We are given astring and our task is to count the number of vowels present in it. Vowels in English include 'a', 'e', 'i', 'o', and 'u' (both uppercase and lowercase). Using sets, we can efficiently check for vowel presence due to their fast membership lookup.For example, if the input string is "Beautiful Day" then the output should be 6 as the vowels present are 'e', 'a', 'u', 'i', 'a', and 'y'.

Using a Set for Fast Lookup

Aset allows quick membership testing, making it an efficient way to count vowels. We iterate through the string and check if each character is in the set of vowels.

s="Python Programming"vowels={'a','e','i','o','u','A','E','I','O','U'}c=sum(1forchinsifchinvowels)print("Number of vowels:",c)

Number of vowels: 4

Explanation:

• We define a set of vowels.
• We iterate over the string and count characters that are present in the vowel set.
• sum(1 for char in s if char in vowels) ensures we get the total vowel count.

Using a Set and Intersection

Instead of iterating through the string, we use set intersection to find common elements between the string and the vowel set.

s="Set operations in Python"vowels={'a','e','i','o','u','A','E','I','O','U'}c=sum(s.count(v)forvinset(s)&vowels)print("Number of vowels:",c)

Number of vowels: 8

Explanation:

• set(s) & vowels extracts unique vowels from the string.
• sum(s.count(v) for v in set(s) & vowels) counts occurrences of each vowel in the string.

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