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[Python-ideas] Pass a function as the argument "step" of range()

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2015-07-03 12:29 GMT+02:00 Andrew Barnert <abarnert at yahoo.com>:> On Jul 2, 2015, at 08:53, Pierre Quentel <pierre.quentel at gmail.com> wrote:> >> > It's true, but testing that an integer is a range is very rare : the> pattern "if X in range(Y)" is only found once in all the Python 3.4> standard library>> Given that most of the stdlib predates Python 3.2, and modules are rarely> rewritten to take advantage of new features just for the hell of it, this> isn't very surprising, or very meaningful.>Then most of the stdlib also predates Python 1.5.2 (the version I startedwith) :Python 1.5.2 (#0, Apr 13 1999, 10:51:12) [MSC 32 bit (Intel)] on win32Copyright 1991-1995 Stichting Mathematisch Centrum, Amsterdam>>> 4 in range(10)1>>>>> Similarly, you'll find that most of the stdlib doesn't use yield from> expressions, and many things that could be written in terms of> singledispatch instead use type switching, and so on. This doesn't mean> yield from or singledispatch are useless or rarely used.-------------- next part --------------An HTML attachment was scrubbed...URL: <http://mail.python.org/pipermail/python-ideas/attachments/20150705/8ae42918/attachment.html>

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