I am completely new to JS, and having trouble figuring out how to validate that theinputvia promptCONTAINS three or more words, seperated by spaces, only alphabetical characters.
This is what I have:
var p = prompt("Enter a phrase:", "");var phr = p.search(/^[^0-9][2,3]$/); if(phr != 0){ alert("invalid");return}else{document.write("phr");
- @Floris-
\wwill match digits also. Besides that your expression will require, for a string three character long, to have an additional space.edi_allen– edi_allen2013-10-31 20:22:53 +00:00CommentedOct 31, 2013 at 20:22 - @edi_allen - you were right. Don't know what I was thinking.Floris– Floris2013-10-31 20:49:50 +00:00CommentedOct 31, 2013 at 20:49
2 Answers2
Use:
if (/^([a-z]+\s+){2,}[a-z]+$/i.test(p))Explanation:
[a-z]= alphabetic character[a-z]+= 1 or more alphabetic character, i.e. a word[a-z]+\s+= word followed by 1 or more whitespace characters([a-z]+\s+)= at least 2 words with whitespace after each([a-z]+\s+){2,}[a-z]+= the above followed by 1 more word^([a-z]+\s+){2,}[a-z]+$= anchor the above to the beginning and end of the string
Thei modifier makes it case-insensitive, so it will allow uppercase letters as well.
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prompt CONTAINS three or more words, seperated by spaces, only alphabetical characters.
You can try this regex:
/^[a-z]+( +[a-z]+){2,}$/i
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