CN115002917A - Underground pipe gallery multi-service communication isolation method based on WiFi6 - Google Patents
Underground pipe gallery multi-service communication isolation method based on WiFi6Download PDFInfo
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Abstract
Translated fromChinese
Description
Translated fromChinese技术领域technical field
本发明涉及一种基于WiFi6的地下管廊多业务通信隔离方法，属于网络业务量管理技术 领域。The invention relates to a WiFi6-based multi-service communication isolation method for an underground pipe gallery, and belongs to the technical field of network traffic management.
背景技术Background technique
地下综合管廊中包含水、电、煤气等多个不同体系的线路管道，共用地下综合管廊空间， 存在种类繁多的通信需求。The underground integrated pipe gallery contains lines and pipelines of different systems such as water, electricity, and gas, sharing the space of the underground integrated pipe gallery, and there are various communication needs.
WiFi6作为最新一代可在通信能力方面对标5G的无线接入技术，成为一种适合地下管廊 多业务通信的技术选型。WiFi6中的OFDMA(Orthogonal Frequency DivisionMultiple Access，正交频分多址接入)技术和MU-MIMO(Multi-User Multiple-InputMultiple-Output, multi-user multiple input multiple output，多用户-多输入多输出)技术可以物理分割信 道资源，利用差异化信道提供通信隔离解决方案。OFDMA技术可以从频域上将工作带宽划分 为多个子信道，这些子信道可以称为资源单元RU；在WiFi6中，信道带宽可以是20、40、80、 160MHz等，带宽可以分为不同大小的RU，RU的最小规格为2MHz，由26个78.125KHz的子 载波组成，除26子载波规格的RU外，还存在52子载波、106子载波、242子载波等规格的 RU。RU可以分配给多个不同的终端，在同一时间为多个不同的业务服务。MU-MIMO技术在发 送端和接收端使用多根同频天线，在接收端实现对多根天线构成的多个信道的分集进行接收 与合并；它能充分利用空间资源，利用多径传播特性，在不增加频谱资源和发射功率的前提 下，提高业务承载能力。As the latest generation of wireless access technology that can benchmark 5G in terms of communication capabilities, WiFi6 has become a technology selection suitable for multi-service communication in underground pipe corridors. OFDMA (Orthogonal Frequency Division Multiple Access, Orthogonal Frequency Division Multiple Access) technology and MU-MIMO (Multi-User Multiple-Input Multiple-Output, multi-user multiple input multiple output) in WiFi6 The technology can physically divide channel resources and provide communication isolation solutions using differentiated channels. OFDMA technology can divide the working bandwidth into multiple sub-channels in the frequency domain, and these sub-channels can be called resource units RU; in WiFi6, the channel bandwidth can be 20, 40, 80, 160 MHz, etc., and the bandwidth can be divided into RU, the minimum specification of RU is 2MHz, which consists of 26 sub-carriers of 78.125KHz. In addition to the RU of 26 sub-carrier specifications, there are RUs of 52 sub-carriers, 106 sub-carriers, and 242 sub-carriers. RUs can be allocated to multiple different terminals to serve multiple different services at the same time. MU-MIMO technology uses multiple co-frequency antennas at the transmitting end and the receiving end, and realizes the diversity reception and combination of multiple channels formed by multiple antennas at the receiving end; On the premise of not increasing spectrum resources and transmit power, the service carrying capacity is improved.
传统多业务无线通信隔离一般通过不同的通信设备承载不同的业务来实现，隔离效果好 但成本较高，同时无法发挥WiFi6多业务并发通信的优势，难以适应城市地下管廊建设要求。Traditional multi-service wireless communication isolation is generally achieved by different communication devices carrying different services. The isolation effect is good but the cost is high. At the same time, the advantages of WiFi6 multi-service concurrent communication cannot be used, and it is difficult to adapt to the construction requirements of urban underground pipe corridors.
发明内容SUMMARY OF THE INVENTION
本发明要解决的技术问题是：使地下管廊的多业务通信彼此隔离。The technical problem to be solved by the present invention is to isolate the multi-service communication of the underground pipe gallery from each other.
