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Deformation (engineering)

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Change in the shape or size of an object
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For usage in physics, seeDeformation (physics).
Compressive stress results in deformation which shortens the object but also expands it outwards.

Inengineering,deformation (the change in size or shape of an object) may beelastic orplastic.If the deformation is negligible, the object is said to berigid.

Main concepts

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Occurrence of deformation in engineering applications is based on the following background concepts:

  • Displacements are any change in position of a point on the object, including whole-body translations and rotations (rigid transformations).
  • Deformation are changes in the relative position between internals points on the object, excluding rigid transformations, causing the body to change shape or size.
  • Strain is therelativeinternal deformation, thedimensionless change in shape of an infinitesimal cube of material relative to a reference configuration. Mechanical strains are caused bymechanical stress,seestress-strain curve.

The relationship between stress and strain is generally linear and reversible up until theyield point and the deformation iselastic. Elasticity in materials occurs when applied stress does not surpass the energy required to break molecular bonds, allowing the material to deform reversibly and return to its original shape once the stress is removed. The linear relationship for a material is known asYoung's modulus. Above the yield point, some degree of permanent distortion remains after unloading and is termedplastic deformation. The determination of the stress and strain throughout a solid object is given by the field ofstrength of materials and for a structure bystructural analysis.

In the above figure, it can be seen that the compressive loading (indicated by the arrow) has caused deformation in thecylinder so that the original shape (dashed lines) has changed (deformed) into one with bulging sides. The sides bulge because the material, although strong enough to not crack or otherwise fail, is not strong enough to support the load without change. As a result, the material is forced out laterally. Internal forces (in this case at right angles to the deformation) resist the applied load.

Types of deformation

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Depending on the type of material, size and geometry of the object, and the forces applied, various types of deformation may result. The image to the right shows the engineering stress vs. strain diagram for a typical ductile material such as steel. Different deformation modes may occur under different conditions, as can be depicted using adeformation mechanism map.

Permanent deformation is irreversible; the deformation stays even after removal of the applied forces, while the temporary deformation is recoverable as it disappears after the removal of applied forces.Temporary deformation is also calledelastic deformation, while the permanent deformation is calledplastic deformation.

Typical stress vs. strain diagram indicating the various stages of deformation.

Elastic deformation

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Further information:Elasticity (physics)

The study of temporary or elastic deformation in the case ofengineering strain is applied to materials used in mechanical and structural engineering, such asconcrete andsteel, which are subjected to very small deformations. Engineering strain is modeled byinfinitesimal strain theory, also calledsmall strain theory,small deformation theory,small displacement theory, orsmall displacement-gradient theory where strains and rotations are both small.

For some materials, e.g.elastomers and polymers, subjected to large deformations, the engineering definition of strain is not applicable, e.g. typical engineering strains greater than 1%,[1] thus other more complex definitions of strain are required, such asstretch,logarithmic strain,Green strain, andAlmansi strain.Elastomers andshape memory metals such asNitinol exhibit large elastic deformation ranges, as doesrubber. However, elasticity is nonlinear in these materials.

Normal metals, ceramics and most crystals show linear elasticity and a smaller elastic range.

Linear elastic deformation is governed byHooke's law, which states:

σ=Eε{\displaystyle \sigma =E\varepsilon }

where

This relationship only applies in the elastic range and indicates that the slope of the stress vs. strain curve can be used to find Young's modulus (E). Engineers often use this calculation in tensile tests. The area under this elastic region is known as resilience.

Note that not all elastic materials undergo linear elastic deformation; some, such asconcrete,gray cast iron, and many polymers, respond in a nonlinear fashion. For these materials Hooke's law is inapplicable.[2]

Difference in true and engineeringstress-strain curves

Plastic deformation

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Swebor-brand high-strength low alloy steel plate, showing both sides, after plastic deformation from bringing to restprojectiles inballistics testing.
See also:Plasticity (physics)

This type of deformation is not undone simply by removing the applied force. An object in the plastic deformation range, however, will first have undergone elastic deformation, which is undone simply by removing the applied force, so the object will return part way to its original shape. Softthermoplastics have a rather large plastic deformation range as do ductile metals such ascopper,silver, andgold.Steel does, too, but notcast iron. Hard thermosetting plastics, rubber, crystals, and ceramics have minimal plastic deformation ranges. An example of a material with a large plastic deformation range is wetchewing gum, which can be stretched to dozens of times its original length.

Under tensile stress, plastic deformation is characterized by astrain hardening region and anecking region and finally, fracture (also called rupture). During strain hardening the material becomes stronger through the movement ofatomic dislocations. The necking phase is indicated by a reduction in cross-sectional area of the specimen. Necking begins after the ultimate strength is reached. During necking, the material can no longer withstand the maximum stress and the strain in the specimen rapidly increases. Plastic deformation ends with the fracture of the material.

