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Alexandroff extension

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(Redirected fromOne-point compactification)
Way to extend a non-compact topological space

In themathematical field oftopology, theAlexandroff extension is a way to extend a noncompacttopological space by adjoining a single point in such a way that the resulting space iscompact. It is named after the Russian mathematicianPavel Alexandroff.More precisely, letX be a topological space. Then the Alexandroff extension ofX is a certain compact spaceX* together with anopenembeddingc : X → X* such that the complement ofX inX* consists of a single point, typically denoted ∞. The mapc is a Hausdorffcompactification if and only ifX is alocally compact, noncompactHausdorff space. For such spaces the Alexandroff extension is called theone-point compactification orAlexandroff compactification. The advantages of the Alexandroff compactification lie in its simple, often geometrically meaningful structure and the fact that it is in a precise sense minimal among all compactifications; the disadvantage lies in the fact that it only gives a Hausdorff compactification on the class of locally compact, noncompact Hausdorff spaces, unlike theStone–Čech compactification which exists for anytopological space (butprovides an embedding exactly forTychonoff spaces).

Example: inverse stereographic projection

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A geometrically appealing example of one-point compactification is given by the inversestereographic projection. Recall that the stereographic projectionS gives an explicit homeomorphism from the unit sphere minus the north pole (0,0,1) to the Euclidean plane. The inverse stereographic projectionS1:R2S2{\displaystyle S^{-1}:\mathbb {R} ^{2}\hookrightarrow S^{2}} is an open, dense embedding into a compact Hausdorff space obtained by adjoining the additional point=(0,0,1){\displaystyle \infty =(0,0,1)}. Under the stereographic projection latitudinal circlesz=c{\displaystyle z=c} get mapped to planar circlesr=(1+c)/(1c){\textstyle r={\sqrt {(1+c)/(1-c)}}}. It follows that the deleted neighborhood basis of(0,0,1){\displaystyle (0,0,1)} given by the punctured spherical capscz<1{\displaystyle c\leq z<1} corresponds to the complements of closed planar disksr(1+c)/(1c){\textstyle r\geq {\sqrt {(1+c)/(1-c)}}}. More qualitatively, a neighborhood basis at{\displaystyle \infty } is furnished by the setsS1(R2K){}{\displaystyle S^{-1}(\mathbb {R} ^{2}\setminus K)\cup \{\infty \}} asK ranges through the compact subsets ofR2{\displaystyle \mathbb {R} ^{2}}. This example already contains the key concepts of the general case.

Motivation

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Letc:XY{\displaystyle c:X\hookrightarrow Y} be an embedding from a topological spaceX to a compact Hausdorff topological spaceY, with dense image and one-point remainder{}=Yc(X){\displaystyle \{\infty \}=Y\setminus c(X)}. Thenc(X) is open in a compact Hausdorff space so is locally compact Hausdorff, hence its homeomorphic preimageX is also locally compact Hausdorff. Moreover, ifX were compact thenc(X) would be closed inY and hence not dense. Thus a space can only admit a Hausdorff one-point compactification if it is locally compact, noncompact and Hausdorff. Moreover, in such a one-point compactification the image of a neighborhood basis forx inX gives a neighborhood basis forc(x) inc(X), and—because a subset of a compact Hausdorff space is compact if and only if it is closed—the open neighborhoods of{\displaystyle \infty } must be all sets obtained by adjoining{\displaystyle \infty } to the image underc of a subset ofX with compact complement.

The Alexandroff extension

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LetX{\displaystyle X} be a topological space. PutX=X{},{\displaystyle X^{*}=X\cup \{\infty \},} and topologizeX{\displaystyle X^{*}} by taking as open sets all the open sets inX together with all sets of the formV=(XC){}{\displaystyle V=(X\setminus C)\cup \{\infty \}} whereC is closed and compact inX. Here,XC{\displaystyle X\setminus C} denotes the complement ofC{\displaystyle C} inX.{\displaystyle X.} Note thatV{\displaystyle V} is an open neighborhood of,{\displaystyle \infty ,} and thus any open cover of{}{\displaystyle \{\infty \}} will contain all except a compact subsetC{\displaystyle C} ofX,{\displaystyle X^{*},} implying thatX{\displaystyle X^{*}} is compact (Kelley 1975, p. 150).

