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General Decision Menu (Basketball, Programming Lnag. gerneral etcetc
Ron Stephensrdsteph at earthlink.net
Fri Apr 13 23:31:05 EDT 2001
I guess i better stop posting these long spaghetti code things, but thisis the first pass at a menu based general decision analysis thing...ithas four parts, one is general any question, two is programming languagechoosier expert system , tow is scripting language chooser, four is abasketball predictor expert sysstem...does anyone know of any Pythonexpert system type of programs I could look at are??? I am interested inany artificial intelligence Python programs or Expert System Pythonprograms...anyway...this program runs fine under Python Win but fails under IDLEfor unknown reasons..."Tcl error expected boolean got??" after I give itthe first answer to the first prompt...Decision_Analysis_Beta3.pyprint "A program to help you make decisions."printprintdef decisionanalysis(): # This code is placed in the public domain def get_list(heading, prompt): print heading print print "(enter a blank line to end the list)" ret = [] i = 1 while 1: line = raw_input(prompt % i) if not line: break ret.append(line) i=i+1 print return ret def get_number(prompt): res = None while res is None: try: res = float(raw_input(prompt)) except ValueError: pass return res # First, ask the user to enter the lists options = get_list("Enter your options", "Option %d: ") criteria = get_list("Enter your criteria ...", "Criterion %d: ") # Next, get the user to rank his criteria. I use a system wherehigher # is better, so that an undesirable characteristic can be given anegative # weight. # # {} is a dictionary, it can be indexed by (nearly) any expression, # and we will index it with the names of the criteria. # number of the criterion) rankings = {} print print "Enter relative importance of criteria (higher is moreimportant)" print for c in criteria: rankings[c] = get_number("Criterion %s: " % c) # Next, get the user to score each option on all the criteria. # Here, we index the dictionary on the pair (option, criterion). # This is similar to a two-dimensional array in other languages score = {} print print "Enter score for each option on each criterion" print for o in options: print print "Scores for option %s" % o print for c in criteria: score[o, c] = get_number("Criterion %s: " % c) # Calculate the resulting score for each option. This equation # is different from Rod Stephen's original program, because I # make more important criteria have higher rankings, and even let # bad criteria have negative rankings. # The "result" dictionary is indexed with the names of the options. result = {} for o in options: value = 0 for c in criteria: print o, c, rankings[c], score[o, c] value = value + rankings[c] * score[o, c] result[o] = value # Now, I want to take the dictionary result, and turn it into aranked list results = result.items() # A list of tuples (key, value) results.sort(lambda x, y: -cmp(x[1], y[1])) # Sort the list using the reverse of the # "value" of the entry, so that higher # values come first print print "Results, in order from highest to lowest score" print print "%5s %s" % ("Score", "Option") # Take the pairs out of results in order, and print them out for option, result in results: print "%5s %s" % (result, option)def ProgramLanguageFinal(): print "This is a program to help give you an idea which programminglanguages you should consider learning. While there are any number oflanguages you might consider, this program considrs only 11 of teh mostpopluar ones. The program will ask you to input a ranking or weightingfor a number of criteria that may be of importance in choosing your nextprogramming language." def get_list(heading, prompt): print heading print print "(enter a blank line to end the list)" ret = [] i = 1 while 1: line = raw_input(prompt % i) if not line: break ret.append(line) i=i+1 print return ret def get_number(prompt): """ get_number(prompt) -> float