String Interpolation with Data Support

Thestrs_format function provides string interpolation using values from a data argument, similar to Python'sstr.format method. For more information, see the details.

Usage

strs_format(string,..., .data=NULL)

Arguments

string

A character vector containing the string with placeholders in curly braces{}. If the vector containsmore than one string, they are concatenated before interpolation.

...

Named arguments that will be made available duringstring interpolation. Note that these will takeprecedence over values in.data.

.data

List-like (e.g., data.frame, list, environment, etc.) object that will be used for lookups duringstring interpolation.

Value

A character vector with the placeholders replaced by the evaluated expressions.

Details

Under the hood, this function uses theglue::glue_data() function to perform the interpolation. Bydefault, this function will only use the variables provided in... and.data. It will NOT use the immediateenvironment to perform the interpolations. If any interpolated expression is NA, it will be NA in the output. If anyinterpolated expression is NULL, it will be NULL in the output.

Examples

# Using a named list for substitutionsdata_list<-list(name="Alice", age=30)strs_format("My name is {name} and I am {age} years old.", .data=data_list)#> [1] "My name is Alice and I am 30 years old."# Output: "My name is Alice and I am 30 years old."# Using additional argumentsstrs_format("My name is {name} and I am {age} years old.", name="Bob", age=25)#> [1] "My name is Bob and I am 25 years old."# Output: "My name is Bob and I am 25 years old."