本发明为解决上述技术问题提出的技术方案是：一种基于WiFi6的地下管廊多业务通信 隔离方法,包括以下步骤:The technical scheme that the present invention proposes to solve the above-mentioned technical problems is: a kind of underground pipe gallery multi-service communication isolation method based on WiFi6, comprises the following steps:
1)构建包括业务层、频域层和空域层的通信架构；1) Construct a communication architecture including business layer, frequency domain layer and airspace layer;
2)在地下管廊通信业务终端将通信需求上报到WiFi6无线AP设备之后，先在所述业务 层根据通信业务信息将通信业务划分为多个通信业务组；2) after the communication demand is reported to the WiFi6 wireless AP equipment at the underground pipe gallery communication service terminal, first at the described service layer, the communication service is divided into a plurality of communication service groups according to the communication service information;
3)在所述频域层，通过WiFi6的OFDMA将通信工作带宽划分为若干个RU，对所述通信 业务组分配RU资源；3) in the frequency domain layer, the communication operating bandwidth is divided into several RUs by OFDMA of WiFi6, and RU resources are allocated to the communication service group;
4)在所述空域层，通过WiFi6的MU-MIMO对信道资源进行空分复用，所述通信业务组获 得RU之后，在通信业务组内部的通信业务之间分配多天线多空间流资源，不同通信业务由不 同空间流承载，不同空间流在不同空间路径传输。4) In the airspace layer, space division multiplexing is performed on channel resources through MU-MIMO of WiFi6, and after the communication service group obtains the RU, multi-antenna multi-spatial stream resources are allocated among the communication services within the communication service group, Different communication services are carried by different spatial streams, and different spatial streams are transmitted in different spatial paths.
进一步，所述步骤2)中，所述通信业务组的划分如下：Further, in the step 2), the division of the communication service group is as follows:
2.1)统计通信业务信息2.1) Statistical communication service information
记通信业务的总数为M，通信业务记为SVC＝{SVC1，SVC2，...，SVCM}；通信业务类型V＝{V1，V2，...，VM},传输速率要求记为R＝{R1，R2，...，RM}；单空间流106子载波RU支持的最大传 输速率记为B106*1；相关WiFi6设备MU-MIMO空分复用支持的最大空间流数量为MAXMIMODenote the total number of communication services as M, and denote communication services as SVC={SVC1 , SVC2 ,..., SVCM }; communication service type V={V1 , V2 ,...,VM }, transmission The rate requirement is denoted asR ={ R1 , R2 , . The maximum number of spatial streams supported is MAXMIMO
2.2)初始化分组信息2.2) Initialize grouping information
通信业务组的数量记为X，初始时X＝0，所有通信业务均未加入业务组；The number of communication service groups is denoted as X, initially X=0, and all communication services are not added to the service group;
2.3)新建通信业务组GX2.3) New communication service group GX
随机选择一个没有加入通信业务组的通信业务，其业务类型为Vk，k是随机选择的通信 业务对应编号，仅选择业务类型为Vk的通信业务加入，以NMIMO表示该业务组中通信业务对应 MIMO空间流数，NMIMO初始值是0；Randomly select a communication service that does not join the communication service group, its service type is Vk , k is the corresponding number of the randomly selected communication service, only select the communication service whose service type is Vk to join, and use NMIMO to represent the communication in this service group The service corresponds to the number of MIMO spatial streams, and the initial value of NMIMO is 0;
2.4)遍历所有通信业务，当第i个通信业务满足Vi＝Vk且
当满足NMIMO＝MAXMIMO和业务序列遍历完毕的两个条件中任一时，GX不再加入新通信业务； 若此时所有通信业务均已加入通信业务组，所述通信业务组划分结束，此时X的取值即为通 信业务组的数量；否则，重复步骤2.3)。When either of the two conditions of NMIMO = MAXMIMO and the traversal of the service sequence is completed,GX no longer joins new communication services; if all communication services have been added to the communication service group at this time, the division of the communication service group ends, At this time, the value of X is the number of communication service groups; otherwise, repeat step 2.3).
