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This article provides supplementary remarks to the reference documentation for this API.
TheGetHashCode method provides a hash code for algorithms that need quick checks of object equality. A hash code is a numeric value that is used to insert and identify an object in a hash-based collection, such as theDictionary<TKey,TValue> class, theHashtable class, or a type derived from theDictionaryBase class.
Note
For information about how hash codes are used in hash tables and for some additional hash code algorithms, see theHash Function entry in Wikipedia.
Two objects that are equal return hash codes that are equal. However, the reverse is not true: equal hash codes do not imply object equality, because different (unequal) objects can have identical hash codes. Furthermore, .NET does not guarantee the default implementation of theGetHashCode method, and the value this method returns may differ between .NET implementations, such as different versions of .NET Framework and .NET Core, and platforms, such as 32-bit and 64-bit platforms. For these reasons, do not use the default implementation of this method as a unique object identifier for hashing purposes. Two consequences follow from this:
Warning
A hash code is intended for efficient insertion and lookup in collections that are based on a hash table. A hash code is not a permanent value. For this reason:
TheGetHashCode method can be overridden by a derived type. IfGetHashCode is not overridden, hash codes for reference types are computed by calling theObject.GetHashCode method of the base class, which computes a hash code based on an object's reference; for more information, seeRuntimeHelpers.GetHashCode. In other words, two objects for which theReferenceEquals method returnstrue
have identical hash codes. If value types do not overrideGetHashCode, theValueType.GetHashCode method of the base class uses reflection to compute the hash code based on the values of the type's fields. In other words, value types whose fields have equal values have equal hash codes. For more information about overridingGetHashCode, see the "Notes to Inheritors" section.
Warning
If you override theGetHashCode method, you should also overrideEquals, and vice versa. If your overriddenEquals method returnstrue
when two objects are tested for equality, your overriddenGetHashCode method must return the same value for the two objects.
If an object that is used as a key in a hash table does not provide a useful implementation ofGetHashCode, you can specify a hash code provider by supplying anIEqualityComparer implementation to one of the overloads of theHashtable class constructor.
When you call theGetHashCode method on a class in the Windows Runtime, it provides the default behavior for classes that don't overrideGetHashCode. This is part of the support that .NET provides for the Windows Runtime (see.NET Support for Windows Store Apps and Windows Runtime). Classes in the Windows Runtime don't inheritObject, and currently don't implement aGetHashCode. However, they appear to haveToString,Equals(Object), andGetHashCode methods when you use them in your C# or Visual Basic code, and the .NET Framework provides the default behavior for these methods.
Note
Windows Runtime classes that are written in C# or Visual Basic can override theGetHashCode method.
One of the simplest ways to compute a hash code for a numeric value that has the same or a smaller range than theInt32 type is to simply return that value. The following example shows such an implementation for aNumber
structure.