Diagram of astress–strain curve, showing the relationship between stress (force applied) and strain (deformation) of a ductile metal.

Failure

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Compressive failure

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Usually, compressive stress applied to bars,columns, etc. leads to shortening.

Loading a structural element or specimen will increase the compressive stress until it reaches itscompressive strength. According to the properties of the material, failure modes areyielding for materials withductile behavior (mostmetals, somesoils andplastics) or rupturing for brittle behavior (geomaterials,cast iron,glass, etc.).

In long, slender structural elements — such as columns ortruss bars — an increase of compressive forceF leads tostructural failure due tobuckling at lower stress than the compressive strength.

Fracture

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See also:Concrete fracture analysis andFracture mechanics

A break occurs after the material has reached the end of the elastic, and then plastic, deformation ranges. At this point forces accumulate until they are sufficient to cause a fracture. All materials will eventually fracture, if sufficient forces are applied.

Types of stress and strain

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Engineering stress andengineering strain are approximations to the internal state that may be determined from the external forces and deformations of an object, provided that there is no significant change in size. When there is a significant change in size, thetrue stress andtrue strain can be derived from the instantaneous size of the object.

Engineering stress and strain

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Consider a bar of originalcross sectional areaA0 being subjected to equal and opposite forcesF pulling at the ends so the bar is under tension. The material is experiencing a stress defined to be the ratio of the force to the cross sectional area of the bar, as well as an axial elongation:

Eng. stress & strain equations
StressStrain
σ=FA0{\displaystyle \sigma ={\frac {F}{A_{0}}}}ε=LL0L0=ΔLL0{\displaystyle \varepsilon ={\frac {L-L_{0}}{L_{0}}}={\frac {\Delta L}{L_{0}}}}

Subscript 0 denotes the original dimensions of the sample. TheSI derived unit for stress isnewtons per square metre, orpascals (1 pascal = 1 Pa = 1 N/m2), and strain isunitless. The stress–strain curve for this material is plotted by elongating the sample and recording the stress variation with strain until the samplefractures. By convention, the strain is set to the horizontal axis and stress is set to vertical axis. Note that for engineering purposes we often assume the cross-section area of the material does not change during the whole deformation process. This is not true since the actual area will decrease while deforming due to elastic and plastic deformation. The curve based on the original cross-section and gauge length is called theengineering stress–strain curve, while the curve based on the instantaneous cross-section area and length is called thetrue stress–strain curve. Unless stated otherwise, engineering stress–strain is generally used.

True stress and strain

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The difference between true stress–strain curve and engineering stress–strain curve

In the above definitions of engineering stress and strain, two behaviors of materials in tensile tests are ignored:

  • the shrinking of section area
  • compounding development of elongation

True stress andtrue strain are defined differently than engineering stress and strain to account for these behaviors. They are given as

True stress & strain equations
StressStrain
σt=FA{\displaystyle \sigma _{\mathrm {t} }={\frac {F}{A}}}εt=δLL{\displaystyle \varepsilon _{\mathrm {t} }=\int {\frac {\delta L}{L}}}

Here the dimensions are instantaneous values. Assuming volume of the sample conserves and deformation happens uniformly,

A0L0=AL{\displaystyle A_{0}L_{0}=AL}

The true stress and strain can be expressed by engineering stress and strain. For true stress,

σt=FA=FA0A0A=FA0LL0=σ(1+ε){\displaystyle \sigma _{\mathrm {t} }={\frac {F}{A}}={\frac {F}{A_{0}}}{\frac {A_{0}}{A}}={\frac {F}{A_{0}}}{\frac {L}{L_{0}}}=\sigma (1+\varepsilon )}

For the strain,

δεt=δLL{\displaystyle \delta \varepsilon _{\mathrm {t} }={\frac {\delta L}{L}}}

Integrate both sides and apply the boundary condition,

εt=ln(LL0)=ln(1+ε){\displaystyle \varepsilon _{\mathrm {t} }=\ln \left({\frac {L}{L_{0}}}\right)=\ln(1+\varepsilon )}

So in atension test, true stress is larger than engineering stress and true strain is less than engineering strain. Thus, a point defining true stress–strain curve is displaced upwards and to the left to define the equivalent engineering stress–strain curve. The difference between the true and engineering stresses and strains will increase withplastic deformation. At low strains (such aselastic deformation), the differences between the two is negligible. As for the tensile strength point, it is the maximal point in engineering stress–strain curve but is not a special point in true stress–strain curve. Because engineering stress is proportional to the force applied along the sample, the criterion fornecking formation can be set asδF=0.{\displaystyle \delta F=0.}

δF=σtδA+Aδσt=0δAA=δσtσt{\displaystyle {\begin{aligned}&\delta F=\sigma _{\text{t}}\,\delta A+A\,\delta \sigma _{\text{t}}=0\\&-{\frac {\delta A}{A}}={\frac {\delta \sigma _{\mathrm {t} }}{\sigma _{\mathrm {t} }}}\end{aligned}}}

This analysis suggests nature of theultimate tensile strength (UTS) point. Thework strengthening effect is exactly balanced by the shrinking of section area at UTS point.

