Bug report

Bug description:

python version:3.12.9
An error occurred when running as a standalone script.
An error message is reported when running the sample code of the python document:

Traceback (most recent call last):
File "C:\Users\wen\Desktop\test.py", line 32, in
main()
File "C:\Users\wen\Desktop\test.py", line 28, in main
for number, prime in zip(PRIMES, executor.map(is_prime, PRIMES)):
^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
File "C:\Miniconda3\Lib\concurrent\futures\process.py", line 636, in _chain_from_iterable_of_lists
for element in iterable:
^^^^^^^^
File "C:\Miniconda3\Lib\concurrent\futures_base.py", line 619, in result_iterator
yield _result_or_cancel(fs.pop())
^^^^^^^^^^^^^^^^^^^^^^^^^^^
File "C:\Miniconda3\Lib\concurrent\futures_base.py", line 317, in _result_or_cancel
return fut.result(timeout)
^^^^^^^^^^^^^^^^^^^
File "C:\Miniconda3\Lib\concurrent\futures_base.py", line 456, in result
return self.__get_result()
^^^^^^^^^^^^^^^^^^^
File "C:\Miniconda3\Lib\concurrent\futures_base.py", line 401, in __get_result
raise self._exception
concurrent.futures.process.BrokenProcessPool: A process in the process pool was terminated abruptly while the future was running or pending.

import concurrent.futuresimport mathPRIMES = [    112272535095293,    112582705942171,    112272535095293,    115280095190773,    115797848077099,    1099726899285419]def is_prime(n):    if n < 2:        return False    if n == 2:        return True    if n % 2 == 0:        return False    sqrt_n = int(math.floor(math.sqrt(n)))    for i in range(3, sqrt_n + 1, 2):        if n % i == 0:            return False    return Truedef main():    with concurrent.futures.ProcessPoolExecutor() as executor:        for number, prime in zip(PRIMES, executor.map(is_prime, PRIMES)):            print('%d is prime: %s' % (number, prime))if __name__ == '__main__':    main()

CPython versions tested on:

3.12

Operating systems tested on:

Windows 10