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Chemistry Steps

Chemistry Steps

Meso Compounds

In my experience of teaching, I have noticed that conveying the message aboutmeso compounds is a lot easier whenFischer projections are used. So, we will talk about it by drawing the Fischer projections of three isomers of 2,3-dichlrobutane:

 

 

Here is how you recognize themeso isomer: it is the one thatcontains a plane of symmetry.

Out of the three, it is only the last one that has a plane of symmetry. It cuts the molecule in two,mirror-reflected halves:

 

 

One important clarification before we finalize the statement aboutmeso compounds.

Ameso compoundmust contain chirality centers. This means that not any molecule that has a plane of symmetry is ameso compound. For example:

 

 

Let’s get back to 2,3-dichlrobutane for additional details that are very important.

Notice that the first two isomers are nonsuperimposable mirror images. Therefore, they areenantiomers.

And to clarify why they nonsuperimposable, rotate the right isomer 180o to have it look like the left one and you will notice that the positions of Br groups are different, i.e. it does not represent the same molecule:

 

 

You can also check this by assigning theR andS configuration. It is inverted from 2R, 3S to 2S, 3R which confirms that they are enantiomers.

 

 

Here is the important part about themeso isomer! Unlike the first two, itdoes NOT have an enantiomer!

Why?

To answer this question, go ahead and draw its mirror image since enantiomers are mirror images:

 

 

At first, these may look like a pair of enantiomers. However, if you flip any of them, you can see that it represents the same molecule as its mirror image:

 

 

In other words, it is superimposable to its mirror image which means the two structures represent the same molecule. Therefore, ameso compound cannot have an enantiomer.

This is consistent with what we discussed in the beginning of stereochemistry-any object has a mirror image, but only chiral objects are nonsuperimposable to their mirror images. And these mirror images are called enantiomers.

 

 

Features of Meso Compounds

Let’s emphasize a few important observations:

1) Meso compounds are achiral

Yes,meso compounds do have chiral centers but they are all inverted. EveryR is inverted toS and everyS is inverted intoR:

 

 

It is similar to having a racemic mixture where equal amounts ofR andS configurations of the same carbon are present. They cancel out the rotation of plane-polarized light making the mixtureoptically inactive.

2) Meso compounds cannot have enantiomers

  • Like any other molecule that is not chiral, meso compounds cannot have enantiomers since their mirror image represents the same compound:

 

 

Wedge and dash in Meso compounds

Sometimes, it is not obvious to spot themeso isomer when it is drawn in bond-line representation. The reason is that it is tempting to assume that themeso isomer is the one with all wedge or all dashed lines since it looks like there is a plane of symmetry.

For example, which of the isomers is a meso compound?

 

 

It looks like it is possible to place a plane of symmetry between the two bromines of the first isomer:

 

 

However, notice that even though the Br groups are on the same side (both wedge), they are still pointing in opposite directions – up and down. Therefore, they are not reflected through a plane of symmetry:

 

 

The second isomer, on the other hand, does have a plane of symmetry! Yes, the Br groups are on opposite sides (wedge and dash), however, if we rotate about the central sigma bond, they both appear right next to each other:

 

 

To summarize, if you are asked to draw themeso isomer of a plain bond-line structure, you have two options. One is two draw the carbon chain in a regular zig-zag form and have the identical groups on the chiral carbon on opposite sides (wedge-dash):

 

 

And the other is to draw the carbon chain with these two groups pointing to the same direction having either both wedge or both dash lines (which is the same molecule since it is a meso compound).

Free

Stereochemistry Practice Problems Quiz

Practice

1.

All the molecules shown below areachiralbecause of the presence of a plane of symmetry. Confirm that they are achiral by drawing the corresponding plane of symmetry and determine if they aremeso compounds. Remember that the plane of symmetry can slice atoms in half.

Answer

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2.

Determine whether each of the molecules is chiral or achiral. Explain your answer by showing the appropriate symmetry element:

a)
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b)
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c)
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d)
Answer

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e)
Answer

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f)
Answer

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g)
Answer

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h)
Answer

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i)
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3.

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9 thoughts on “Meso Compounds”

  1. I needed to review this concept and the trick about the wedge and dash notation for the alkyne quiz. Thanks for linking them.

    Reply
  2. You are welcome, Autumn. It’s good to hear this feedback.

    Reply
  3. So much information. Thank you, sir!

    Reply
  4. Hi, why is the c) from exercise 2 chiral?

    Reply
    • You need to pay attention to the configuration of the methyl groups and determine whether it allows to have a plane of symmetry. I wrote more about it in the answer to the problem.

      Reply
  5. Hello, the logic applied for meso compound where both the Cl are on the same side, can be applied for the one with Cl on different sides. From that, we get the same compound like meso one, but that would be wrong. Please clarify.

    Reply
  6. why 1. a) is meso? I thought it doesn’t have chiral centers. Thank you in advance.

    Reply

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