This function prompts for a number. If the user enters bad input,such as "cat" or "3l", it will prompt again. """ res = None while res is None: try: res = float(raw_input(prompt)) except ValueError: pass return res options = ["Python", "Perl", "Ruby", "Tcl", "JavaScript", "VisualBasic", "Java", "C++", "C", "Lisp", "Delphi"] criteria = ["ease of learning", "ease of use", "speed of programexecution", "quality of available tools", "popularity", "power &expressiveness", "cross platform?", "cost"] rankings = {} print print "Enter relative importance of criteria (higher is moreimportant)" print for c in criteria: rankings[c] = get_number("Criterion %s: " % c) # Next, get the user to score each option on all the criteria. # Here, we index the dictionary on the pair (option, criterion). # This is similar to a two-dimensional array in other languages score = {("Python", "ease of learning"):100, ("Python", "ease ofuse"):100, ("Python", "speed of program execution"):10, ("Python","quality of available tools"):70, ("Python", "popularity"):50,("Python", "power & expressiveness"):100, ("Python", "crossplatform?"):100, ("Python", "cost"):100, ("Perl", "ease of learning"):50, ("Perl", "ease of use"):90,("Perl", "speed of program execution"):30, ("Perl", "quality ofavailable tools"):50, ("Perl", "popularity"):75, ("Perl", "power &expressiveness"):100, ("Perl", "cross platform?"):100, ("Perl","cost"):100, ("Ruby", "ease of learning"):50, ("Ruby", "ease of use"):100,("Ruby", "speed of program execution"):20, ("Ruby", "quality ofavailable tools"):20, ("Ruby", "popularity"):10, ("Ruby", "power &expressiveness"):100, ("Ruby", "cross platform?"):80, ("Ruby","cost"):100, ("Tcl", "ease of learning"):100, ("Tcl", "ease of use"):100, ("Tcl","speed of program execution"):10, ("Tcl", "quality of availabletools"):50, ("Tcl", "popularity"):40, ("Tcl", "power &expressiveness"):10, ("Tcl", "cross platform?"):100, ("Tcl","cost"):100, ("JavaScript", "ease of learning"):70, ("JavaScript", "ease ofuse"):75, ("JavaScript", "speed of program execution"):10,("JavaScript", "quality of available tools"):50, ("JavaScript","popularity"):100, ("JavaScript", "power & expressiveness"):40,("JavaScript", "cross platform?"):50, ("JavaScript", "cost"):100, ("Visual Basic", "ease of learning"):50, ("Visual Basic", "ease ofuse"):100, ("Visual Basic", "speed of program execution"):20, ("VisualBasic", "quality of available tools"):100, ("Visual Basic","popularity"):100, ("Visual Basic", "power & expressiveness"):50,("Visual Basic", "cross platform?"):1, ("Visual Basic", "cost"):1, ("Java", "ease of learning"):15, ("Java", "ease of use"):50,("Java", "speed of program execution"):50, ("Java", "quality ofavailable tools"):100, ("Java", "popularity"):100, ("Java", "power &expressiveness"):100, ("Java", "cross platform?"):100, ("Java","cost"):100, ("C++", "ease of learning"):10, ("C++", "ease of use"):25, ("C++","speed of program execution"):90, ("C++", "quality of availabletools"):100, ("C++", "popularity"):100, ("C++", "power &expressiveness"):100, ("C++", "cross platform?"):100, ("C++","cost"):100, ("C", "ease of learning"):15, ("C", "ease of use"):10, ("C", "speedof program execution"):100, ("C", "quality of available tools"):100,("C", "popularity"):100, ("C", "power & expressiveness"):100, ("C","cross platform?"):110, ("C", "cost"):100, ("Lisp", "ease of learning"):20, ("Lisp", "ease of use"):30,("Lisp", "speed of program execution"):70, ("Lisp", "quality ofavailable tools"):50, ("Lisp", "popularity"):25, ("Lisp", "power &expressiveness"):110, ("Lisp", "cross platform?"):80, ("Lisp","cost"):90, ("Delphi", "ease of learning"):50, ("Delphi", "ease of use"):110,("Delphi", "speed of program execution"):85, ("Delphi", "quality ofavailable tools"):100, ("Delphi", "popularity"):30, ("Delphi", "power &expressiveness"):100, ("Delphi", "cross platform?"):80, ("Delphi","cost"):10} # Calculate the resulting score for each option. # The "result" dictionary is indexed with the names of