;        this.prev = null;    }}public class Main {    //this link always point to first Link    public static Node head = null;    //this link always point to last Link    public static Node last = null;    //this link always point to current Link    public static Node current = null;    //is list empty    public static boolean isEmpty() {        return head == null;    }    //display the doubly linked list    public static void printList() {        Node ptr = head;        while (ptr != null) {            System.out.print("(" + ptr.key + "," + ptr.data + ") ");            ptr = ptr.next;        }    }    //insert link at the first location    public static void insertFirst(int key, int data) {        //create a link        Node link = new Node(data, key);        if (isEmpty()) {            //make it the last link            last = link;        } else {            //update first prev link            head.prev = link;        }        //point it to old first link        link.next = head;        head = link;    }    //delete the first item    public static Node deleteFirst() {        //save reference to first link        Node tempLink = head;        //if only one link        if (head.next == null) {            last = null;        } else {            head.next.prev = null;        }        head = head.next;        //return the deleted link        return tempLink;    }    public static void main(String[] args) {        insertFirst(1, 10);        insertFirst(2, 20);        insertFirst(3, 30);        insertFirst(4, 1);        insertFirst(5, 40);        insertFirst(6, 56);        System.out.print("Doubly Linked List: \n");        printList();        System.out.print("\nList after deleting first record: \n");        deleteFirst();        printList();    }}

Output

Doubly Linked List: (6,56) (5,40) (4,1) (3,30) (2,20) (1,10) List after deleting first record: (5,40) (4,1) (3,30) (2,20) (1,10)
#Python code for doubly linked listclass Node:    def __init__(self, data=None, key=None):        self.data = data        self.key = key        self.next = None        self.prev = None#this link always point to first Linkhead = None#this link always point to last Linklast = Nonecurrent = None#is list emptydef isEmpty():    return head == None#display the doubly linked listdef printList():    ptr = head    while ptr != None:        print(f"({ptr.key},{ptr.data}) ", end="")        ptr = ptr.next#insert link at the first locationdef insertFirst(key, data):    #create a link    global head, last    link = Node(data, key)    if isEmpty():        #make it the last link        last = link    else:        #update first prev link        head.prev = link    #point it to old first link    link.next = head    head = link#delete first itemdef deleteFirst():     #save reference to first link    global head, last    tempLink = head    #if only one link    if head.next == None:        last = None    else:        head.next.prev = None    head = head.next    #return the deleted link    return tempLinkinsertFirst(1,10)insertFirst(2,20)insertFirst(3,30)insertFirst(4,1)insertFirst(5,40)insertFirst(6,56)print("Doubly Linked List:")printList()print("\nList after deleting first record:")deleteFirst()printList()

Output

Doubly Linked List: (6,56) (5,40) (4,1) (3,30) (2,20) (1,10) List after deleting first record: (5,40) (4,1) (3,30) (2,20) (1,10)

Doubly Linked List - Complete Implementation

Following are the complete implementations of Doubly Linked List in various programming languages −