using System;public struct Number{ private int n; public Number(int value) { n = value; } public int Value { get { return n; } } public override bool Equals(Object obj) { if (obj == null || ! (obj is Number)) return false; else return n == ((Number) obj).n; } public override int GetHashCode() { return n; } public override string ToString() { return n.ToString(); }}public class Example1{ public static void Main() { Random rnd = new Random(); for (int ctr = 0; ctr <= 9; ctr++) { int randomN = rnd.Next(Int32.MinValue, Int32.MaxValue); Number n = new Number(randomN); Console.WriteLine("n = {0,12}, hash code = {1,12}", n, n.GetHashCode()); } }}// The example displays output like the following:// n = -634398368, hash code = -634398368// n = 2136747730, hash code = 2136747730// n = -1973417279, hash code = -1973417279// n = 1101478715, hash code = 1101478715// n = 2078057429, hash code = 2078057429// n = -334489950, hash code = -334489950// n = -68958230, hash code = -68958230// n = -379951485, hash code = -379951485// n = -31553685, hash code = -31553685// n = 2105429592, hash code = 2105429592
open System[<Struct; CustomEquality; NoComparison>]type Number(value: int) = member _.Value = value override _.Equals(obj) = match obj with | :? Number as n -> n.Value = value | _ -> false override _.GetHashCode() = value override _.ToString() = string valuelet rnd = Random()for _ = 0 to 9 do let randomN = rnd.Next(Int32.MinValue, Int32.MaxValue) let n = Number randomN printfn $"n = {n,12}, hash code = {n.GetHashCode(),12}"// The example displays output like the following:// n = -634398368, hash code = -634398368// n = 2136747730, hash code = 2136747730// n = -1973417279, hash code = -1973417279// n = 1101478715, hash code = 1101478715// n = 2078057429, hash code = 2078057429// n = -334489950, hash code = -334489950// n = -68958230, hash code = -68958230// n = -379951485, hash code = -379951485// n = -31553685, hash code = -31553685// n = 2105429592, hash code = 2105429592
Public Structure Number Private n As Integer Public Sub New(value As Integer) n = value End Sub Public ReadOnly Property Value As Integer Get Return n End Get End Property Public Overrides Function Equals(obj As Object) As Boolean If obj Is Nothing OrElse Not TypeOf obj Is Number Then Return False Else Return n = CType(obj, Number).n End If End Function Public Overrides Function GetHashCode() As Integer Return n End Function Public Overrides Function ToString() As String Return n.ToString() End FunctionEnd StructureModule Example1 Public Sub Main() Dim rnd As New Random() For ctr As Integer = 0 To 9 Dim randomN As Integer = rnd.Next(Int32.MinValue, Int32.MaxValue) Dim n As New Number(randomN) Console.WriteLine("n = {0,12}, hash code = {1,12}", n, n.GetHashCode()) Next End SubEnd Module' The example displays output like the following:' n = -634398368, hash code = -634398368' n = 2136747730, hash code = 2136747730' n = -1973417279, hash code = -1973417279' n = 1101478715, hash code = 1101478715' n = 2078057429, hash code = 2078057429' n = -334489950, hash code = -334489950' n = -68958230, hash code = -68958230' n = -379951485, hash code = -379951485' n = -31553685, hash code = -31553685' n = 2105429592, hash code = 2105429592
Frequently, a type has multiple data fields that can participate in generating the hash code. One way to generate a hash code is to combine these fields using anXOR (eXclusive OR)
operation, as shown in the following example.
using System;// A type that represents a 2-D point.public struct Point2{ private int x; private int y; public Point2(int x, int y) { this.x = x; this.y = y; } public override bool Equals(Object obj) { if (! (obj is Point2)) return false; Point2 p = (Point2) obj; return x == p.x & y == p.y; } public override int GetHashCode() { return x ^ y; }}public class Example3{ public static void Main() { Point2 pt = new Point2(5, 8); Console.WriteLine(pt.GetHashCode()); pt = new Point2(8, 5); Console.WriteLine(pt.GetHashCode()); }}// The example displays the following output:// 13// 13
// A type that represents a 2-D point.[<Struct; CustomEquality; NoComparison>]type Point(x: int, y: int) = member _.X = x member _.Y = y override _.Equals(obj) = match obj with | :? Point as p -> x = p.X && y = p.Y | _ -> false override _.GetHashCode() = x ^^^ ylet pt = Point(5, 8)printfn $"{pt.GetHashCode()}"let pt2 = Point(8, 5)printfn $"{pt.GetHashCode()}"// The example displays the following output:// 13// 13
' A type that represents a 2-D point.Public Structure Point3 Private x As Integer Private y As Integer Public Sub New(x As Integer, y As Integer) Me.x = x Me.y = y End Sub Public Overrides Function Equals(obj As Object) As Boolean If Not TypeOf obj Is Point3 Then Return False Dim p As Point3 = CType(obj, Point3) Return x = p.x And y = p.y End Function Public Overrides Function GetHashCode() As Integer Return x Xor y End FunctionEnd StructurePublic Module Example3 Public Sub Main() Dim pt As New Point3(5, 8) Console.WriteLine(pt.GetHashCode()) pt = New Point3(8, 5) Console.WriteLine(pt.GetHashCode()) End SubEnd Module
The previous example returns the same hash code for (n1, n2) and (n2, n1), and so may generate more collisions than are desirable. A number of solutions are available so that hash codes in these cases are not identical. One is to return the hash code of aTuple
object that reflects the order of each field. The following example shows a possible implementation that uses theTuple<T1,T2> class. Note, though, that the performance overhead of instantiating aTuple
object may significantly impact the overall performance of an application that stores large numbers of objects in hash tables.