the options. result = {} for o in options: value = 0 for c in criteria: value = value + rankings[c] * score[o, c] result[o] = value # Now, I want to take the dictionary result, and turn it into aranked list results = result.items() # A list of tuples (key, value) results.sort(lambda x, y: -cmp(x[1], y[1])) # Sort the list using the reverse of the # "value" of the entry, so that higher # values come first print print "Results, in order from highest to lowest score" print print "%5s %s" % ("Score", "Option") # Take the pairs out of results in order, and print them out for option, result in results: print "%5s %s" % (result, option) def ProgramLanguageScript(): def get_list(heading, prompt): print heading print print "(enter a blank line to end the list)" ret = [] i = 1 while 1: line = raw_input(prompt % i) if not line: break ret.append(line) i=i+1 print return ret def get_number(prompt): res = None while res is None: try: res = float(raw_input(prompt)) except ValueError: pass return res # First, ask the user to enter the lists options = ["Python", "Perl", "Ruby", "Tcl", "JavaScript", "VisualBasic"] criteria = ["ease of learning", "ease of use", "speed of programexecution", "quality of available tools", "popularity", "power &expressiveness", "cross platform?", "cost"] # Next, get the user to rank his criteria. I use a system wherehigher # is better, so that an undesirable characteristic can be given anegative # weight. # # {} is a dictionary, it can be indexed by (nearly) any expression, # and we will index it with the names of the criteria. # (For a more traditional program, we could use a list and index bythe # number of the criterion) rankings = {} print print "Enter relative importance of criteria (higher is moreimportant)" print for c in criteria: rankings[c] = get_number("Criterion %s: " % c) # Next, get the user to score each option on all the criteria. # Here, we index the dictionary on the pair (option, criterion). # This is similar to a two-dimensional array in other languages score = {("Python", "ease of learning"):100, ("Python", "ease ofuse"):100, ("Python", "speed of program execution"):10, ("Python","quality of available tools"):50, ("Python", "popularity"):50,("Python", "power & expressiveness"):100, ("Python", "crossplatform?"):100, ("Python", "cost"):100, ("Perl", "ease of learning"):50, ("Perl", "ease of use"):90,("Perl", "speed of program execution"):30, ("Perl", "quality ofavailable tools"):50, ("Perl", "popularity"):75, ("Perl", "power &expressiveness"):100, ("Perl", "cross platform?"):100, ("Perl","cost"):100, ("Ruby", "ease of learning"):50, ("Ruby", "ease of use"):100,("Ruby", "speed of program execution"):10, ("Ruby", "quality ofavailable tools"):20, ("Ruby", "popularity"):10, ("Ruby", "power &expressiveness"):100, ("Ruby", "cross platform?"):80, ("Ruby","cost"):100, ("Tcl", "ease of learning"):100, ("Tcl", "ease of use"):100, ("Tcl","speed of program execution"):5, ("Tcl", "quality of availabletools"):50, ("Tcl", "popularity"):40, ("Tcl", "power &expressiveness"):10, ("Tcl", "cross platform?"):100, ("Tcl","cost"):100, ("JavaScript", "ease of learning"):70, ("JavaScript", "ease ofuse"):75, ("JavaScript", "speed of program execution"):10,("JavaScript", "quality of available tools"):50, ("JavaScript","popularity"):100, ("JavaScript", "power & expressiveness"):40,("JavaScript", "cross platform?"):50, ("JavaScript", "cost"):100, ("Visual Basic", "ease of learning"):50, ("Visual Basic", "ease ofuse"):100, ("Visual Basic", "speed of program execution"):20, ("VisualBasic", "quality of available tools"):100, ("Visual Basic","popularity"):100, ("Visual Basic", "power & expressiveness"):50,("Visual Basic", "cross platform?"):1, ("Visual Basic", "cost"):1} # Calculate the resulting score for each option. This equation # is different from Rod Stephen's original program, because I # make more important criteria have higher rankings, and even let # bad criteria have negative rankings. # The "result" dictionary is