- Notifications
You must be signed in to change notification settings - Fork441
Step info improve jpp#567
New issue
Have a question about this project? Sign up for a free GitHub account to open an issue and contact its maintainers and the community.
By clicking “Sign up for GitHub”, you agree to ourterms of service andprivacy statement. We’ll occasionally send you account related emails.
Already on GitHub?Sign in to your account
Step info improve jpp#567
Uh oh!
There was an error while loading.Please reload this page.
Conversation
1) System Type 1 - Step response not stationary: G(s)=1/s(s+1)2) SISO system with under shoot response and positive final value G(s)=(-s+1)/(s²+s+1)3) Same system that 2) with k=-14) example from matlab online helphttps://www.mathworks.com/help/control/ref/stepinfo.html G(s)=(s²+5s+5)/(s^4+1.65s^3+6.5s+2)with stepinfo output: RiseTime: 3.8456 SettlingTime: 27.9762 SettlingMin: 2.0689 SettlingMax: 2.6873 Overshoot: 7.4915 Undershoot: 0 Peak: 2.6873 PeakTime: 8.05305) example from matlab online helphttps://www.mathworks.com/help/control/ref/stepinfo.htmlA = [0.68 -0.34; 0.34 0.68];B = [0.18 -0.05; 0.04 0.11];C = [0 -1.53; -1.12 -1.10];D = [0 0; 0.06 -0.37];sys = StateSpace(A,B,C,D,0.2);examine the response characteristics for the response from the first input to the second output of sys.with stepinfo output: RiseTime: 0.4000 SettlingTime: 2.8000 SettlingMin: -0.6724 SettlingMax: -0.5188 Overshoot: 24.6476 Undershoot: 11.1224 Peak: 0.6724 PeakTime: 1
coveralls commentedMar 12, 2021 • edited
Loading Uh oh!
There was an error while loading.Please reload this page.
edited
Uh oh!
There was an error while loading.Please reload this page.
Uh oh!
There was an error while loading.Please reload this page.
rise_time: float = np.NaN | ||
settling_time: float = np.NaN | ||
settling_min: float = np.NaN | ||
settling_max: float = np.NaN | ||
peak_value: float = np.Inf | ||
peak_time: float = np.Inf | ||
undershoot: float = np.NaN | ||
overshoot: float = np.NaN |
There was a problem hiding this comment.
Choose a reason for hiding this comment
The reason will be displayed to describe this comment to others.Learn more.
The first use of typing in python-control?
There was a problem hiding this comment.
Choose a reason for hiding this comment
The reason will be displayed to describe this comment to others.Learn more.
yes, is wrong?
There was a problem hiding this comment.
Choose a reason for hiding this comment
The reason will be displayed to describe this comment to others.Learn more.
Not at all! Good thing we already ditched Python 2.
control/timeresp.py Outdated
if InfValue < 0.0: | ||
# RiseTime | ||
tr_lower_index = (np.where(yout <= RiseTimeLimits[0] * InfValue)[0])[0] | ||
tr_upper_index = (np.where(yout <= RiseTimeLimits[1] * InfValue)[0])[0] | ||
# SettlingTime | ||
for i in reversed(range(T.size - 1)): | ||
if (-yout[i] <= np.abs(inf_margin)) | (-yout[i] >= np.abs(sup_margin)): | ||
settling_time = T[i + 1] | ||
break | ||
# Overshoot and Undershoot | ||
overshoot = np.abs(100. * ((-yout).max() - np.abs(InfValue)) / np.abs(InfValue)) | ||
undershoot = np.abs(100. * (-yout).min() / np.abs(InfValue)) | ||
else: | ||
tr_lower_index = (np.where(yout >= RiseTimeLimits[0] * InfValue)[0])[0] | ||
tr_upper_index = (np.where(yout >= RiseTimeLimits[1] * InfValue)[0])[0] | ||
# SettlingTime | ||
for i in reversed(range(T.size - 1)): | ||
if (yout[i] <= inf_margin) | (yout[i] >= sup_margin): | ||
settling_time = T[i + 1] | ||
break | ||
# Overshoot and Undershoot | ||
overshoot = np.abs(100. * (yout.max() - InfValue) / InfValue) | ||
undershoot = np.abs(100. * yout.min() / InfValue) |
bnavigatorMar 12, 2021 • edited
Loading Uh oh!
There was an error while loading.Please reload this page.
edited
Uh oh!
There was an error while loading.Please reload this page.
There was a problem hiding this comment.
Choose a reason for hiding this comment
The reason will be displayed to describe this comment to others.Learn more.
Hmm, this has a lot of duplicate code. Have you considered using asign
variable and theabs()
function instead of two completely separate blocks? I think It won't turn out much more convoluted than the current InfValue < 0 part.
There was a problem hiding this comment.
Choose a reason for hiding this comment
The reason will be displayed to describe this comment to others.Learn more.
ok
systems converting to SISO systems from input=0 to output =0solve problems with non stationary systems doingSteadyStateValue= nan when y_final is inf
Other than the MIMO handling (#574), this looks good to me. I'll merge this. Future PRs can improve it further. |
This modification improve step_info results:
Solve the issue Any plan for step_info to support negative step responses?#337
solve the issue step_info problem with non stationary systems response#564
solve the issue step_info undershoot must be "Undershoot: Percentage of undershoot"#565
I try to fullfill pep 8
Add some aditional tests to check the results