进一步，所述步骤3)中，Further, in the step 3),
3.1)按照下式(2)计算各通信业务的保护带宽3.1) Calculate the protection bandwidth of each communication service according to the following formula (2)
式(2)中，RUband是RU对应子信道的带宽，σService是各类型通信业务的保护带宽参数，
3.2)根据计算得到的各类通信业务对应的保护带宽，与IEEE标准中规定的106子载波 RU在频谱上的位置，在不同类别通信业务保护带宽的约束下进行频谱上的RU资源分配；3.2) According to the guard bandwidths corresponding to various communication services obtained by calculation, and the positions of the 106 subcarrier RUs specified in the IEEE standard on the frequency spectrum, the RU resource allocation on the frequency spectrum is carried out under the constraints of the guard bandwidths of different types of communication services;
RU在频谱上与最近的另一个RU的距离为DR＝{DR1，DR2，...，DRY}，Y为当前工作带宽下106 子载波的数量，当GVx＜DRy时，RUy是满足通信业务组Gx的保护带宽，通信业务组Gx可以获 得RUy；The distance between the RU and the nearest RU in the spectrumisDR= {DR1 , DR2 , . RUy is the protection bandwidth that satisfies the communication service group Gx , and the communication service group Gx can obtain RUy ;
资源分配目标函数如下式(3)，The resource allocation objective function is as follows (3),
RU与通信业务组的匹配关系记为GR＝{GR1，GR2，...，GRX}，当业务组Gx得到RUy时，GRx＝RUy， 否则GRx＝Null；GL为业务组对应的隔离因子，用于反映业务组的资源获取优先级，业务组 对应GL的取值为“σService*业务组中业务的数量”；The matching relationship between the RU and the communication service group is denoted as GR={GR1 , GR2 , ..., GRX }, when the service group Gx obtains RUy , GRx =RUy , otherwise GRx =Null; is the isolation factor corresponding to the business group, which is used to reflect the resource acquisition priority of the business group, and the value of the GL corresponding to the business group is "σService * the number of services in the business group";
将RU分配抽象为赋权二分图匹配，二分图的两个点集分别为G＝{G1，G2，...，GX}和RU＝{RU1，RU2，...，RUY}，当GVx＜DRy时，Gx和RUy之间存在带权边E(Gx，RUy)，权值为Gx对应的隔离因子GLx；The RU assignment is abstracted as weighted bipartite graph matching, and the two point sets of the bipartite graph are G={G1 , G2 ,..., GX } and RU={RU1 , RU2 ,..., RUY }, when GVx <DRy , there is a weighted edge E(Gx , RUy ) between Gx and RUy , and the weight is the isolation factor GLx corresponding to G x;
向二分图添加“虚边”与“虚点”，向点数较少的点集中添加“虚点”，以使两个点集中 点的数量相同，向两个点集中不相连的点之间添加“虚边”，其权值为0，将该图改造为完全 二分图，对改造后的赋权二分图采用KM算法进行求解，算法输出的边集Match；Add "imaginary edges" and "imaginary points" to the bipartite graph, add "imaginary points" to the point set with fewer points, so that the number of points in the two point sets is the same, and add points between the two point sets that are not connected "Virtual edge", whose weight is 0, transforms the graph into a complete bipartite graph, uses the KM algorithm to solve the transformed weighted bipartite graph, and outputs the edge set Match;
删除添加的“虚点”及其对应边，由边集Match可得业务组与RU的匹配关系，目标函数 得到最优解。Delete the added "virtual point" and its corresponding edge, the matching relationship between the business group and the RU can be obtained from the edge set Match, and the objective function can obtain the optimal solution.
进一步，所述步骤4)中，当各业务组分配RU资源后，WiFi6通过MU-MIMO技术对各业务组得到的RU资源进行空分复用，得到多个空域上的空间流，这些空间流在业务组内部分配； 在确定各通信业务与MIMO空间流的对应关系后，测量出每根天线到每个终端的信道特征，然 后根据每个终端的信道特征，将要发送的数据进行预编码计算，将预编码后信号在每根天线 上发出，使不同通信业务在不同空间路径传输，实现业务组内部各通信业务之间的隔离。Further, in the step 4), after each service group allocates RU resources, WiFi6 performs space division multiplexing on the RU resources obtained by each service group through MU-MIMO technology to obtain multiple spatial streams in the spatial domain. Allocate within the service group; after determining the correspondence between each communication service and the MIMO spatial stream, measure the channel characteristics from each antenna to each terminal, and then perform precoding calculation on the data to be sent according to the channel characteristics of each terminal , the precoded signal is sent out on each antenna, so that different communication services are transmitted in different spatial paths, and the isolation between communication services within the service group is realized.
本发明的有益效果是：首先，设计了地下管廊通信多业务隔离架构，考虑了WiFi6的通 信特征与不同通信业务的隔离需求，设计了一种三层架构；其次，在业务层根据业务信息实 现通信分组；之后，在频域层计算不同业务组对应的保护带宽需求，并基于保护带宽的要求 和频谱资源的限制，通过改进KM算法实现隔离资源分配；最后，在空域层通过WiFi6多天线 的特点，在业务组内部进行空间流资源的分配，在空域上实现业务组内部通信业务的隔离。 本发明的方案结合WiFi6中OFDMA和MU-MIMO两种多用户技术，在频域和空域两个层次设计 了业务隔离机制，满足地下管廊通信多业务隔离的同时降低建设成本。The beneficial effects of the invention are as follows: firstly, a multi-service isolation architecture for underground pipe gallery communication is designed, and a three-layer architecture is designed in consideration of the communication characteristics of WiFi6 and the isolation requirements of different communication services; Realize communication grouping; after that, calculate the protection bandwidth requirements corresponding to different service groups in the frequency domain layer, and implement isolation resource allocation by improving the KM algorithm based on the protection bandwidth requirements and spectrum resource constraints; finally, in the airspace layer through WiFi6 multi-antenna The characteristics of , the allocation of spatial stream resources is carried out within the business group, and the isolation of communication services within the business group is realized in the airspace. The scheme of the present invention combines the two multi-user technologies of OFDMA and MU-MIMO in WiFi6, and designs a service isolation mechanism at two levels of frequency domain and air domain, which meets the multi-service isolation of underground pipe gallery communication and reduces construction costs.
