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Commitba87dae

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Misc Itertools recipe tweaks (GH-100493)
(cherry picked from commit0769f95)Co-authored-by: Raymond Hettinger <rhettinger@users.noreply.github.com>
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‎Doc/library/itertools.rst

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@@ -749,6 +749,11 @@ which incur interpreter overhead.
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..testcode::
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import collections
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import math
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import operator
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import random
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def take(n, iterable):
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"Return first n items of the iterable as a list"
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return list(islice(iterable, n))
@@ -853,6 +858,21 @@ which incur interpreter overhead.
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data[2] = 1
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return iter_index(data, 1) if n > 2 else iter([])
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def factor(n):
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"Prime factors of n."
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# factor(97) --> 97
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# factor(98) --> 2 7 7
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# factor(99) --> 3 3 11
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for prime in sieve(n+1):
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while True:
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quotient, remainder = divmod(n, prime)
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if remainder:
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break
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yield prime
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n = quotient
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if n == 1:
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return
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def flatten(list_of_lists):
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"Flatten one level of nesting"
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return chain.from_iterable(list_of_lists)
@@ -1104,11 +1124,6 @@ which incur interpreter overhead.
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Now, we test all of the itertool recipes
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>>>import operator
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>>>import collections
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>>>import math
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>>>import random
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>>>take(10, count())
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[0, 1, 2, 3, 4, 5, 6, 7, 8, 9]
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@@ -1221,6 +1236,35 @@ which incur interpreter overhead.
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>>>set(sieve(10_000)).isdisjoint(carmichael)
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True
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list(factor(0))
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[]
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list(factor(1))
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[]
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list(factor(2))
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[2]
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list(factor(3))
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[3]
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list(factor(4))
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[2, 2]
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list(factor(5))
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[5]
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list(factor(6))
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[2, 3]
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list(factor(7))
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[7]
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list(factor(8))
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[2, 2, 2]
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list(factor(9))
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[3, 3]
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list(factor(10))
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[2, 5]
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all(math.prod(factor(n)) == n for n in range(1, 1000))
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True
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all(set(factor(n)) <= set(sieve(n+1)) for n in range(1, 1000))
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True
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all(list(factor(n)) == sorted(factor(n)) for n in range(1, 1000))
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True
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>>>list(flatten([('a','b'), (), ('c','d','e'), ('f',), ('g','h','i')]))
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['a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i']
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