using System;public struct Point3{ private int x; private int y; public Point3(int x, int y) { this.x = x; this.y = y; } public override bool Equals(Object obj) { if (obj is Point3) { Point3 p = (Point3) obj; return x == p.x & y == p.y; } else { return false; } } public override int GetHashCode() { return Tuple.Create(x, y).GetHashCode(); }}public class Example{ public static void Main() { Point3 pt = new Point3(5, 8); Console.WriteLine(pt.GetHashCode()); pt = new Point3(8, 5); Console.WriteLine(pt.GetHashCode()); }}// The example displays the following output:// 173// 269
[<Struct; CustomEquality; NoComparison>]type Point(x: int, y: int) = member _.X = x member _.Y = y override _.Equals(obj) = match obj with | :? Point as p -> x = p.X && y = p.Y | _ -> false override _.GetHashCode() = (x, y).GetHashCode()let pt = Point(5, 8)printfn $"{pt.GetHashCode()}"let pt2 = Point(8, 5)printfn $"{pt2.GetHashCode()}"// The example displays the following output:// 173// 269
Public Structure Point Private x As Integer Private y As Integer Public Sub New(x As Integer, y As Integer) Me.x = x Me.y = y End Sub Public Overrides Function Equals(obj As Object) As Boolean If Not TypeOf obj Is Point Then Return False Dim p As Point = CType(obj, Point) Return x = p.x And y = p.y End Function Public Overrides Function GetHashCode() As Integer Return Tuple.Create(x, y).GetHashCode() End Function End Structure Public Module Example Public Sub Main() Dim pt As New Point(5, 8) Console.WriteLine(pt.GetHashCode()) pt = New Point(8, 5) Console.WriteLine(pt.GetHashCode()) End Sub End Module ' The example displays the following output:' 173' 269
A second alternative solution involves weighting the individual hash codes by left-shifting the hash codes of successive fields by two or more bits. Optimally, bits shifted beyond bit 31 should wrap around rather than be discarded. Since bits are discarded by the left-shift operators in both C# and Visual Basic, this requires creating a left shift-and-wrap method like the following:
public int ShiftAndWrap(int value, int positions){ positions = positions & 0x1F; // Save the existing bit pattern, but interpret it as an unsigned integer. uint number = BitConverter.ToUInt32(BitConverter.GetBytes(value), 0); // Preserve the bits to be discarded. uint wrapped = number >> (32 - positions); // Shift and wrap the discarded bits. return BitConverter.ToInt32(BitConverter.GetBytes((number << positions) | wrapped), 0);}
let shiftAndWrap (value: int) positions = let positions = positions &&& 0x1F // Save the existing bit pattern, but interpret it as an unsigned integer. let number = BitConverter.ToUInt32(BitConverter.GetBytes value, 0) // Preserve the bits to be discarded. let wrapped = number >>> (32 - positions) // Shift and wrap the discarded bits. BitConverter.ToInt32(BitConverter.GetBytes((number <<< positions) ||| wrapped), 0)
Public Function ShiftAndWrap(value As Integer, positions As Integer) As Integer positions = positions And &h1F ' Save the existing bit pattern, but interpret it as an unsigned integer. Dim number As UInteger = BitConverter.ToUInt32(BitConverter.GetBytes(value), 0) ' Preserve the bits to be discarded. Dim wrapped AS UInteger = number >> (32 - positions) ' Shift and wrap the discarded bits. Return BitConverter.ToInt32(BitConverter.GetBytes((number << positions) Or wrapped), 0)End Function
The following example then uses this shift-and-wrap method to compute the hash code of thePoint
structure used in the previous examples.
