![]() | This![]() It is of interest to the followingWikiProjects: | |||||||||||||||||||||||||||
|
There isn’t 148,510,800 square minutes in a sphere, if it isn’t a misquotation that is perhaps something that’s only valid for the Earth’s sky. Earth is not a perfect sphere.2πr = 60·360 = 21,600 arcminutes, r = 21,600/2π, A = 4πr^2 = 4π·(466,560,000/4π^2) = 466,560,000/π ≈ 148,510,660.498 square arcminutes. I'm fixing it, but just if anyone disagrees for some reason (since there's a source and everything for the false info).User:DeclinedShadow02:50, 17 July 2009 (UTC)[reply]
Rewrote thisagain since someone changed it back, and added some calculations. Anyone of you can just look at theSquare degree page, there's the same formula being used.User:DeclinedShadow03:52, 2 August 2009 (UTC)[reply]
What the heck is this feature for??Well, I'll be darned.Shouldn't this be "Minute of Arc"?
I'll see what I can do on anglar measurements.-- April 09:04 Aug 7, 2002 (PDT)
It seems sensible that one ofMinute of arc andArcsecond should be renamed to fit in with the other. Both belong to Category: Units of angleIcairns 21:39, 25 Jun 2004 (UTC)
First we have to decide which is the "most correct". Arcsecond (or arc second) is far less awkward, anyway. --Elektron 10:28, 2004 Jul 4 (UTC)
I see above that there has been some discussion in the past about merging the articles on arcminute andarcsecond. This may be a good idea to pick up. Most info on one page could be (or already is) on the other.MHD11:04, 3 February 2006 (UTC)[reply]
I agree: merging all three may be a sensible thing to do, but maybe also a little more time consuming to do, as opposed to just merging thearcminute andarcsecond articles and leaving thedegree article as it is.
As to the millimetre/centimetre/metre issue, I have no idea whymillimetre links to1 E-3 m, and not tometre, which it should, in my opinion.
MHD09:56, 8 February 2006 (UTC)[reply]
Arcminutes and arcseconds are indeed used when measuring thedeclination of an object on the sky. When measuring theright ascension (RA), these units arenot used (as is correctly stated byUser:Zandperl in the article). Instead, RA is measured in:
This a fair thing to put in an article on arcminutes (orarcseconds for that matter).
However, there are numerous other coordinate systems that use thedegree (and its subdivisions arcminute and arcsecond), such asGalactic coordinates, though it is also common to express galactic longitude and latitude in ordinary decimal fractions of degrees, the coordinates of an object may be expressed as "l = 48.85 and b = -1.96", meaning that it has a galactic longitude of 48 and 85/100 of a degree and a galactic latitude of minus 1 minus 96/100 of a degree.
Oops, forgot to sign this message yesterday. It was written by me:MHD11:35, 4 February 2006 (UTC)[reply]
I agree to the fact that information in the arcminute page should also be on arcsecond, that is exactly the reason why I proposed to merge these two articles (see topic above this one). 17:23, 4 February 2006 (UTC)
Visual acuity should be under a different section as best as I can tell. Unfortuntately, I only know about visual acuity what I've read on Wikipedia. Should the section be called "Ophthalmology"? Thanks!Don20:13, 19 February 2006 (UTC)[reply]
I am only familiar with the term 'Right Ascension' when it is used in astronomy. I am a bit confused as to what it really means in cartography: does it refer to a different concept than geographical longitude, or is is just a different name for the same thing? I understand that the distance over the surface of the earth corresponding to 1 degree of right ascension would vary depending on the geographical latitude (how far from the equator you are). Talking about such variations makes much less sense in astronomy, which is why I removed the reference to astronomy in the Cartography section.
In addition: the page aboutRight ascension does not handle the subject of its use in cartography at all, so I don't think it is wise to have a link pointing from the cartography section ofMinute of arc directly toRight ascension.
Can somebody help me out on the meaning of 'right ascension' in cartography? And maybe (help me) come up with a clearer description in this section and/or write a section about the use of right ascension in theRight ascension article?
Thanks,MHD12:18, 18 April 2006 (UTC)[reply]
Although I am not a firearm afficionado, i think the correct formula is 2*tan(MOA ∙π/21600)*distance, since you are trying to find the opposite side of an angle, given the adjacent side. It may be that for accurate estimates, the tan is not needed since the results are very close, for example in the example given, the answer computed using tan is approximately 1.04719756 which differs by only 7∙10^-9 inches from the previous value.
