Inphysics,mean free path is the average distance over which a movingparticle (such as anatom, amolecule, or aphoton) travels before substantially changing its direction or energy (or, in a specific context, other properties), typically as a result of one or more successivecollisions with other particles.
Imagine a beam of particles being shot through a target, and consider an infinitesimally thin slab of the target (see the figure).[1] The atoms (or particles) that might stop a beam particle are shown in red. The magnitude of the mean free path depends on the characteristics of the system. Assuming that all the target particles are at rest but only the beam particle is moving, that gives an expression for the mean free path:
whereℓ is the mean free path,n is the number of target particles per unit volume, andσ is the effectivecross-sectional area for collision.
The area of the slab isL2, and its volume isL2 dx. The typical number of stopping atoms in the slab is the concentrationn times the volume, i.e.,n L2 dx. The probability that a beam particle will be stopped in that slab is the net area of the stopping atoms divided by the total area of the slab:
whereσ is the area (or, more formally, the "scattering cross-section") of one atom.
The drop in beam intensity equals the incoming beam intensity multiplied by the probability of the particle being stopped within the slab:
This is anordinary differential equation:
whose solution is known asBeer–Lambert law and has the form, wherex is the distance traveled by the beam through the target, andI0 is the beam intensity before it entered the target;ℓ is called the mean free path because it equals themean distance traveled by a beam particle before being stopped. To see this, note that the probability that a particle is absorbed betweenx andx +dx is given by
Thus theexpectation value (or average, or simply mean) ofx is
The fraction of particles that are not stopped (attenuated) by the slab is calledtransmission, wherex is equal to the thickness of the slab.
In thekinetic theory of gases, themean free path of a particle, such as amolecule, is the average distance the particle travels between collisions with other moving particles. The derivation above assumed the target particles to be at rest; therefore, in reality, the formula holds for a beam particle with a high speed relative to the velocities of an ensemble of identical particles with random locations. In that case, the motions of target particles are comparatively negligible, hence the relative velocity.
If, on the other hand, the beam particle is part of an established equilibrium with identical particles, then the square of relative velocity is:
In equilibrium, and are random and uncorrelated, therefore, and the relative speed is
This means that the number of collisions is times the number with stationary targets. Therefore, the following relationship applies:[2]
and using (ideal gas law) and (effective cross-sectional area for spherical particles with diameter), it may be shown that the mean free path is[3]
wherekB is theBoltzmann constant, is the pressure of the gas and is the absolute temperature.
In practice, the diameter of gas molecules is not well defined. In fact, thekinetic diameter of a molecule is defined in terms of the mean free path. Typically, gas molecules do not behave like hard spheres, but rather attract each other at larger distances and repel each other at shorter distances, as can be described with aLennard-Jones potential. One way to deal with such "soft" molecules is to use the Lennard-Jones σ parameter as the diameter.
Another way is to assume a hard-sphere gas that has the sameviscosity as the actual gas being considered. This leads to a mean free path[4]
where is the molecular mass, is the density of ideal gas, andμ is the dynamic viscosity. This expression can be put into the following convenient form
with being thespecific gas constant, equal to 287 J/(kg*K) for air.
The following table lists some typical values for air at different pressures at room temperature. Note that different definitions of the molecular diameter, as well as different assumptions about the value of atmospheric pressure (100 vs 101.3 kPa) and room temperature (293.17 K vs 296.15 K or even 300 K) can lead to slightly different values of the mean free path.
Vacuum range | Pressure inhPa (mbar) | Pressure inmmHg (Torr) | number density (Molecules / cm3) | number density (Molecules / m3) | Mean free path |
---|---|---|---|---|---|
Ambient pressure | 1013 | 759.8 | 2.7 × 1019 | 2.7 × 1025 | 64 – 68nm[5] |
Low vacuum | 300 – 1 | 220 – 8×10−1 | 1019 – 1016 | 1025 – 1022 | 0.1 – 100μm |
Medium vacuum | 1 – 10−3 | 8×10−1 – 8×10−4 | 1016 – 1013 | 1022 – 1019 | 0.1 – 100 mm |
High vacuum | 10−3 – 10−7 | 8×10−4 – 8×10−8 | 1013 – 109 | 1019 – 1015 | 10 cm – 1 km |
Ultra-high vacuum | 10−7 – 10−12 | 8×10−8 – 8×10−13 | 109 – 104 | 1015 – 1010 | 1 km – 105 km |
Extremely high vacuum | <10−12 | <8×10−13 | <104 | <1010 | >105 km |
Ingamma-rayradiography themean free path of apencil beam of mono-energeticphotons is the average distance a photon travels between collisions with atoms of the target material. It depends on the material and the energy of the photons:
whereμ is thelinear attenuation coefficient,μ/ρ is themass attenuation coefficient andρ is thedensity of the material. Themass attenuation coefficient can be looked up or calculated for any material and energy combination using theNational Institute of Standards and Technology (NIST) databases.[7][8]
InX-rayradiography the calculation of themean free path is more complicated, because photons are not mono-energetic, but have somedistribution of energies called aspectrum. As photons move through the target material, they areattenuated with probabilities depending on their energy, as a result their distribution changes in process called spectrum hardening. Because of spectrum hardening, themean free path of theX-ray spectrum changes with distance.
Sometimes one measures the thickness of a material in thenumber of mean free paths. Material with the thickness of onemean free path will attenuate to 37% (1/e) of photons. This concept is closely related tohalf-value layer (HVL): a material with a thickness of one HVL will attenuate 50% of photons. A standard x-ray image is a transmission image, an image with negative logarithm of its intensities is sometimes called anumber of mean free paths image.
In macroscopic charge transport, the mean free path of acharge carrier in a metal is proportional to theelectrical mobility, a value directly related toelectrical conductivity, that is:
whereq is thecharge, is themean free time,m* is theeffective mass, andvF is theFermi velocity of the charge carrier. The Fermi velocity can easily be derived from theFermi energy via the non-relativistic kinetic energy equation. Inthin films, however, the film thickness can be smaller than the predicted mean free path, making surface scattering much more noticeable, effectively increasing theresistivity.
Electron mobility through a medium with dimensions smaller than the mean free path of electrons occurs throughballistic conduction or ballistic transport. In such scenarios electrons alter their motion only in collisions with conductor walls.
If one takes a suspension of non-light-absorbing particles of diameterd with avolume fractionΦ, the mean free path of the photons is:[9]
whereQs is the scattering efficiency factor.Qs can be evaluated numerically for spherical particles usingMie theory.
In an otherwise empty cavity, the mean free path of a single particle bouncing off the walls is:
whereV is the volume of the cavity,S is the total inside surface area of the cavity, andF is a constant related to the shape of the cavity. For most simple cavity shapes,F is approximately 4.[10]
This relation is used in the derivation of theSabine equation in acoustics, using a geometrical approximation of sound propagation.[11]
In particle physics the concept of the mean free path is not commonly used, being replaced by the similar concept ofattenuation length. In particular, for high-energy photons, which mostly interact by electron–positronpair production, theradiation length is used much like the mean free path in radiography.
Independent-particle models in nuclear physics require the undisturbed orbiting ofnucleons within thenucleus before they interact with other nucleons.[12]
The effective mean free path of a nucleon in nuclear matter must be somewhat larger than the nuclear dimensions in order to allow the use of the independent particle model. This requirement seems to be in contradiction to the assumptions made in the theory ... We are facing here one of the fundamental problems of nuclear structure physics which has yet to be solved.
— John Markus Blatt andVictor Weisskopf,Theoretical nuclear physics (1952)[13]
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