附图说明Description of drawings
下面结合附图对本发明的基于WiFi6的地下管廊多业务通信隔离方法作进一步说明。The method for isolating multi-service communication of underground pipe gallery based on WiFi6 of the present invention will be further described below with reference to the accompanying drawings.
图1是实施例的步骤KM算法对赋权二分图的求解结果Fig. 1 is the solution result of the step KM algorithm of the embodiment to the weighted bipartite graph
具体实施方式Detailed ways
实施例Example
本实施例的基于WiFi6的地下管廊多业务通信隔离方法选取某物联网作为测试网络，测 试网络包括1个AP(无线局域网中的多端口的转发器或集线器或交换机)与15个物联网终 端设备STA(连接到无线网络中的终端)，所有设备均支持8*8MU-MIMO，即在空域上支持8 个空间流，无线信道模型符合瑞利衰落；工作频段为2.4GHz工作带宽为40MHz，MCS值为9， 采用256QAM调制，码率为5/6，符号位长为8，Symbol Time为13.6us(帧间间隙GI为0.8us， 传输的基本时间为12.8us)、TXOP为5ms。此时，单空间流106子载波RU的理论传输速率为 (8*5/6*106*1)/(12.8+0.8)＝52Mbps，而实际情况下传输速率一般无法达到理论值，测试 中认为实际传输速率为理论传输速率的50％，即26Mbps。The WiFi6-based multi-service communication isolation method for an underground pipe gallery in this embodiment selects an Internet of Things as a test network, and the test network includes one AP (multi-port repeater or hub or switch in a wireless local area network) and 15 Internet of Things terminals Equipment STA (terminal connected to the wireless network), all equipment support 8*8MU-MIMO, that is, 8 spatial streams are supported in the airspace, and the wireless channel model conforms to Rayleigh fading; the working frequency band is 2.4GHz and the working bandwidth is 40MHz. The MCS value is 9, 256QAM modulation is adopted, the code rate is 5/6, the symbol bit length is 8, the Symbol Time is 13.6us (the inter-frame gap GI is 0.8us, and the basic transmission time is 12.8us), and the TXOP is 5ms. At this time, the theoretical transmission rate of a single spatial stream 106 sub-carriers RU is (8*5/6*106*1)/(12.8+0.8)=52Mbps, but in practice the transmission rate generally cannot reach the theoretical value. The actual transmission rate is 50% of the theoretical transmission rate, that is, 26Mbps.
参加测试的通信业务分有4类，相关信息如下表1所示，σService是四个类型通信业务的 各自保护带宽参数，与业务隔离强度正相关，用于计算通信业务保护带宽。There are four types of communication services participating in the test, and the relevant information is shown in Table 1 below. σService is the respective protection bandwidth parameter of the four types of communication services, which is positively related to the service isolation strength, and is used to calculate the protection bandwidth of communication services.
表1Table 1
本实施例的基于WiFi6的地下管廊多业务通信隔离方法执行步骤如下：The execution steps of the WiFi6-based multi-service communication isolation method for an underground pipe gallery in this embodiment are as follows:
1)构建包括业务层、频域层和空域层的通信架构；1) Construct a communication architecture including business layer, frequency domain layer and airspace layer;
2)在地下管廊通信业务终端将通信需求上报到WiFi6无线AP设备之后，先在业务层根 据业务信息将通信业务划分为多个通信业务组；具体是：2) After the communication demand is reported to the WiFi6 wireless AP device by the communication service terminal of the underground pipe gallery, the communication service is first divided into a plurality of communication service groups according to the service information at the service layer; specifically:
2.1)统计通信业务信息2.1) Statistical communication service information
AP统计STA的通信请求，测试中，15个物联网终端设备均提出了通信请求。The AP counts the communication requests of the STA. During the test, 15 IoT terminal devices all made communication requests.
此时，通信业务总数为M＝15，通信业务记为SVC＝{SVC1，SVC2，...，SVC15}；At this time, the total number of communication services is M=15, and the communication services are denoted as SVC={SVC1 , SVC2 , . . . , SVC15 };
通信业务类型V＝{V1，V2，...，V15}＝{a，a，a，a，a，b，b，b，b，b，c，c，c，d，d}；Communication service type V={V1 , V2 , . . . , V15 }={a, a, a, a, a, b, b, b, b, b, c, c, c, d, d };
传输速率要求R＝{R1，R2，...，R15}＝{8,3,2,4,7,12,66,58,55,19,1,2,2,53,13}，单位Mbps；Transmission rate requirements R = {R1 , R2 , ..., R15 } = {8, 3, 2, 4, 7, 12, 66, 58, 55, 19, 1, 2, 2, 53, 13 }, in Mbps;
单空间流106子载波RU支持的最大传输速率B106*1＝26Mbps；相关WiFi6设备MU-MIMO 空分复用支持的最大空间流数量为8。The maximum transmission rate B106*1 =26 Mbps supported by a single spatial stream 106 subcarriers RU; the maximum number of spatial streams supported by the MU-MIMO spatial division multiplexing of the related WiFi6 device is 8.