I also think it's incorrect. Tangent is a right triangle function, in the main article formula, tan(MOA ∕ 60)*distance, tangent is being applied to an isosceles triangle. Because the two equal angles at the base approach 90 degrees (in these cases) the error is not so great. However, the correct approach is to split the isosceles triangle into two identical right triangles, as the person who posted the above paragraph did, calculate the value for the halves then multiply it by two. So the formula for would be 2*tan(MOA/120)*distance. (JohnMc 7-31-08)—Precedingunsigned comment added byJohnMc (talk •contribs)00:10, 1 August 2008 (UTC)[reply]
The calculation byDexadine, now cited in the article, considers the length along an arc all points of which are 100 yards from the observer. JohnMc, above, treats the distance between the endpoints of that arc. In an edit I reverted, CoastalShooter considers the length of a line perpendicular to the line of sight with one end 100 yards from the observer. The results differ by a few ten-thousands of an inch, not enough to be worth arguing about. It's enough to say that the length is approximately 1.047 inches, which everyone agrees on.Peter Brown (talk)16:28, 23 December 2019 (UTC)[reply]
The is no "minute of arc" it is MINUTE OF ANGLE.—The precedingunsigned comment was added by62.248.159.240 (talk)17:05, 28 April 2007 (UTC).[reply]
How about adding a simple paragraph that discusses the "minute of arc" vs "minute of angle". While it looks to me like astronomer types use arc, the firearms people most definitely do not. So a firearms person coming to this page may be confused, even if arc is technically the correct term (which I am not sure of). So maybe a "common confusion" paragraph/section that explains common usages, etc.Arthurrh19:57, 9 July 2007 (UTC)[reply]
There definitely is a "minute of arc". It is used by vision scientists (too).—Precedingunsigned comment added by188.142.56.253 (talk)20:10, 12 February 2011 (UTC)[reply]
one "arc" is a 1/6 of a revolution. so 1/60 arc, is a degree (6*60 = 360). then 1/60*1/60 = 1/3600, etc (just like time fractioning). its so weird that some people still insisting to use this kind of decimalizationTabascofernandez (talk)21:51, 14 July 2017 (UTC)[reply]
"one "arc" is a 1/6 of a revolution." Huh? An arc is simply a piece of a circle and can be any length or subtend any angle.Cross Reference (talk)21:29, 1 January 2020 (UTC)[reply]
Re: the previous post --"Minute of angle" may be the correct terminology in firearms work -- from the article, I gathered that --but it is never used in astronomy. In astronomy, the correct terminology is "minute of arc". I don'thave a reference for this, but I have long experience as a professional optical astronomer. So themoral is, don't be too hasty in categorically saying a term is not used, the world is very big!
Regarding the merging of arcsecond into arcminute, I think it could be improved. Also, there's no noting that the abbreviation "mas" means "milliarcsecond" in some contexts; if you look at e.g. the article on "Teegarden's star" the quoted values for parallax and proper motion make use of the "mas" notation, which directs you to "minute of arc", where there is no longer an explanation of the "mas".67.142.130.45 = Jthorstensen ;04:39, 29 April 2007 (UTC)[reply]
(A little later) -- I went ahead and touched up the arcsecond discussion a bit, in particular adding an explicit reference to the milliarcsecond; I know it's a standard SI prefix, but it seems to confuse people so it's worth a sentence or two. I can't seem to get my four-tilde signature to work from home, but I am JThorstensen.
after milli/ micro sec[ond] in time, the milli/ micro deg[ree] in angle is the best path to proceed, while lacking in temperature (98 Fa[hren], 53 Ce[lsie], 520 Ke[lvin] ).Tabascofernandez (talk)22:16, 14 July 2017 (UTC)[reply]
minute of arc the band can be found at www.mypace.com/moa
This appears at the head of this article as of 11:42PM EST. That belongs on a disambiguation page! Whomever posted that needs to take it down and do it right. Thanks.—Precedingunsigned comment added by69.140.192.220 (talk)03:44, 9 April 2009 (UTC)[reply]
In terms of racing, I've seen the elapsed time displayed as, say 33'21" (33 minutes, 21 seconds). However, this article is not very clear on what happens in races that last over an hour. Does the minutes continue to count up (93'=60'+33'), does it use the degree symbol °, or is it displayed in some other format?
I request a new section on the use of the arcminute in racing.
Christopher, Salem, OR (talk)07:50, 1 July 2010 (UTC)[reply]
I just checked all of the unit conversions using Google as a calculator both with Google's value of pi and with MathWorld's value of pi. The only value I was unable to verify to all digits was minute of arc in radians (which has one more significant figure than Google supports). Given that these conversions involve only integers and pi, I am shocked by this label on this article: "The factual accuracy of this article may be compromised by unit conversions quoted to a greater precision than can be justified from the original data. Please help improve this article by truncating values to a suitable number of significant figures." I haven't edited wikipedia in a while, so I am reluctant to remove this label.rs2 (talk)20:35, 29 July 2010 (UTC)[reply]
I think we should mergeMinute of Angle into this article. Note thatMinute of angle with lowercase "a" already redirects here.AliveFreeHappy (talk)20:55, 6 October 2010 (UTC)[reply]
Currently the article contains the statement: "However, they [arcsecond and arcminute] are not themselves SI units because they are dimensionless.". This looks false to me -- is there a reference for this? Regardless of whether one considers units of angle to be dimensionless, that does not preclude them from being SI units. They are presumably not SI units for some other reason, perhaps because instead SI chooses radian as the unit for angle.Gwideman (talk)01:14, 8 June 2011 (UTC)[reply]
The article says "This article is about geometry. For firearms terminology, see Minute of Angle." When you click on "Minute of Angle", it brings you right back to this page, because "Minute of Angle" is set to redirect here. Something is obviously wrong...71.109.153.28 (talk)04:17, 6 February 2012 (UTC)[reply]
I see prad, etc., used at least in the units-of-angle table to express various angle units in terms of other ones.
