| Parameter | Value |
|---|---|
| renal blood flow | RBF = 1000 mL/min |
| hematocrit | HCT = 40% |
| glomerular filtration rate | GFR = 120 mL/min |
| renal plasma flow | RPF = 600 mL/min |
| filtration fraction | FF = 20% |
| urine flow rate | V = 1 mL/min |
| Sodium | Inulin | Creatinine | PAH |
|---|---|---|---|
| SNa = 150 mEq/L | SIn = 1 mg/mL | SCr = 0.01 mg/mL | SPAH = |
| UNa = 710 mEq/L | UIn = 150 mg/mL | UCr = 1.25 mg/mL | UPAH = |
| CNa = 5 mL/min | CIn = 150 mL/min | CCr = 125 mL/min | CPAH = 420 mL/min |
| ER = 90% | |||
| ERPF = 540 mL/min |
Effective renal plasma flow (eRPF) is a measure used inrenal physiology[1] to calculaterenal plasma flow (RPF) and hence estimaterenal function.
Because theextraction ratio of PAH is high, it has become commonplace to estimate the RPF by dividing the amount of PAH in the urine by the plasma PAH level, ignoring the level in renal venous blood. The value obtained in this way is called the effective renal plasma flow (eRPF) to indicate that the level in renal venous plasma was not measured.[2]: 664–665
The actual RPF can be calculated from eRPF as follows:
whereextraction ratio is the ratio of compound entering the kidney that is excreted into the final urine.[2]: 664–665
When using a compound with an extraction ratio near 1, such aspara-aminohippurate (PAH), eRPF approximates RPF. Therefore,PAH clearance can be used to estimate RPF.[3]
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