AP根据通信业务类型及WiFi6支持的空间流数量限制进行分组，将通信业务划分为若干 个通信业务组。APs are grouped according to the type of communication service and the number of spatial streams supported by WiFi6, and the communication service is divided into several communication service groups.
2.2)初始化分组信息2.2) Initialize grouping information
通信业务组的数量记为X，初始时X＝0，所有通信业务均未加入通信业务组。The number of communication service groups is denoted as X, and initially X=0, and all communication services are not added to the communication service group.
2.3)新建通信业务组GX2.3) Create a new communication service groupGX
随机选择一个没有加入业务组的通信业务，其通信业务类型为Vk(k为随机选择的通信业 务对应编号)，GX仅选择业务类型为Vk的业务加入。以NMIMO表示该业务组中通信业务对应MIMO 空间流数，NMIMO初始值是0。Randomly select a communication service that has not been added to the service group, and its communication service type is Vk (k is the corresponding number of the randomly selected communication service), andGX only selects the service whose service type isVk to join. The number of MIMO spatial streams corresponding to the communication service in the service group is represented byNMIMO , and the initial value of NMIMO is 0.
2.4)遍历通信业务，当第i个通信业务满足“Vi＝Vk”且
将15个STA的通信业务的相关参数代入的过程具体如下：The process of substituting the relevant parameters of the communication services of the 15 STAs is as follows:
步骤2.2)Step 2.2)
初始时，X＝0，所有通信业务均未加入通信业务组。Initially, X=0, and all communication services are not added to the communication service group.
步骤2.3)Step 2.3)
新建通信业务组G1，随机选择一个通信业务，如选择得到SVC7。因为V7＝b,通信业务组G1仅选择通信业务类型为b的业务，NMIMO＝0。Create a new communication service group G1 , and randomly select a communication service, for example, to obtain SVC7 . Because V7 =b, the communication service group G1 only selects the service whose communication service type is b, and NMIMO =0.
步骤2.4)Step 2.4)
遍历通信业务，通信业务组G1依次加入SVC6，SVC7，SVC8，SVC10。在加入SVC10后，满足“NMIMO＝8”。此时，仍有通信业务没有加入通信业务组。Traversing the communication services, the communication service group G1 joins SVC6 , SVC7 , SVC8 , and SVC10 in sequence. After joining the SVC10 , "NMIMO = 8" is satisfied. At this time, there are still communication services that have not joined the communication service group.
重复步骤2.3)Repeat step 2.3)
新建通信业务组G2，随机选择一个通信业务，如选择得到SVC4。因为V4＝a,G2仅选择通信 业务类型为a的业务，NMIMO＝0。A new communication service group G2 is created, and a communication service is randomly selected, for example, an SVC4 is obtained by selection. Because V4 =a, G2 only selects the service whose communication service type is a, and NMIMO =0.
重复步骤2.4)Repeat step 2.4)
遍历通信业务，通信业务组G2依次加入SVC1，SVC2，SVC3，SVC4，SVC5。当遍历SVC15后，满足“业务序列遍历完毕”。此时，仍有通信业务没有加入通信业务组。Traversing the communication services, the communication service group G2 joins SVC1 , SVC2 , SVC3 , SVC4 , and SVC5 in sequence. After traversing the SVC15 , "traversal of the business sequence is completed" is satisfied. At this time, there are still communication services that have not joined the communication service group.
重复步骤2.3)Repeat step 2.3)
新建通信业务组G3，随机选择一个通信业务，如选择得到SVC9。因为V9＝b,G3仅选择通信 业务类型为b的业务，NMIMO＝0。进入Step3。A new communication service group G3 is created, and a communication service is randomly selected, for example, an SVC9 is obtained by selection. Because V9 =b, G3 only selects the service whose communication service type is b, and NMIMO =0. Enter Step3.
重复步骤2.4)Repeat step 2.4)
遍历通信业务，通信业务组G3加入SVC9。当遍历SVC15后，满足“业务序列遍历完毕”。此 时，仍有通信业务没有加入业务组。Traversing the communication service, the communication service group G3 joins the SVC9 . After traversing the SVC15 , "traversal of the business sequence is completed" is satisfied. At this time, there are still communication services that have not joined the service group.
