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[Python-Dev] partition() (was: Remove str.find in 3.0?)
Ron Adamrrr at ronadam.com
Tue Aug 30 21:37:18 CEST 2005
Phillip J. Eby wrote:> At 02:25 PM 8/30/2005 -0400, Raymond Hettinger wrote:>>> That case should be handled with consecutive partitions:>>>> # keep everything after the second 'X'>> head, found, s = s.partition('X')>> head, found, s = s.partition('x')I was thinking of cases where head is everything before the second 'X'.A posible use case might be getting items in comma delimited string.> Or:>> s=s.partition('X')[2].partition('X')[2]>> which actually suggests a shorter, clearer way to do it:>> s = s.after('X').after('X')>> And the corresponding 'before' method, of course, such that if sep in s:>> s.before(sep), sep, s.after(sep) == s.partition(sep)>> Technically, these should probably be before_first and after_first, with> the corresponding before_last and after_last corresponding to rpartition.Do you really think these are easer than: head, found, tail = s.partition('X',2)I don't feel there is a need to avoid numbers entirely. In this case Ithink it's the better way to find the n'th seperator and since it's anoptional value I feel it doesn't add a lot of complication. Anyway...It's just a suggestion.Cheers,Ron
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