pandas.Series.abs#

Series.abs()[source]#

Return a Series/DataFrame with absolute numeric value of each element.

This function only applies to elements that are all numeric.

Returns:

abs

Series/DataFrame containing the absolute value of each element.

See also

numpy.absolute

Calculate the absolute value element-wise.

Notes

Forcomplex inputs,1.2+1j, the absolute value is\(\sqrt{ a^2 + b^2 }\).

Examples

Absolute numeric values in a Series.

>>>s=pd.Series([-1.10,2,-3.33,4])>>>s.abs()0    1.101    2.002    3.333    4.00dtype: float64

Absolute numeric values in a Series with complex numbers.

>>>s=pd.Series([1.2+1j])>>>s.abs()0    1.56205dtype: float64

Absolute numeric values in a Series with a Timedelta element.

>>>s=pd.Series([pd.Timedelta('1 days')])>>>s.abs()0   1 daysdtype: timedelta64[ns]

Select rows with data closest to certain value using argsort (fromStackOverflow).

>>>df=pd.DataFrame({...'a':[4,5,6,7],...'b':[10,20,30,40],...'c':[100,50,-30,-50]...})>>>df     a    b    c0    4   10  1001    5   20   502    6   30  -303    7   40  -50>>>df.loc[(df.c-43).abs().argsort()]     a    b    c1    5   20   500    4   10  1002    6   30  -303    7   40  -50