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Pre-Image


Letf:A->B be a map between setsA andB. LetY subset= B. Then the preimage ofY underf is denoted byf^(-1)(Y), and is the set of all elements ofA that map to elements inY underf. Thus

 f^(-1)(Y)={a in A|f(a) in Y}.
(1)

One is not to be mislead by the notation into thinking of the preimage as having to do with an inverse off. The preimage is defined whetherf has an inverse or not. Note however that iff does have an inverse, then the preimagef^(-1)(Y) is exactly theimage ofY under the inverse map, thus justifying the perhaps slightly misleading notation.

For anyY subset= B, it is true that

 f(f^(-1)(Y)) subset= Y,
(2)

with equality occurring, iff is surjective, and for any subsetX subset= A, it is true that

 X subset= f^(-1)(f(X)),
(3)

with equality occurring iff is injective.

Preimages occur in a variety of subjects, the most persistent of these being topology, where a map is continuous, by definition, if the preimage of every open set is open.


See also

Image

This entry contributed byRasmusHedegaard

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Cite this as:

Hedegaard, Rasmus. "Pre-Image." FromMathWorld--A Wolfram Resource, created byEric W. Weisstein.https://mathworld.wolfram.com/Pre-Image.html

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Created, developed and nurtured by Eric Weisstein at Wolfram Research

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