using System;public struct Point{ private int x; private int y; public Point(int x, int y) { this.x = x; this.y = y; } public override bool Equals(Object obj) { if (!(obj is Point)) return false; Point p = (Point) obj; return x == p.x & y == p.y; } public override int GetHashCode() { return ShiftAndWrap(x.GetHashCode(), 2) ^ y.GetHashCode(); } private int ShiftAndWrap(int value, int positions) { positions = positions & 0x1F; // Save the existing bit pattern, but interpret it as an unsigned integer. uint number = BitConverter.ToUInt32(BitConverter.GetBytes(value), 0); // Preserve the bits to be discarded. uint wrapped = number >> (32 - positions); // Shift and wrap the discarded bits. return BitConverter.ToInt32(BitConverter.GetBytes((number << positions) | wrapped), 0); }}public class Example2{ public static void Main() { Point pt = new Point(5, 8); Console.WriteLine(pt.GetHashCode()); pt = new Point(8, 5); Console.WriteLine(pt.GetHashCode()); }}// The example displays the following output:// 28// 37
open System[<Struct; CustomEquality; NoComparison>]type Point(x: int, y: int) = member _.X = x member _.Y = y override _.Equals(obj) = match obj with | :? Point as p -> x = p.X && y = p.Y | _ -> false override this.GetHashCode() = this.ShiftAndWrap(x.GetHashCode(), 2) ^^^ y.GetHashCode() member _.ShiftAndWrap(value, positions) = let positions = positions &&& 0x1F // Save the existing bit pattern, but interpret it as an unsigned integer. let number = BitConverter.ToUInt32(BitConverter.GetBytes value, 0) // Preserve the bits to be discarded. let wrapped = number >>> (32 - positions) // Shift and wrap the discarded bits. BitConverter.ToInt32(BitConverter.GetBytes((number <<< positions) ||| wrapped), 0)let pt = Point(5, 8)printfn $"{pt.GetHashCode()}"let pt2 = Point(8, 5)printfn $"{pt2.GetHashCode()}"// The example displays the following output:// 28// 37
Public Structure Point5 Private x As Integer Private y As Integer Public Sub New(x As Integer, y As Integer) Me.x = x Me.y = y End Sub Public Overrides Function Equals(obj As Object) As Boolean If Not TypeOf obj Is Point5 Then Return False Dim p As Point5 = CType(obj, Point5) Return x = p.x And y = p.y End Function Public Overrides Function GetHashCode() As Integer Return ShiftAndWrap(x.GetHashCode(), 2) Xor y.GetHashCode() End Function Private Function ShiftAndWrap(value As Integer, positions As Integer) As Integer positions = positions And &H1F ' Save the existing bit pattern, but interpret it as an unsigned integer. Dim number As UInteger = BitConverter.ToUInt32(BitConverter.GetBytes(value), 0) ' Preserve the bits to be discarded. Dim wrapped As UInteger = number >> (32 - positions) ' Shift and wrap the discarded bits. Return BitConverter.ToInt32(BitConverter.GetBytes((number << positions) Or wrapped), 0) End FunctionEnd StructureModule Example2 Public Sub Main() Dim pt As New Point5(5, 8) Console.WriteLine(pt.GetHashCode()) pt = New Point5(8, 5) Console.WriteLine(pt.GetHashCode()) End SubEnd Module' The example displays the following output:' 28' 37
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