重复步骤2.3)Repeat step 2.3)
新建通信业务组G4，随机选择一个通信业务，如选择得到SVC12。因为V12＝c,G4仅选择通 信业务类型为c的业务，NMIMO＝0。A new communication service group G4 is created, and a communication service is randomly selected, for example, an SVC12 is obtained by selection. Because V12 =c, G4 only selects the service whose communication service type is c, and NMIMO =0.
重复步骤2.4)Repeat step 2.4)
遍历通信业务，通信业务组G4依次加入SVC11，SVC12，SVC13。当遍历SVC15后，满足“业务 序列遍历完毕”。此时，仍有通信业务没有加入通信业务组。Traversing the communication services, the communication service group G4 joins SVC11 , SVC12 , and SVC13 in sequence. After traversing the SVC15 , "traversal of the business sequence is completed" is satisfied. At this time, there are still communication services that have not joined the communication service group.
重复步骤2.3)Repeat step 2.3)
新建通信业务组G5，随机选择一个通信业务，如选择得到SVC15。因为V15＝d,G3仅选择通 信业务类型为d的业务，NMIMO＝0。A new communication service group G5 is created, and a communication service is randomly selected, for example, an SVC15 is obtained by selection. Because V15 =d, G3 only selects the service whose communication service type is d, and NMIMO=0.
重复步骤2.4)Repeat step 2.4)
遍历通信业务，通信业务组G5依次加入SVC14，SVC15。当SVC15加入G5后，满足“业务序列 遍历完毕”。此时，所有通信业务均加入各通信业务组，分组结束。Traversing the communication services, the communication service group G5 joins the SVC14 and the SVC15 in sequence. When the SVC15 joins the G5 , "traversal of the service sequence is completed" is satisfied. At this time, all communication services are added to each communication service group, and the grouping ends.
通过上述分组方式，最终得到通信业务组的数量X＝5，即有5个通信业务组，记为G＝{G1，G2，G3，G4，G5}，G1＝{SVC6，SVC7，SVC8，SVC9，SVC10}，G2＝{SVC1，SVC2，SVC3，SVC4，SVC5，}， G3＝{SVC9}，G4＝{SVC11，SVC12，SVC13}，G5＝{SVC14，SVC15}。Through the above grouping method, the number of communication service groups X=5 is finally obtained, that is, there are 5 communication service groups, denoted as G={G1 , G2 , G3 , G4 , G5 }, G1 ={SVC6 , SVC7 , SVC8 , SVC9 , SVC10 }, G2 = {SVC1 , SVC2 , SVC3 , SVC4 , SVC5 , }, G3 = {SVC9 }, G4 = {SVC11 , SVC12 , SVC13 }, G5 ={SVC14 , SVC15 }.
3)在频域层，通过WiFi6的OFDMA将通信工作带宽划分为若干个RU，对5个通信业务组分配RU资源。3) In the frequency domain layer, the communication working bandwidth is divided into several RUs through OFDMA of WiFi6, and RU resources are allocated to 5 communication service groups.
3.1)按照下式(2)计算各通信业务的保护带宽，由于每个通信业务组仅包含单类业务， 通信业务组的保护带宽与其包含的通信业务的保护带宽一致。3.1) Calculate the protection bandwidth of each communication service according to the following formula (2). Since each communication service group contains only a single type of service, the protection bandwidth of the communication service group is consistent with the protection bandwidth of the communication service it contains.
式(2)中，RUband为RU对应子信道的带宽，σService为四类型通信业务的保护带宽参数，
表2Table 2
此时,RUband取值＝106*78.125KHz≈8.28MHz，，四类通信业务的σService取值分别为0.1， 0.4，0.7，1.0。At this time, the value of RUband=106*78.125KHz≈8.28MHz, and the values of σService of the four types of communication services are 0.1, 0.4, 0.7, and 1.0, respectively.
将RUband，σService带入公式(2)，计算得到基础数据采集类业务的保护带宽为131.5KHz。 同样的，视频图像类业务的保护带宽为526KHz，语音通话类业务的保护带宽为920.5KHz， 紧急类业务的保护带宽为1315KHz。Bringing RUband and σService into formula (2), it is calculated that the protection bandwidth of basic data collection services is 131.5KHz. Similarly, the protection bandwidth of video and image services is 526KHz, the protection bandwidth of voice call services is 920.5KHz, and the protection bandwidth of emergency services is 1315KHz.
