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Translatelibrary/sched.po#894
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reviewed~
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| "future calls to :meth:`run`." | ||
| msgstr"" | ||
| "*action* 或 *delayfunc* 都可能引發例外。無論哪種情況,排程器都將保持一致的狀" | ||
| "態並傳遞例外。如果是由 *action* 引發例外,則後續呼叫 :meth:`run` 時將不會嘗試" |
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這邊這句 the event will not be attempted in future calls to :meth:run
我看不太出來他是連傳都不會傳 還是是傳了但不會運行
如果沒想法就維持這個翻譯吧(畢竟原文就沒寫清楚)
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mattwang44 commentedJun 10, 2024
rebased |
Co-authored-by: Payon <ken71301@hotmail.com>
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LGTM~

resolved#225