importres='My Profile: https://www.geeksforgeeks.org/404.html/ in the portal of https://www.geeksforgeeks.org/'pattern=r'https?://\S+|www\.\S+'print("URLs:",re.findall(pattern,s))

URLs: ['https://www.geeksforgeeks.org/404.html/', 'https://www.geeksforgeeks.org/']

Explanation:

• r'https?://\S+|www\.\S+' is a regex pattern to match URLs starting with http://, https://, or www.
• findall() extracts all matches in a list.

Using the urlparse()

urlparse() function from Python's urllib.parse module helps break down a URL into its key parts, such as the scheme (http, https), domain name, path, query parameters, and fragments. This function is useful for validating and extracting URLs from text by checking if a word follows a proper URL structure.

fromurllib.parseimporturlparses='My Profile: https://www.geeksforgeeks.org/404.html/ in the portal of https://www.geeksforgeeks.org/'# Split the string into wordssplit_s=s.split()# Empty list to collect URLsurls=[]forwordinsplit_s:parsed=urlparse(word)ifparsed.schemeandparsed.netloc:urls.append(word)print("URLs:",urls)

URLs: ['https://www.geeksforgeeks.org/404.html/', 'https://www.geeksforgeeks.org/']

Explanation:

• s.split() function splits the string to words.
• then urlparse(word) function checks each word to see if it has a valid scheme (http/https) and domain.
• URLs are added to url list using append() function.

Using urlextract()

urlextract is a third party library so to use it we need to first install it by giving the command "pip install urlextract" in out terminal, it offers a pre-built solution to find URLs in text. Its URLExtract class helps us to quickly identify URLs without needing custom patterns, making it a convenient choice for difficult extraction of URLs.

fromurlextractimportURLExtracts='My Profile: https://www.geeksforgeeks.org/user/Prajjwal%20/contributions/ in the portal of https://www.geeksforgeeks.org/'extractor=URLExtract()urls=extractor.find_urls(s)print("URLs:",urls)

Urls:  ['https://www.geeksforgeeks.org/user/Prajjwal%20/contributions/', 'https://www.geeksforgeeks.org/']

Explanation:

• import URLExtract from the urlextract library.
• URLExtract() creates an extractor object to scan the string.
• find_urls() detects all URLs in s and returns them as a list, no manual splitting or validation is needed.

Using startswith()

One simple approach is to split the string and check if each word starts with "http://" or "https://" using .startswith() built-in method, we can use .split() function to split the string and then check each word, if it starts with "http://" or "https://". If it does, we add it to our list of extracted URLs.

s='My Profile: https://www.geeksforgeeks.org/404.html/ in the portal of https://www.geeksforgeeks.org/'x=s.split()# Empty list to extract the URLres=[]foriinx:ifi.startswith("https:")ori.startswith("http:"):res.append(i)print("Urls: ",res)

Urls:  ['https://www.geeksforgeeks.org/404.html/', 'https://www.geeksforgeeks.org/']

Explanation:

• string.split() method splits the string into words.
• then we checks if each word starts with http:// or https:// using the "if" statement.
• if it does, then we add it to the list of URLs using .append() method.

Using find() method

find() is a built-in method in Python that is used to find a specific element in a collection, so we can use it to identify and extract a URL from a string. Here's how:

s='My Profile: https://www.geeksforgeeks.org/404.html/ in the portal of https://www.geeksforgeeks.org/'split_s=s.split()res=[]foriinsplit_s:ifi.find("https:")==0ori.find("http:")==0:res.append(i)print("Urls: ",res)

Urls:  ['https://www.geeksforgeeks.org/404.html/', 'https://www.geeksforgeeks.org/']

Explanation:

• s.split() funtion splits the string to words.
• identify url using i.find() function.
• add the URLs to the list 'res' using .append().

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