#include <stdio.h>#include <string.h>#include <stdlib.h>#include <stdbool.h>struct node {   int data;   int key;   struct node *next;   struct node *prev;};//this link always point to first Linkstruct node *head = NULL;//this link always point to last Linkstruct node *last = NULL;struct node *current = NULL;//is list emptybool isEmpty(){   return head == NULL;}//display the list in from first to lastvoid displayForward(){   //start from the beginning   struct node *ptr = head;   //navigate till the end of the list   printf("\n[ ");   while(ptr != NULL) {      printf("(%d,%d) ",ptr->key,ptr->data);      ptr = ptr->next;   }   printf(" ]");}//display the list from last to firstvoid displayBackward(){//start from the last   struct node *ptr = last;   //navigate till the start of the list   printf("\n[ ");   while(ptr != NULL) {      //print data      printf("(%d,%d) ",ptr->key,ptr->data);      //move to next item      ptr = ptr ->prev;      printf(" ");   }   printf(" ]");}//insert link at the first locationvoid insertFirst(int key, int data){   //create a link   struct node *link = (struct node*) malloc(sizeof(struct node));   link->key = key;   link->data = data;   if(isEmpty()) {      //make it the last link      last = link;   } else {      //update first prev link      head->prev = link;   }   //point it to old first link   link->next = head;   //point first to new first link   head = link;}//insert link at the last locationvoid insertLast(int key, int data){   //create a link   struct node *link = (struct node*) malloc(sizeof(struct node));   link->key = key;   link->data = data;   if(isEmpty()) {      //make it the last link      last = link;   } else {      //make link a new last link      last->next = link;      //mark old last node as prev of new link      link->prev = last;   }   //point last to new last node   last = link;}//delete first itemstruct node* deleteFirst(){   //save reference to first link   struct node *tempLink = head;   //if only one link   if(head->next == NULL) {      last = NULL;   } else {      head->next->prev = NULL;   }   head = head->next;   //return the deleted link   return tempLink;}//delete link at the last locationstruct node* deleteLast(){   //save reference to last link   struct node *tempLink = last;   //if only one link   if(head->next == NULL) {      head = NULL;   } else {      last->prev->next = NULL;   }   last = last->prev;   //return the deleted link   return tempLink;}//delete a link with given keystruct node* delete(int key){   //start from the first link   struct node* current = head;   struct node* previous = NULL;   //if list is empty   if(head == NULL) {      return NULL;   }   //navigate through list   while(current->key != key) {      //if it is last node      if(current->next == NULL) {         return NULL;      } else {         //store reference to current link         previous = current;         //move to next link         current = current->next;      }   }   //found a match, update the link   if(current == head) {      //change first to point to next link      head = head->next;   } else {      //bypass the current link      current->prev->next = current->next;   }   if(current == last) {      //change last to point to prev link      last = current->prev;   } else {      current->next->prev = current->prev;   }   return current;}bool insertAfter(int key, int newKey, int data){   //start from the first link   struct node *current = head;   //if list is empty   if(head == NULL) {      return false;   }   //navigate through list   while(current->key != key) {      //if it is last node      if(current->next == NULL) {         return false;      } else {         //move to next link         current = current->next;      }   }   //create a link   struct node *newLink = (struct node*) malloc(sizeof(struct node));   newLink->key = key;   newLink->data = data;   if(current == last) {      newLink->next = NULL;      last = newLink;   } else {      newLink->next = current->next;      current->next->prev = newLink;   }   newLink->prev = current;   current->next = newLink;   return true;}int main(){   insertFirst(1,10);   insertFirst(2,20);   insertFirst(3,30);   insertFirst(4,1);   insertFirst(5,40);   insertFirst(6,56);   printf("\nList (First to Last): ");   displayForward();   printf("\n");   printf("\nList (Last to first): ");   displayBackward();   printf("\nList , after deleting first record: ");   deleteFirst();   displayForward();   printf("\nList , after deleting last record: ");   deleteLast();   displayForward();   printf("\nList , insert after key(4) : ");   insertAfter(4,7, 13);   displayForward();   printf("\nList , after delete key(4) : ");   delete(4);   displayForward();}