由IEEE Std 802.11ax-2021(IEEESTD.2021.9442429)标准可得，在40MHz工作带宽下， 存在4个106子载波RU，当它们均进行数据传输时，它们与相邻RU的最小频谱距离分别为 2187.5KHz、546.875KHz、546.875KHz、2187.5KHz。According to the IEEE Std 802.11ax-2021 (IEEE STD.2021.9442429) standard, there are 4 RUs with 106 sub-carriers under the working bandwidth of 40MHz. When they all carry out data transmission, the minimum spectral distances between them and adjacent RUs are 2187.5 KHz, 546.875KHz, 546.875KHz, 2187.5KHz.
3.2)根据计算得到的各类通信业务对应的保护带宽，与IEEE标准中规定的106子载波 RU在频谱上的位置，在不同类别通信业务保护带宽的约束下进行频谱上的RU资源分配；3.2) According to the guard bandwidths corresponding to various communication services obtained by calculation, and the positions of the 106 subcarrier RUs specified in the IEEE standard on the frequency spectrum, the RU resource allocation on the frequency spectrum is carried out under the constraints of the guard bandwidths of different types of communication services;
此时，5个业务组对应的保护带宽要求分别是：At this time, the protection bandwidth requirements corresponding to the five service groups are:
GV＝{GV1，GV2，GV3，GV4，GV5}＝{526，131.5，526，920.5，1315}；GV={GV1 , GV2 , GV3 , GV4 , GV5 }={526, 131.5, 526, 920.5, 1315};
RU在频谱上与最近的另一个RU的距离是The spectral distance of a RU to the nearest other RU is
DR＝{DR1，DR2，DR3，DR4}＝{2187.5，546.875，546.875，2187.5}，GV和DR的单位均为KHz(千赫 兹。DR={DR1 , DR2 , DR3 , DR4 }={2187.5, 546.875, 546.875, 2187.5}, and the units of GV and DR are both KHz (KHz).
当GVx＜DRy时，RUy满足业务组x的隔离强度，Gx可以获得RUy；其中，RU1和RU4能 满足4类通信业务的频域隔离强度(即保护带宽)，RU2和RU3能满足“基础数据采集类”和“视 频图像类”业务的频域隔离强度(即保护带宽)。When GVx < DRy , RUy satisfies the isolation strength of service group x, and Gx can obtain RUy ; where RU1 and RU4 can satisfy the frequency-domain isolation strength (ie, protection bandwidth) of four types of communication services, RU2 and RU3 can meet the frequency domain isolation strength (ie protection bandwidth) of "basic data collection" and "video image" services.
除保护带宽的约束外，引入隔离因子GL来反映业务组的资源获取优先级。方案倾向于“通 信业务数量多”且“保护带宽大”的业务组优先得到RU资源，业务组对应GL的取值为“σService* 业务组中业务的数量”，σService为业务组中通信业务对应的保护带宽参数。In addition to the constraint of protection bandwidth, the isolation factor GL is introduced to reflect the resource acquisition priority of the service group. The solution tends to favor the service group with "large number of communication services" and "large protection bandwidth" to obtain RU resources first. The value of GL corresponding to the service group is "σService * the number of services in the service group", and σService is the communication in the service group. The protection bandwidth parameter corresponding to the service.
G1对应的GL1＝σb*4＝0.4*4＝1.6，G2对应的GL2＝σa*5＝0.1*5＝0.5。类似的， 计算得到GL＝{GL1，GL2，GL3，GL4，GL5}＝{1.6，0.5，0.4，2.1，2.0}。GL1 corresponding to G1 =σb*4=0.4*4=1.6, and GL2 corresponding to G2 =σa *5=0.1*5=0.5. Similarly, GL={GL1 , GL2 , GL3 , GL4 , GL5 }={1.6, 0.5, 0.4, 2.1, 2.0} is calculated.
资源分配目标函数如下式(3)，The resource allocation objective function is as follows (3),
RU与业务组的匹配关系记为GR＝{GR1，GR2，GR3，GR4，GR5}，当业务组Gx得到RUy时，GRx＝RUy，否则GRx＝Null。The matching relationship between the RU and the service group is denoted as GR={GR1 , GR2 , GR3 , GR4 , GR5 }, when the service group Gx obtains RUy , GRx =RUy , otherwise GRx =Null.
