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I want to use regex to match the string of the following format :(#sometext#)

In the sense ,whatever is there between (# and#) only should be matched.So, the text:

var s = "hello(%npm%)hi";var res = s.split(/(\([^()]*\))/);alert(res[0]);o/p: hello(%npm%)hi

And

var s = "hello(#npm#)hi";var res = s.split(/(\([^()]*\))/);alert(res[0]);o/p: helloalert(res[1]);o/p : (#npm#);

But the thing is , the regex/(\([^()]*\))/ is matching everything between() rather than extracting the string including(# .. #)like:

hello(#npm#)hi
Brian Tompsett - 汤莱恩's user avatar
Brian Tompsett - 汤莱恩
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askedJan 9, 2017 at 5:28
user1400915's user avatar
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    You can do something likes.match(/\(#([^#]*)#\)/) if you don't need the parts outside the parentheses. (Why are you using.split()? If you really want to do that then maybe something likes.split(/(\(#|#\))/)?)CommentedJan 9, 2017 at 5:31
  • @nnnnnn: I have edited the questionCommentedJan 9, 2017 at 5:36
  • Try this:s.match(/((#([^#]*)#))/);CommentedJan 9, 2017 at 5:43

3 Answers3

2

By going in your way of fetching content, try this:

var s = "hello(%npm%)hi";var res = s.split(/\(%(.*?)%\)/);alert(res[1]);//o/p: hello(%npm%)hivar s = "hello(#npm#)hi";    var res = s.split(/(\(#.*?#\))/);console.log(res);    //hello, (#npm#), hi

From your comment, updated the second portion, you get your segments in res array:

[  "hello",  "(#npm#)",  "hi"]
answeredJan 9, 2017 at 5:39
Mustofa Rizwan's user avatar
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I need the output as : hello, (#npm#), hi for the second example
1

The following pattern is going to give the required output:

var s = "hello(#&yu()#$@8#)hi";var res = s.split(/(\(#.*#\))/);console.log(res);

"." matches everything between (# and #)

answeredJan 9, 2017 at 6:14
user2630764's user avatar

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It depends if you have multiple matches per string.

// like this if there is only 1 match per textvar text = "some text #goes#";var matches = text.match(/#([^#]+)#/);console.log(matches[1]);// like this if there is multiple matches per textvar text2 = "some text #goes# and #here# more";var matches = text2.match(/#[^#]+#/g).map(function (e){  // strip the extra #'s  return e.match(/#([^#]+)#/)[1];});console.log(matches);

answeredJan 9, 2017 at 5:35
Phil Poore's user avatar

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