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Multiplicity of infection

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Ratio of infecting agents to infection targets
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Inmicrobiology, themultiplicity of infection orMOI is theratio of agents (e.g.phage or more generallyvirus,bacteria) to infection targets (e.g.cell). For example, when referring to a group of cells inoculated with virus particles, the MOI is the ratio of the number of virus particles to the number of target cells present in a defined space.[1]

Interpretation

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The actual number of viruses or bacteria that will enter any given cell is astochastic process: some cells may absorb more than one infectious agent, while others may not absorb any. Before determining the multiplicity of infection, it's absolutely necessary to have a well-isolated agent, as crude agents may not produce reliable and reproducible results. Theprobability that a cell will absorbn{\displaystyle n} virus particles or bacteria when inoculated with an MOI ofm{\displaystyle m} can be calculated for a given population using aPoisson distribution. This application of Poisson's distribution was applied and described by Ellis and Delbrück.[2]

P(n)=mnemn!{\displaystyle P(n)={\frac {m^{n}\cdot e^{-m}}{n!}}}

wherem{\displaystyle m} is the multiplicity of infection or MOI,n{\displaystyle n} is the number of infectious agents that enter the infection target, andP(n){\displaystyle P(n)} is the probability that an infection target (a cell) will get infected byn{\displaystyle n} infectious agents.

In fact, the infectivity of the virus or bacteria in question will alter this relationship. One way around this is to use a functional definition of infectious particles rather than a strict count, such as aplaque forming unit for viruses.[3]

For example, when an MOI of 1 (1 infectious viral particle per cell) is used to infect a population of cells, the probability that a cell will not get infected isP(0)=36.79%{\displaystyle P(0)=36.79\%}, and the probability that it be infected by a single particle isP(1)=36.79%{\displaystyle P(1)=36.79\%}, by two particles isP(2)=18.39%{\displaystyle P(2)=18.39\%}, by three particles isP(3)=6.13%{\displaystyle P(3)=6.13\%}, and so on.

The average percentage of cells that will become infected as a result of inoculation with a given MOI can be obtained by realizing that it is simplyP(n>0)=1P(0){\displaystyle P(n>0)=1-P(0)}. Hence, the average fraction of cells that will become infected following an inoculation with an MOI ofm{\displaystyle m} is given by:

P(n>0)=1P(n=0)=1m0em0!=1em{\displaystyle P(n>0)=1-P(n=0)=1-{\frac {m^{0}\cdot e^{-m}}{0!}}=1-e^{-m}}

which is approximately equal tom{\displaystyle m} for small values ofm1{\displaystyle m\ll 1}.

Example

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Percentage of cells infected based on MOI.

As the MOI increases, the percentages of cells infected with at least one viral particle (n>0{\displaystyle n>0}) also increases.[4]

MOI% Infected
00%
0.19.5%
0.2522.1%
0.539.3%
1.063.2%
2.086.5%
3.095.0%
4.098.2%
5.099.3%

See also

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References

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  1. ^Abedon, S. T.; Bartom, E. (2013-01-01),"Multiplicity of Infection", in Maloy, Stanley; Hughes, Kelly (eds.),Brenner's Encyclopedia of Genetics (Second Edition), San Diego:Academic Press, pp. 509–510,ISBN 978-0-08-096156-9, retrieved2022-03-09
  2. ^Ellis, Emory; Delbruck, Max (Jan 20, 1939)."The Growth of Bacteriophage".The Journal of General Physiology.22 (3):365–384.doi:10.1085/jgp.22.3.365.PMC 2141994.PMID 19873108.
  3. ^"Plaque forming unit".Science Direct.
  4. ^Fields BN, Knipe DM, Howley PM (2007).Fields virology: Part 1. Philadelphia: Wolters Kluwer Health/Lippincott Williams & Wilkins.ISBN 9780781760607.OCLC 71812790.
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