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Description
Description of the problem, including code/CLI snippet
This is my config file :
[global]default = gitlabssl_verify = truetimeout = 5[gitlab]url = https://gitlab.comprivate_token = helper: ~/showGitlabToken.shThe~/showGitlabToken.sh runs akeepassxc-cli command to show the gitlab token.
Thiskeepassxc-cli needs to prompt me for my password.
Expected Behavior
When I rungitlab ls I get a prompt for my keyring password, then a result
Actual Behavior
I get an error
Traceback (most recent call last): File "/home/MYUSERNAME/.local/bin/gitlab", line 8, in <module> sys.exit(main()) File "/home/MYUSERNAME/.local/lib/python3.9/site-packages/gitlab/cli.py", line 204, in main config = gitlab.config.GitlabConfigParser(options.gitlab, options.config_file) File "/home/MYUSERNAME/.local/lib/python3.9/site-packages/gitlab/config.py", line 164, in __init__ self._get_values_from_helper() File "/home/MYUSERNAME/.local/lib/python3.9/site-packages/gitlab/config.py", line 224, in _get_values_from_helper subprocess.check_output(commmand, stderr=subprocess.PIPE) File "/usr/lib/python3.9/subprocess.py", line 424, in check_output return run(*popenargs, stdout=PIPE, timeout=timeout, check=True, File "/usr/lib/python3.9/subprocess.py", line 505, in run with Popen(*popenargs, **kwargs) as process: File "/usr/lib/python3.9/subprocess.py", line 951, in __init__ self._execute_child(args, executable, preexec_fn, close_fds, File "/usr/lib/python3.9/subprocess.py", line 1821, in _execute_child raise child_exception_type(errno_num, err_msg, err_filename)OSError: [Errno 8] Exec format error: '/home/MYUSERNAME/showGitlabToken.sh'Specifications
- python-gitlab version: 2.9.0
- API version you are using (v3/v4):
- Gitlab server version (or gitlab.com):