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Originally posted by@AlexWaygood in#106354 (comment):
Tools/clinic/clinic.py:5039: error: Incompatible return value type (got"tuple[str, bool, dict[str | None, Any]]", expected"tuple[str, bool, dict[str, Any]]") [return-value] return name, False, kwargs ^~~~~~~~~~~~~~~~~~~I think mypy is flagging a real bug in the code here. The issue is this block of code here:
cpython/Tools/clinic/clinic.py
Lines 5033 to 5039 ind694f04
| caseast.Call(func=ast.Name(name)): | |
| symbols=globals() | |
| kwargs= { | |
| node.arg:eval_ast_expr(node.value,symbols) | |
| fornodeinannotation.keywords | |
| } | |
| returnname,False,kwargs |
The function is annotated as returntuple[str, bool, KwargDict], andKwargDict is a type alias fordict[str, Any]. It's important that the dictionary that's the third element of the tuple only has strings as keys. If it doesn't, then this will fail:
cpython/Tools/clinic/clinic.py
Line 4617 ind694f04
| return_converter=return_converters[name](**kwargs) |
The code as written, however, doesn't guarantee that all the keys in thekwargs dictionary will be strings. In the dictionary comprehension, we can see thatannotation is anast.Call instance. That means thatannotation.keywords is of typelist[ast.keyword] -- we can see this from typeshed's stubs for theast module (which are an invaluable reference if you're working with ASTs in Python!):https://github.com/python/typeshed/blob/18d45d62aabe68fce78965c4920cbdeddb4b54db/stdlib/_ast.pyi#L324-L329. Ifannotation.keywords is of typelist[ast.keyword], that means that thenode variable in the dictionary comprehension is of typekeyword, which means (again using typeshed'sast stubs), thatnode.arg is of typestr | None:https://github.com/python/typeshed/blob/18d45d62aabe68fce78965c4920cbdeddb4b54db/stdlib/_ast.pyi#L516-L520. AKA, the keys in this dictionary are not always guaranteed to be strings -- there's a latent bug in this code!