indexed with the names of the options. result = {} for o in options: value = 0 for c in criteria: print o, c, rankings[c], score[o, c] value = value + rankings[c] * score[o, c] result[o] = value # Now, I want to take the dictionary result, and turn it into aranked list results = result.items() # A list of tuples (key, value) results.sort(lambda x, y: -cmp(x[1], y[1])) # Sort the list using the reverse of the # "value" of the entry, so that higher # values come first print print "Results, in order from highest to lowest score" print print "%5s %s" % ("Score", "Option") # Take the pairs out of results in order, and print them out for option, result in results: print "%5s %s" % (result, option)def Basketball(): print "This is a program to help you decide which team will win abasketball game" print print "When prompted, enter a number ranking each team on theprompted team skill on a scle form 1 to 100, with 1 being terrible and100 being the best imaginable" print team_one = raw_input ("What is the name of team one:") team_two = raw_input ("What is the name of team two:") criteria = {"speed":100, "size":66, "jumping_ability":50,"defense":60, "shooting":75, "ballhandling":50, "rebounding":50} scoreonespeed = input ("rank the team speed of %s on a scale of 1 to100:" % team_one) scoretwospeed = input ("rank the team speed of %s on a scale of 1 to100:" % team_two) scoreonesize= input ("rank the team size of %s on scale of 1 to 100"% team_one) scoretwosize= input ("rank the team size of %s on scale of 1 to 100"% team_two) scoreonejumping_ability= input("rank the jumping ability of %s" %team_one) scoretwojumping_ability= input("rank the jumping ability of %s" %team_two) scoreonedefense = input ("ramk the defense of %s" % team_one) scoretwodefense = input ("ramk the defense of %s" % team_two) scoreoneshooting = input ("rank the shooting ability of %s" %team_one) scoretwoshooting = input ("rank the shooting ability of %s" %team_two) scoreoneballhandling= input("rank the ballhandling ability of %s:" %team_one) scoretwoballhandling= input("rank the ballhandling ability of %s:" %team_two) scoreonerebounding = input ("rank the rebounding ability of %s" %team_one) scoretworebounding = input ("rank the rebounding ability of %s" %team_two) scoreteamone = (criteria["speed"])*(scoreonespeed) +(criteria["size"])*(scoreonesize)+(criteria["jumping_ability"])*(scoreonejumping_ability)+(criteria["defense"])*(scoreonedefense) +(criteria["shooting"])*(scoreoneshooting)+(criteria["ballhandling"])*(scoreoneballhandling)+(criteria["rebounding"])*(scoreonerebounding) scoreteamtwo = (criteria["speed"])*(scoretwospeed) +(criteria["size"])*(scoretwosize)+(criteria["jumping_ability"])*(scoretwojumping_ability)+(criteria["defense"])*(scoretwodefense) +(criteria["shooting"])*(scoretwoshooting)+(criteria["ballhandling"])*(scoretwoballhandling)+(criteria["rebounding"])*(scoretworebounding) print "%s has a power ranking of %d" % (team_one, scoreteamone) print print "%s has a power ranking of %d" % (team_two, scoreteamtwo) if scoreteamone > scoreteamtwo: print "%s wins!!!" % team_one elif scoreteamone == scoreteamtwo: print "the two teams are a toss-up!!!" else: print "%s wins!!!" % team_twoprint "Please enter the number for the type of decision you wish toanalayze:"print "1. General Decision Analysis, you choose the options, criteria,etc."print "2. Help in Choosing Programming Language amongst 11 popularlanguages"print "3. Help in choosing scripting programming language amongst 6scripting languages"print "4. Which Basketball Team will win the Game???"while 1: # loop forever choice = input("Please type in the number of the type ofdecision-program you wish to run from above and hit enter:") if choice ==1: decisionanalysis() elif choice ==2: ProgramLanguageFinal() elif choice ==3: ProgramLanguageScript() elif choice ==4: Basketball() elif choice =="quit": break # exit from infinite loop else: print "Invalid operation"
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