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  • $\begingroup$Excuse me, I have a stupid question, how to show the Noether charge for local gauge transformation is zero? I looked for this topic in this website, but did not get the point ...$\endgroup$CommentedFeb 20, 2014 at 2:20
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    $\begingroup$The second Noether states that the Noether current for any infinitesimal local symmetry vanishes on shell. However, this is based on the assumption that local symmetries act as the identity outside a bounded space-time region. Global gauge symmetries are not of this kind, they do not act as the identity as you move to infinity. Just think of Gauss's law: by measuring the electric flux through an arbitrarily large sphere, you can determine the amont of electric charge bounded by it.$\endgroup$CommentedFeb 20, 2014 at 3:59
  • $\begingroup$For a thorough discussion on how Gauss's law is coherent with the second Noether theorem, I recommend the (long) paper by M. Forger and H. Römer,Currents and the Energy-Momentum Tensor in Classical Field Theory: A fresh look at an Old Problem, Annals Phys.309 (2004) 306-389, arXiv:hep-th/0307199. See also the related physics.SE questionphysics.stackexchange.com/q/46476$\endgroup$CommentedFeb 20, 2014 at 4:09
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    $\begingroup$Doesn't the algebra of first class constraints generate the gauge transformations?$\endgroup$CommentedFeb 20, 2014 at 4:44
  • $\begingroup$@Dan: That is correct (up to some pathological counter-examples), but the first class constraints are not Noether charges, they rather appear in the Noether identities that encode the on-shell vanishing of the corresponding Noether current.$\endgroup$CommentedFeb 20, 2014 at 6:56
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