After the formation of necking, the sample undergoes heterogeneous deformation, so equations above are not valid. The stress and strain at the necking can be expressed as:

σt=FAneckεt=ln(A0Aneck){\displaystyle {\begin{aligned}\sigma _{\mathrm {t} }&={\frac {F}{A_{\mathrm {neck} }}}\\\varepsilon _{\mathrm {t} }&=\ln \left({\frac {A_{0}}{A_{\mathrm {neck} }}}\right)\end{aligned}}}

Anempirical equation is commonly used to describe the relationship between true stress and true strain.

σt=K(εt)n{\displaystyle \sigma _{\mathrm {t} }=K(\varepsilon _{\mathrm {t} })^{n}}

Here,n is the strain-hardening exponent andK is the strength coefficient.n is a measure of a material's work hardening behavior. Materials with a highern have a greater resistance to necking. Typically, metals at room temperature haven ranging from 0.02 to 0.5.[3]

Discussion

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Since we disregard the change of area during deformation above, the true stress and strain curve should be re-derived. For deriving the stress strain curve, we can assume that the volume change is 0 even if we deformed the materials. We can assume that:

Ai×εi=Af×εf{\displaystyle A_{i}\times \varepsilon _{i}=A_{f}\times \varepsilon _{f}}

Then, the true stress can be expressed as below:

σT=FAf=FAi×AiAf=σe×lfli=σE×li+δlli=σE(1+εE){\displaystyle {\begin{aligned}\sigma _{T}={\frac {F}{A_{f}}}&={\frac {F}{A_{i}}}\times {\frac {A_{i}}{A_{f}}}\\&=\sigma _{e}\times {\frac {l_{f}}{l_{i}}}\\[2pt]&=\sigma _{E}\times {\frac {l_{i}+\delta l}{l_{i}}}\\[2pt]&=\sigma _{E}(1+\varepsilon _{E})\end{aligned}}}

Additionally, the true strainεT can be expressed as below:

εT=dll0+dll1+dll2+=idlli{\displaystyle \varepsilon _{T}={\frac {dl}{l_{0}}}+{\frac {dl}{l_{1}}}+{\frac {dl}{l_{2}}}+\cdots =\sum _{i}{\frac {dl}{l_{i}}}}

Then, we can express the value as

l0lidlldx=ln(lil0)=ln(1+εE){\displaystyle \int _{l_{0}}^{l_{i}}{\frac {dl}{l}}\,dx=\ln \left({\frac {l_{i}}{l_{0}}}\right)=\ln(1+\varepsilon _{E})}

Thus, we can induce the plot in terms ofσT{\displaystyle \sigma _{T}} andεE{\displaystyle \varepsilon _{E}} as right figure.

Additionally, based on the true stress-strain curve, we can estimate the region where necking starts to happen. Since necking starts to appear after ultimate tensile stress where the maximum force applied, we can express this situation as below:

dF=0=σTdAi+AidσT{\displaystyle dF=0=\sigma _{T}dA_{i}+A_{i}d\sigma _{T}}

so this form can be expressed as below:

dσTσT=dAiAi{\displaystyle {\frac {d\sigma _{T}}{\sigma _{T}}}=-{\frac {dA_{i}}{A_{i}}}}

It indicates that the necking starts to appear where reduction of area becomes much significant compared to the stress change. Then the stress will be localized to specific area where the necking appears.

Additionally, we can induce various relation based on true stress-strain curve.

1) True strain and stress curve can be expressed by the approximate linear relationship by taking a log on true stress and strain. The relation can be expressed as below:

σT=K×(εT)n{\displaystyle \sigma _{T}=K\times (\varepsilon _{T})^{n}}

WhereK{\displaystyle K} is stress coefficient andn{\displaystyle n} is strain-hardening coefficient. Usually, the value ofn{\displaystyle n} has range around 0.02 to 0.5 at room temperature. Ifn{\displaystyle n} is 1, we can express this material as perfect elastic material.[4][5]

2) In reality, stress is also highly dependent on the rate of strain variation. Thus, we can induce the empirical equation based on the strain rate variation.

