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How best to write this if-else?

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From: Mick <vsl6 at paradise.net.nz>> for i in all:>     ma = i[0].match(str)>     if ma:>         i[1](ma)>for r,f in all:    ma = r.mach(str)    if ma:        f(ma)ly-y'rs-gzeljko>> Mick>>> -----Original Message-----> From:python-list-admin at python.org> [mailto:python-list-admin at python.org]On Behalf Of Roy Smith> Sent: Sunday, April 22, 2001 9:02 AM> To:python-list at python.org> Subject: Re: How best to write this if-else?>>> "Ingo Wilken" <Ingo.Wilken at Informatik.Uni-Oldenburg.DE> wrote:> > for e in [e1, e2, e3]:> >     m = e.match(line)> >     if m:> >         text = m.group(1)> >         break> > else:> >     no match found>> OK, that's pretty neat, but I realize now that my example was> unintentionally misleading.  The problem is not quite as regular as I made> it out to be.>> What if I want to execute different code depending on which expression I> matched?  Something along the lines of (pseudocode):>> if (m = e1.match(line)):>    text1 = m.group(1)>    do_complicated_processing (text1)> elif (m = e2.match(line)):>    text1 = m.group(1)>    text2 = m.group(2)>    print text1, text2> elif (m = e3.match(line)):>    return> -->http://mail.python.org/mailman/listinfo/python-list>>> -->http://mail.python.org/mailman/listinfo/python-list>

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