The spaceX{\displaystyle X^{*}} is called theAlexandroff extension ofX (Willard, 19A). Sometimes the same name is used for the inclusion mapc:XX.{\displaystyle c:X\to X^{*}.}

The properties below follow from the above discussion:

The one-point compactification

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In particular, the Alexandroff extensionc:XX{\displaystyle c:X\rightarrow X^{*}} is a Hausdorff compactification ofX if and only ifX is Hausdorff, noncompact and locally compact. In this case it is called theone-point compactification orAlexandroff compactification ofX.

Recall from the above discussion that any Hausdorff compactification with one point remainder is necessarily (isomorphic to) the Alexandroff compactification. In particular, ifX{\displaystyle X} is a compact Hausdorff space andp{\displaystyle p} is alimit point ofX{\displaystyle X} (i.e. not anisolated point ofX{\displaystyle X}),X{\displaystyle X} is the Alexandroff compactification ofX{p}{\displaystyle X\setminus \{p\}}.

LetX be any noncompactTychonoff space. Under the natural partial ordering on the setC(X){\displaystyle {\mathcal {C}}(X)} of equivalence classes of compactifications, any minimal element is equivalent to the Alexandroff extension (Engelking, Theorem 3.5.12). It follows that a noncompact Tychonoff space admits a minimal compactification if and only if it is locally compact.

Non-Hausdorff one-point compactifications

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Let(X,τ){\displaystyle (X,\tau )} be an arbitrary noncompact topological space. One may want to determine all the compactifications (not necessarily Hausdorff) ofX{\displaystyle X} obtained by adding a single point, which could also be calledone-point compactifications in this context. So one wants to determine all possible ways to giveX=X{}{\displaystyle X^{*}=X\cup \{\infty \}} a compact topology such thatX{\displaystyle X} is dense in it and the subspace topology onX{\displaystyle X} induced fromX{\displaystyle X^{*}} is the same as the original topology. The last compatibility condition on the topology automatically implies thatX{\displaystyle X} is dense inX{\displaystyle X^{*}}, becauseX{\displaystyle X} is not compact, so it cannot be closed in a compact space.Also, it is a fact that the inclusion mapc:XX{\displaystyle c:X\to X^{*}} is necessarily anopen embedding, that is,X{\displaystyle X} must be open inX{\displaystyle X^{*}} and the topology onX{\displaystyle X^{*}} must contain every memberofτ{\displaystyle \tau }.[1]So the topology onX{\displaystyle X^{*}} is determined by the neighbourhoods of{\displaystyle \infty }. Any neighborhood of{\displaystyle \infty } is necessarily the complement inX{\displaystyle X^{*}} of a closed compact subset ofX{\displaystyle X}, as previously discussed.

The topologies onX{\displaystyle X^{*}} that make it a compactification ofX{\displaystyle X} are as follows:

Further examples

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Compactifications of discrete spaces

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Compactifications of continuous spaces

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As a functor

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The Alexandroff extension can be viewed as afunctor from thecategory of topological spaces with proper continuous maps as morphisms to the category whose objects are continuous mapsc:XY{\displaystyle c\colon X\rightarrow Y} and for which the morphisms fromc1:X1Y1{\displaystyle c_{1}\colon X_{1}\rightarrow Y_{1}} toc2:X2Y2{\displaystyle c_{2}\colon X_{2}\rightarrow Y_{2}} are pairs of continuous mapsfX:X1X2, fY:Y1Y2{\displaystyle f_{X}\colon X_{1}\rightarrow X_{2},\ f_{Y}\colon Y_{1}\rightarrow Y_{2}} such thatfYc1=c2fX{\displaystyle f_{Y}\circ c_{1}=c_{2}\circ f_{X}}. In particular, homeomorphic spaces have isomorphic Alexandroff extensions.

See also

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Notes

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  1. ^"General topology – Non-Hausdorff one-point compactifications".
  2. ^abJoseph J. Rotman,An Introduction to Algebraic Topology (1988) Springer-VerlagISBN 0-387-96678-1(See Chapter 11 for proof.)

References

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