In this article, we will explore various methods to remove multiple elements from a list in Python. The simplest way to do this is by using aloop. A simplefor loop can also be used to remove multiple elements from a list.

a=[10,20,30,40,50,60,70]# Elements to removeremove=[20,40,60]# Remove elements using a simple for loopres=[]forvalina:ifvalnotinremove:res.append(val)print(res)

[10, 30, 50, 70]

Explanation

• Iterate through each element in the original listaand adding it to result if it's not inremovelist.

Let's explore other different ways to remove multiple elements from list:

Using List Comprehension

List comprehensionis one of the most concise and efficient ways to remove multiple elements from a list.

a=[10,20,30,40,50,60,70]# Elements to removeremove=[20,40,60]# Remove elements using list comprehensiona=[xforxinaifxnotinremove]print(a)

[10, 30, 50, 70]

Explanation:

• Iterate over each element inaand checking if it is not inremove list.
• Elements not inremove list are included in the new list.

Using remove() in a Loop

remove() method removes the first occurrence of a specified element from the list. To remove multiple elements, we can use a loop to repeatedly callremove().

a=[10,20,30,40,50,60,70]# Elements to removeremove=[20,40,60]# Remove elements using remove() in a loopforvalinremove:whilevalina:a.remove(val)print(a)

[10, 30, 50, 70]

Explanation:

• We iterate over each element inremove list.
• The while loop make sure that all occurrences of each element are removed from the list.

Using filter() Function

filter()function can be used to remove elements from a list by providing a filtering condition and typically through alambda function.

a=[10,20,30,40,50,60,70]# Elements to removeremove={20,40,60}# Remove elements using filtera=list(filter(lambdax:xnotinremove,a))print(a)

[10, 30, 50, 70]

Explanation:

• filter() function iterates over the listaand applying the lambda function.
• If an element is not inremove list then include it in the filtered list.

Similar Reads