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Commit7ae5f79

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864_ShortestPathToGetAllKeys864
1 parentd728a25 commit7ae5f79

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/**
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* We are given a 2-dimensional grid. "." is an empty cell, "#" is a wall, "@"
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* is the starting point, ("a", "b", ...) are keys, and ("A", "B", ...) are
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* locks.
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*
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* We start at the starting point, and one move consists of walking one space
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* in one of the 4 cardinal directions. We cannot walk outside the grid, or
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* walk into a wall. If we walk over a key, we pick it up. We can't walk over
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* a lock unless we have the corresponding key.
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*
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* For some 1 <= K <= 6, there is exactly one lowercase and one uppercase
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* letter of the first K letters of the English alphabet in the grid. This
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* means that there is exactly one key for each lock, and one lock for each
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* key; and also that the letters used to represent the keys and locks were
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* chosen in the same order as the English alphabet.
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*
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* Return the lowest number of moves to acquire all keys.
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* If it's impossible, return -1.
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*
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* Example 1:
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* Input: ["@.a.#","###.#","b.A.B"]
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* Output: 8
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*
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* Example 2:
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* Input: ["@..aA","..B#.","....b"]
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* Output: 6
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*
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* Note:
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* 1 <= grid.length <= 30
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* 1 <= grid[0].length <= 30
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* grid[i][j] contains only '.', '#', '@', 'a'-'f' and 'A'-'F'
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* The number of keys is in [1, 6].
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* Each key has a different letter and opens exactly one lock.
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*/
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publicclassShortestPathToGetAllKeys864 {
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privateint[][]directions =newint[][]{{0,1}, {1,0}, {0, -1}, {-1,0}};
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publicintshortestPathAllKeys(String[]grid) {
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intM =grid.length;
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intN =grid[0].length();
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char[][]maze =newchar[M][N];
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intnumKeys =0;
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int[]start =newint[2];
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for (inti=0;i<M;i++) {
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char[]row =grid[i].toCharArray();
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for (intj=0;j<N;j++) {
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maze[i][j] =row[j];
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if (row[j] =='@') {
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start[0] =i;
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start[1] =j;
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}elseif (row[j] >='a' &&row[j] <='f') {
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numKeys++;
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}
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}
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}
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int[]res =newint[]{Integer.MAX_VALUE};
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Set<Character>keySet =newHashSet<>();
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helper(maze,start,numKeys,keySet,0,M,N,res);
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returnres[0] ==Integer.MAX_VALUE ? -1 :res[0];
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}
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publicvoidhelper(char[][]maze,int[]start,intnumKeys,Set<Character>keySet,intsteps,intM,intN,int[]res) {
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if (numKeys ==keySet.size()) {
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res[0] =Math.min(res[0],steps);
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return;
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}
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boolean[][]visited =newboolean[M][N];
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Queue<int[]>q =newLinkedList<>();
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q.add(start);
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visited[start[0]][start[1]] =true;
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Set<int[]>newKeys =newHashSet<>();
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intlevel =1;
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while (!q.isEmpty() &&steps +level <res[0]) {
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intsize =q.size();
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for (inti=0;i<size;i++) {
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int[]curr =q.poll();
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for (int[]dir:directions) {
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intx =curr[0] +dir[0];
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inty =curr[1] +dir[1];
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if (x <0 ||y <0 ||x >=M ||y >=N)continue;
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charnext =maze[x][y];
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if (next =='#' ||visited[x][y])continue;
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if (next =='@' ||next =='.') {
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q.add(newint[]{x,y});
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visited[x][y] =true;
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}elseif (next >='a' &&next <='f') {
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if (!keySet.contains(next)) {
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newKeys.add(newint[]{x,y,level});
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}else {
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q.add(newint[]{x,y});
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visited[x][y] =true;
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}
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}elseif (next >='A' &&next <='F') {
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if (keySet.contains(Character.toLowerCase(next))) {
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q.add(newint[]{x,y});
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visited[x][y] =true;
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}
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}
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}
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}
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level++;
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}
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if (!newKeys.isEmpty()) {
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for (int[]newKey:newKeys) {
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int[]newKeyPos =newint[]{newKey[0],newKey[1]};
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charkey =maze[newKey[0]][newKey[1]];
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keySet.add(key);
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helper(maze,newKeyPos,numKeys,keySet,steps +newKey[2],M,N,res);
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keySet.remove(key);
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}
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}
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}
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}

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