But nowhere in Wikipedia could I find "prad" per se. Googling, I learned that prad stands for picoradian, one-trillionth (10-12) of a radian. But even the term "picoradian" occurs only once in Wikipedia, and does not seem to be defined there.
So I would recommend that any unit used here that can't be linked to its definition elsewhere in Wikipedia be defined here.Daqu (talk)02:09, 25 April 2012 (UTC)[reply]
The table is titled "Thesexagesimal system ofangular measurement", but this is far from a purely sexagesimal system. If it were sexagesimal, each second would be divided into 60thirds ortierces, not 1000 milliseconds. I think it should just say "common units ofangular measurement", or something. —Steve Summit (talk)18:08, 17 December 2015 (UTC)[reply]
e.g.https://he.wikipedia.org/wiki/%D7%93%D7%A7%D7%AA_%D7%A7%D7%A9%D7%AA --MeUser42 (talk)11:13, 18 January 2016 (UTC)[reply]
we have sec[ond] as the 1/3600 of an hour. then we use milli-sec, micro-sec etc, good. what if we had deg[ree] as 1/360 of a revolution? then we have milli-deg, micro-deg, etc. {specifying sec as time (not any other) and deg as angle (only, e.g. 34 Ce[lsie] }
Tabascofernandez (talk)21:41, 14 July 2017 (UTC)[reply]
The sidebar illustration says a soccer ball (22 cm diameter) subtends an angle of 1 arcminute at a distance of approximately 775 meters.
When I calculate this I get 756 metres. Wouldn't a better "approximation" be 750 metres (or 3/4 of a kilometre)?— Precedingunsigned comment added by86.151.138.137 (talk) 14:06, 2 July 2018 (UTC) Agreed. I saw the dubious notation and did the calculation as well and got 756.30 as well.— Precedingunsigned comment added byPmsteven (talk •contribs)19:21, 3 August 2020 (UTC)[reply]
Were it not for the growing presence offlat earth conspiracy theorists, I would not be sensitive to the statement, which appears in a list of examples, that
Of course this is misleading because a dime at the top of the Eiffel Tower could not be seen from New York even on a perfectly clear day with infinite visibility because of the curvature of the earth. Putting the dime on top of the tower doesn't help.
It's also ambiguous because it doesn't specify whether the distance between the cities is along the planet's surface as the crow flies, or through the earth as the neutrino flies (which is about 210 km shorter than the air travel distance of 5853 km).
The last problem with this example is that it is not numerically accurate. A milliarcsecond is bigger than the example supposes. TheUnited States Mint says the diameter of adime is 17.91 mm[1]. At the distance between Paris and New York, a dime would subtend an angle of only about 0.63 or 0.65 milliarcseconds, depending on whether the dime was viewed byRay Milland or by light somehow bending around the Earth's surface.
A better example might be
Given that theEiffel_Tower is at 48°51′29.6″N 2°17′40.2″E and theWashington_Monument is at 38°53′22″N 77°2′7″W, thegreat-circle distance between them is 6162 km computed using thehaversine formula for shortest surface distance[2]. As the U.S. Mint describes a half dollar as 30.61 mm in diameter, the angle would bearctangent(30.61 mm / 6162 km) ≈ 1.025 milliarcseconds.
By the way, the article actually does not seem to say anywhere how the angles are computed, but a better formula would be 2×arctangent(d/(2D)), whered is the diameter of the object viewed andD is the distance from the observer to the center of the object, rather than simply arctangent(d/D). For these numerical examples, the discrepancy is negligible, but it would become signficant whend andD become more similar in size.
--Scwarebang (talk)21:45, 26 November 2021 (UTC)[reply]
References
The following Wikimedia Commons file used on this page or its Wikidata item has been nominated for deletion:
Participate in the deletion discussion at thenomination page. —Community Tech bot (talk)22:40, 7 January 2022 (UTC)[reply]
The article is meant to cover both the arcminute and the arcsecond, but the infobox only covers the arcminute.
Wootery (talk)18:58, 5 June 2022 (UTC)[reply]
The article seems to have been vandalized. Worse yet, the INCORRECT definition here is the first definition brought up in a number of browsers! An arc minute is 1/60th of a degree! Not 1/3600th!!! The subsequently derived numbers are also, therefore wrong. It seems to be an intentional vandalism, since the definition of an arcsecond is identical (and correct).174.130.71.156 (talk)21:21, 8 March 2023 (UTC)[reply]