σT=K×(εT˙)m{\displaystyle \sigma _{T}=K'\times ({\dot {\varepsilon _{T}}})^{m}}
True stress-strain curve of FCC metal and its derivative form[4]

WhereK{\displaystyle K'} is constant related to the material flow stress.εT˙{\displaystyle {\dot {\varepsilon _{T}}}} indicates the derivative of strain by the time, which is also known as strain rate.m{\displaystyle m} is the strain-rate sensitivity. Moreover, value ofm{\displaystyle m} is related to the resistance toward the necking. Usually, the value ofm{\displaystyle m} is at the range of 0-0.1 at room temperature and as high as 0.8 when the temperature is increased.

By combining the 1) and 2), we can create the ultimate relation as below:

σT=K×(εT)n(εT˙)m{\displaystyle \sigma _{T}=K''\times (\varepsilon _{T})^{n}({\dot {\varepsilon _{T}}})^{m}}

WhereK{\displaystyle K''} is the global constant for relating strain, strain rate and stress.

3) Based on the true stress-strain curve and its derivative form, we can estimate the strain necessary to start necking. This can be calculated based on the intersection between true stress-strain curve as shown in right.

This figure also shows the dependency of the necking strain at different temperature. In case of FCC metals, both of the stress-strain curve at its derivative are highly dependent on temperature. Therefore, at higher temperature, necking starts to appear even under lower strain value.

All of these properties indicate the importance of calculating the true stress-strain curve for further analyzing the behavior of materials in sudden environment.

4) A graphical method, so-called "Considere construction", can help determine the behavior of stress-strain curve whether necking or drawing happens on the sample. By settingλ=L/L0{\displaystyle \lambda =L/L_{0}}as determinant, the true stress and strain can be expressed with engineering stress and strain as below:

σT=σe×λ,εT=lnλ.{\displaystyle \sigma _{T}=\sigma _{e}\times \lambda ,\qquad \varepsilon _{T}=\ln \lambda .}

Therefore, the value of engineering stress can be expressed by the secant line from made by true stress andλ{\displaystyle \lambda } value whereλ=0{\displaystyle \lambda =0} toλ=1{\displaystyle \lambda =1}. By analyzing the shape ofσTλ{\displaystyle \sigma _{T}-\lambda } diagram and secant line, we can determine whether the materials show drawing or necking.

Considere Plot. (a) True stress-strain curve without tangents. There is neither necking nor drawing. (b) With one tangent. There is only necking. (c) With two tangents. There are both necking and drawing.[6]

On the figure (a), there is only concave upward Considere plot. It indicates that there is no yield drop so the material will be suffered from fracture before it yields. On the figure (b), there is specific point where the tangent matches with secant line at point whereλ=λY{\displaystyle \lambda =\lambda _{Y}}. After this value, the slope becomes smaller than the secant line where necking starts to appear. On the figure (c), there is point where yielding starts to appear but whenλ=λd{\displaystyle \lambda =\lambda _{d}}, the drawing happens. After drawing, all the material will stretch and eventually show fracture. BetweenλY{\displaystyle \lambda _{Y}} andλd{\displaystyle \lambda _{d}}, the material itself does not stretch but rather, only the neck starts to stretch out.

Misconceptions

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A popular misconception is that all materials that bend are "weak" and those that do not are "strong". In reality, many materials that undergo large elastic and plastic deformations, such as steel, are able to absorb stresses that would cause brittle materials, such as glass, with minimal plastic deformation ranges, to break.[7]

See also

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References

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  1. ^Rees, David (2006).Basic Engineering Plasticity: An Introduction with Engineering and Manufacturing Applications. Butterworth-Heinemann. p. 41.ISBN 0-7506-8025-3.Archived from the original on 2017-12-22.
  2. ^Callister, William D. (2004)Fundamentals of Materials Science and Engineering, John Wiley and Sons, 2nd ed. p. 184.ISBN 0-471-66081-7.
  3. ^Courtney, Thomas (2005).Mechanical behavior of materials. Waveland Press, Inc. pp. 6–13.
  4. ^abCourtney, Thomas (2000).Mechanical Behavior of Materials. Illinois: Waveland Press. p. 165.ISBN 9780073228242.
  5. ^"True Stress and Strain"(PDF). Archived fromthe original(PDF) on 2018-01-27. Retrieved2018-05-15.
  6. ^Roland, David."STRESS-STRAIN CURVES"(PDF).MIT.
  7. ^Rice, Peter and Dutton, Hugh (1995).Structural glass. Taylor & Francis. p. 33.ISBN 0-419-19940-3.{{cite book}}: CS1 maint: multiple names: authors list (link)
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