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To compute basic mathematical calculation like addition, subtraction, multiplication and division on a large digit number in c++.

int i = 0;char ch = i;cout<<ch;

Output : 48

So, whenever we add 48 into a number this is to convert an integer into a string and vice versa.

1. string ZeroPadNumber(string ret, int num){
2. int str_length = ret.length();
3. for (int i = 0; i < num - str_length; i++)

4.  ret = "0" + ret;

5. return ret;
6. }

Key points

1. In c++ you cannot store 10-20 digit number, so if we want to add these numbers then this concept is used.
2. Time Complexity - O(n) where n indicate length of number i.e., number of digits.
3. No Exception, run for all cases.

Key points

1. In c++ you cannot store 10-20 digit number, so if we want to implement subtraction on these numbers then this concept is used.
2. Time Complexity - O(n) where n indicate length of number i.e., number of digits.
3. No Exception, run for all cases.

Key points

1. In c++ you cannot store 10-20 digit number, so if we want to add these numbers then this concept is used.
2. Time Complexity - O(n*n) where n indicate length of number i.e., number of digits.
3. No Exception, run for all cases.

Key points

1. In c++ you cannot store 10-20 digit number, so if we want to add these numbers then this concept is used.
2. Time Complexity - O(2^n) where n indicate length of number i.e., number of digits.
3. 1 Exception, this code is recursive in nature, if stack is overloaded then it will terminate abruptly.