将RU分配问题抽象为赋权二分图匹配问题。二分图的两个点集分别为 G＝{G1，G2，G3，G4，G5}和RU＝{RU1，RU2，RU3，RU4}。当GVx＜DRy时，Gx和RUy之间存在带权 边E(Gx，RUy)，权值为Gx对应的隔离因子GLx。该问题采用Kuhn-Munkres(KM)算法求解，由 于KM算法用于求解完备匹配下的最大权问题，而该问题最终求解结果不必是完备匹配，对该 问题对应的赋权二分图进行改造。具体的，向二分图添加“虚边”与“虚点”，向点数较少的 点集中添加“虚点”，以使两个点集中点的数量相同，向两个点集中不相连的点之间添加“虚 边”，其权值为0，将该图改造为完全二分图。本实例中，向RU＝{RU1，RU2，RU3，RU4}点集中 添加RU5作为“虚点”。对改造后的赋权二分图采用KM算法进行求解，算法输出的边集Match 为{E(G1,RU2),E(G2,RU3),E(G3,RU5),E(G4,RU1),E(G5,RU4)}。图1是KM算法对赋权二 分图的求解结果。Abstract the RU assignment problem as a weighted bipartite graph matching problem. The two point sets of the bipartite graph are G={G1 , G2 , G3 , G4 , G5 } and RU={RU1 , RU2 , RU3 , RU4 } respectively. When GVx <DRy , a weighted edge E(Gx , RUy ) exists between Gx and RUy , and the weight is the isolation factor GLx corresponding to G x. This problem is solved by the Kuhn-Munkres (KM) algorithm. Since the KM algorithm is used to solve the maximum weight problem under complete matching, and the final solution result of this problem does not have to be complete matching, the weighted bipartite graph corresponding to the problem is transformed. Specifically, "imaginary edges" and "imaginary points" are added to the bipartite graph, and "imaginary points" are added to the point set with a smaller number of points, so that the number of points in the two point sets is the same, and the points that are not connected to the two point sets are added. Add a "virtual edge" between them with a weight of 0, and transform the graph into a complete bipartite graph. In this example, RU5 is added as a "virtual point" to the point setof RU={ RU1, RU2, RU3,RU4 }. The KM algorithm is used to solve the transformed weighted bipartite graph. The edge set Match output by the algorithm is {E(G1,RU2),E(G2,RU3),E(G3,RU5),E(G4,RU1), E(G5,RU4)}. Figure 1 is the solution result of the KM algorithm for the weighted bipartite graph.
删除添加的“虚点”RU5及其对应边，由边集Match可得，业务组与RU的匹配关系 GR＝{GR1＝RU2，GR2＝RU3，GR3＝null，GR4＝RU1，GR5＝RU4}。此时，f(GR)＝6.2，目 标函数得到最优解。Delete the added "virtual point" RU5 and its corresponding edge, which can be obtained from the edge set Match. The matching relationship between the service group and RU is GR={GR1 =RU2, GR2 =RU3, GR3 =null, GR4 =RU1, GR5 =RU4}. At this time, f(GR)=6.2, the objective function obtains the optimal solution.
4)在空域层，通过MU-MIMO对信道资源进行空分复用，5个通信业务组获得RU之后，在通 信业务组内部的通信业务之间分配多天线多空间流资源，不同通信业务由不同空间流承载， 不同空间流在不同空间路径传输。4) In the spatial layer, the channel resources are space-division multiplexed through MU-MIMO. After the 5 communication service groups obtain RU, the multi-antenna and multi-spatial stream resources are allocated among the communication services within the communication service group. Different spatial streams are carried, and different spatial streams are transmitted in different spatial paths.
当5个通信业务组得到RU资源后，WiFi6通过MU-MIMO技术对业务组得到的RU资源进 行空分复用，得到多个空域上的空间流，因为实例中所有相关设备均支持8*8MU-MIMO，每 个RU对应的空间流数量均为8，这些空间流在业务组内部分配。After 5 communication service groups obtain RU resources, WiFi6 uses MU-MIMO technology to perform space division multiplexing on the RU resources obtained by the service groups to obtain spatial streams in multiple airspaces, because all related devices in the example support 8*8MU -MIMO, the number of spatial streams corresponding to each RU is 8, and these spatial streams are allocated within the service group.
通信业务根据其传输速率要求Ri获得
表3table 3
在确定5个通信业务组中的15个通信业务与MIMO空间流的对应关系后，AP测量出每根 天线到每个终端的信道特征，然后AP根据信道特征，将要发送的数据进行预编码计算，将预 编码后信号在每根天线上发出，使不同通信业务在不同空间路径传输以实现业务组内部业务 之间的隔离。After determining the correspondence between the 15 communication services in the 5 communication service groups and the MIMO spatial stream, the AP measures the channel characteristics from each antenna to each terminal, and then the AP calculates the precoding of the data to be sent according to the channel characteristics. , the precoded signal is sent out on each antenna, so that different communication services are transmitted in different spatial paths to achieve isolation between services within the service group.
以上所述仅为本发明的较佳实施例而已，但本发明并不局限于此，所有根据本发明的构 思及其技术方案加以等同替换或等同改变均应涵盖在本发明的保护范围之内。The above are only preferred embodiments of the present invention, but the present invention is not limited thereto, and all equivalent replacements or equivalent changes based on the concept and technical solutions of the present invention shall be included within the protection scope of the present invention .
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