Output

List (First to Last): [ (6,56) (5,40) (4,1) (3,30) (2,20) (1,10)  ]List (Last to first): [ (1,10)  (2,20)  (3,30)  (4,1)  (5,40)  (6,56)   ]List , after deleting first record: [ (5,40) (4,1) (3,30) (2,20) (1,10)  ]List , after deleting last record: [ (5,40) (4,1) (3,30) (2,20)  ]List , insert after key(4) : [ (5,40) (4,1) (4,13) (3,30) (2,20)  ]List , after delete key(4) : [ (5,40) (4,13) (3,30) (2,20)  ]
#include <iostream>#include <cstring>#include <cstdlib>#include <cstdbool>using namespace std;struct node {   int data;   int key;   struct node *next;   struct node *prev;};//this link always point to first Linkstruct node *head = NULL;//this link always point to last Linkstruct node *last = NULL;struct node *current = NULL;//is list emptybool isEmpty(){   return head == NULL;}//display the list in from first to lastvoid displayForward(){   //start from the beginning   struct node *ptr = head;   //navigate till the end of the list   cout << "\n[ ";   while(ptr != NULL) {      cout << "(" << ptr->key << "," << ptr->data << ")";      ptr = ptr->next;   }   cout << " ]" << endl;}//display the list from last to firstvoid displayBackward(){   //start from the last   struct node *ptr = last;   //navigate till the start of the list   cout << "\n[ ";   while(ptr != NULL) {      //print data      cout << "(" << ptr->key << "," << ptr->data << ")";      //move to next item      ptr = ptr ->prev;      cout << " ";   }   cout << " ]" << endl;}//insert link at the first locationvoid insertFirst(int key, int data){   //create a link   struct node *link = (struct node*) malloc(sizeof(struct node));   link->key = key;   link->data = data;   if(isEmpty()) {      //make it the last link      last = link;   } else {      //update first prev link      head->prev = link;   }   //point it to old first link   link->next = head;   //point first to new first link   head = link;}//insert link at the last locationvoid insertLast(int key, int data){   //create a link   struct node *link = (struct node*) malloc(sizeof(struct node));   link->key = key;   link->data = data;   if(isEmpty()) {      //make it the last link      last = link;   } else {      //make link a new last link      last->next = link;      //mark old last node as prev of new link      link->prev = last;   }   //point last to new last node   last = link;}//delete first itemstruct node* deleteFirst(){   //save reference to first link   struct node *tempLink = head;   //if only one link   if(head->next == NULL) {      last = NULL;   } else {      head->next->prev = NULL;   }   head = head->next;   //return the deleted link   return tempLink;}//delete link at the last locationstruct node* deleteLast(){   //save reference to last link   struct node *tempLink = last;   //if only one link   if(head->next == NULL) {      head = NULL;   } else {      last->prev->next = NULL;   }   last = last->prev;   //return the deleted link   return tempLink;}//delete a link with given keystruct node* deletenode(int key){   //start from the first link   struct node* current = head;   struct node* previous = NULL;   //if list is empty   if(head == NULL) {      return NULL;   }   //navigate through list   while(current->key != key) {      //if it is last node      if(current->next == NULL) {         return NULL;      } else {         //store reference to current link         previous = current;         //move to next link         current = current->next;      }   }   //found a match, update the link   if(current == head) {      //change first to point to next link      head = head->next;   } else {            //bypass the current link      current->prev->next = current->next;   }   if(current == last) {      //change last to point to prev link      last = current->prev;   } else {      current->next->prev = current->prev;   }   return current;}bool insertAfter(int key, int newKey, int data){   //start from the first link   struct node *current = head;   //if list is empty   if(head == NULL) {      return false;   }   //navigate through list   while(current->key != key) {      //if it is last node      if(current->next == NULL) {         return false;      } else {         //move to next link         current = current->next;      }   }   //create a link   struct node *newLink = (struct node*) malloc(sizeof(struct node));   newLink->key = key;   newLink->data = data;   if(current == last) {      newLink->next = NULL;      last = newLink;   } else {      newLink->next = current->next;      current->next->prev = newLink;   }   newLink->prev = current;   current->next = newLink;   return true;}int main(){   insertFirst(1,10);   insertFirst(2,20);   insertFirst(3,30);   insertFirst(4,1);   insertFirst(5,40);   insertFirst(6,56);   printf("\nList (First to Last): ");   displayForward();   printf("\n");   printf("\nList (Last to first): ");   displayBackward();   printf("\nList , after deleting first record: ");   deleteFirst();   displayForward();   printf("\nList , after deleting last record: ");   deleteLast();   displayForward();   printf("\nList , insert after key(4) : ");   insertAfter(4, 7, 13);   displayForward();   printf("\nList , after delete key(4) : ");   deletenode(4);   displayForward();   return 0;}

