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Formatting RFC 822 date
Barry A. Warsawbarry at digicool.com
Wed Apr 4 17:25:16 EDT 2001
>>>>> "MDC" == Matthew Dixon Cowles <matt at mondoinfo.com> writes: >> Is there a module that I'm missing that will take a time tuple >> and output the proper RFC 822 date string? MDC> I'll append what I do in Swallow. I think it's right.How about rfc822.formatdate()? :)>>> import time>>> import rfc822>>> rfc822.formatdate()'Wed, 04 Apr 2001 21:23:07 GMT'>>> rfc822.formatdate(time.time() - 3600)'Wed, 04 Apr 2001 20:23:23 GMT'Okay, so it takes a time float, but you can easy convert a time tupleto a time float via time.mktime().Cheers,-Barry
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