Output

List (First to Last):[ (6, 56) (5, 40) (4, 1) (3, 30) (2, 20) (1, 10) ]List (Last to First):[ (1, 10) (2, 20) (3, 30) (4, 1) (5, 40) (6, 56) ]List, after deleting first record:[ (5, 40) (4, 1) (3, 30) (2, 20) (1, 10) ]List, after deleting last record:[ (5, 40) (4, 1) (3, 30) (2, 20) ]List, insert after key(4):[ (5, 40) (4, 1) (7, 13) (3, 30) (2, 20) ]List, after delete key(4):[ (5, 40) (7, 13) (3, 30) (2, 20) ]
class Node {    int data;    int key;    Node next;    Node prev;    public Node(int key, int data) {        this.key = key;        this.data = data;        this.next = null;        this.prev = null;    }}class DoublyLinkedList {    Node head;    Node last;    boolean isEmpty() {        return head == null;    }    void displayForward() {        Node ptr = head;        System.out.print("[ ");        while (ptr != null) {            System.out.print("(" + ptr.key + "," + ptr.data + ") ");            ptr = ptr.next;        }        System.out.println("]");    }    void displayBackward() {        Node ptr = last;        System.out.print("[ ");        while (ptr != null) {            System.out.print("(" + ptr.key + "," + ptr.data + ") ");            ptr = ptr.prev;        }        System.out.println("]");    }    void insertFirst(int key, int data) {        Node link = new Node(key, data);        if (isEmpty()) {            last = link;        } else {            head.prev = link;        }        link.next = head;        head = link;    }    void insertLast(int key, int data) {        Node link = new Node(key, data);        if (isEmpty()) {            last = link;        } else {            last.next = link;            link.prev = last;        }        last = link;    }    Node deleteFirst() {        if (isEmpty()) {            return null;        }        Node tempLink = head;        if (head.next == null) {            last = null;        } else {            head.next.prev = null;        }        head = head.next;        return tempLink;    }    Node deleteLast() {        if (isEmpty()) {            return null;        }        Node tempLink = last;        if (head.next == null) {            head = null;        } else {            last.prev.next = null;        }        last = last.prev;        return tempLink;    }    Node delete(int key) {        Node current = head;        Node previous = null;        if (head == null) {            return null;        }        while (current.key != key) {            if (current.next == null) {                return null;            } else {                previous = current;                current = current.next;            }        }        if (current == head) {            head = head.next;        } else {            current.prev.next = current.next;        }        if (current == last) {            last = current.prev;        } else {            current.next.prev = current.prev;        }        return current;    }    boolean insertAfter(int key, int newKey, int data) {        Node current = head;        if (head == null) {            return false;        }        while (current.key != key) {            if (current.next == null) {                return false;            } else {                current = current.next;            }        }        Node newLink = new Node(newKey, data);        if (current == last) {            newLink.next = null;            last = newLink;        } else {            newLink.next = current.next;            current.next.prev = newLink;        }        newLink.prev = current;        current.next = newLink;        return true;    }}public class Main {    public static void main(String[] args) {        DoublyLinkedList dll = new DoublyLinkedList();        dll.insertFirst(1, 10);        dll.insertFirst(2, 20);        dll.insertFirst(3, 30);        dll.insertFirst(4, 1);        dll.insertFirst(5, 40);        dll.insertFirst(6, 56);        System.out.println("List (First to Last):");        dll.displayForward();        System.out.println();        System.out.println("List (Last to First):");        dll.displayBackward();        System.out.println("List, after deleting first record:");        dll.deleteFirst();        dll.displayForward();        System.out.println("List, after deleting last record:");        dll.deleteLast();        dll.displayForward();        System.out.println("List, insert after key(4):");        dll.insertAfter(4, 7, 13);        dll.displayForward();        System.out.println("List, after delete key(4):");        dll.delete(4);        dll.displayForward();    }}

Output

List (First to Last):[ (6, 56) (5, 40) (4, 1) (3, 30) (2, 20) (1, 10) ]List (Last to First):[ (1, 10) (2, 20) (3, 30) (4, 1) (5, 40) (6, 56) ]List, after deleting first record:[ (5, 40) (4, 1) (3, 30) (2, 20) (1, 10) ]List, after deleting last record:[ (5, 40) (4, 1) (3, 30) (2, 20) ]List, insert after key(4):[ (5, 40) (4, 1) (7, 13) (3, 30) (2, 20) ]List, after delete key(4):[ (5, 40) (7, 13) (3, 30) (2, 20) ]
class Node:    def __init__(self, key, data):        self.key = key        self.data = data        self.next = None        self.prev = Noneclass DoublyLinkedList:    def __init__(self):        self.head = None        self.last = None    def is_empty(self):        return self.head is None    def display_forward(self):        ptr = self.head        print("[", end=" ")        while ptr:            print("({}, {})".format(ptr.key, ptr.data), end=" ")            ptr = ptr.next        print("]")    def display_backward(self):        ptr = self.last        print("[", end=" ")        while ptr:            print("({}, {})".format(ptr.key, ptr.data), end=" ")            ptr = ptr.prev        print("]")    def insert_first(self, key, data):        link = Node(key, data)        if self.is_empty():            self.last = link        else:            self.head.prev = link        link.next = self.head        self.head = link    def insert_last(self, key, data):        link = Node(key, data)        if self.is_empty():            self.last = link        else:            self.last.next = link            link.prev = self.last        self.last = link    def delete_first(self):        if self.is_empty():            return None        temp_link = self.head        if self.head.next is None:            self.last = None        else:            self.head.next.prev = None        self.head = self.head.next        return temp_link    def delete_last(self):        if self.is_empty():            return None        temp_link = self.last        if self.head.next is None:            self.head = None        else:            self.last.prev.next = None        self.last = self.last.prev        return temp_link    def delete(self, key):        current = self.head        while current and current.key != key:            current = current.next        if current is None:            return None        if current == self.head:            self.head = self.head.next        else:            current.prev.next = current.next        if current == self.last:            self.last = current.prev        else:            current.next.prev = current.prev        return current    def insert_after(self, key, new_key, data):        current = self.head        while current and current.key != key:            current = current.next        if current is None:            return False        new_link = Node(new_key, data)        if current == self.last:            new_link.next = None            self.last = new_link        else:            new_link.next = current.next            current.next.prev = new_link        new_link.prev = current        current.next = new_link        return True# Example usagedll = DoublyLinkedList()dll.insert_first(1, 10)dll.insert_first(2, 20)dll.insert_first(3, 30)dll.insert_first(4, 1)dll.insert_first(5, 40)dll.insert_first(6, 56)print("List (First to Last):")dll.display_forward()print()print("List (Last to First):")dll.display_backward()print("List, after deleting first record:")dll.delete_first()dll.display_forward()print("List, after deleting last record:")dll.delete_last()dll.display_forward()print("List, insert after key(4):")dll.insert_after(4, 7, 13)dll.display_forward()print("List, after delete key(4):")dll.delete(4)dll.display_forward()

Output

List (First to Last):[ (6, 56) (5, 40) (4, 1) (3, 30) (2, 20) (1, 10) ]List (Last to First):[ (1, 10) (2, 20) (3, 30) (4, 1) (5, 40) (6, 56) ]List, after deleting first record:[ (5, 40) (4, 1) (3, 30) (2, 20) (1, 10) ]List, after deleting last record:[ (5, 40) (4, 1) (3, 30) (2, 20) ]List, insert after key(4):[ (5, 40) (4, 1) (7, 13) (3, 30) (2, 20) ]List, after delete key(4):[ (5, 40) (7, 13) (3, 30) (2, 20) ]
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