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Commit31380bc

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Spell "partitionwise" consistently.
I'm not sure which spelling is better, "partitionwise" or "partition-wise",but everywhere else we spell it "partitionwise", so be consistent.Tatsuro Yamada reported the one in README, I found the other one with grep.Discussion:https://www.postgresql.org/message-id/d25ebf36-5a6d-8b2c-1ff3-d6f022a56000@lab.ntt.co.jp
1 parent661dd23 commit31380bc

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‎contrib/postgres_fdw/expected/postgres_fdw.out

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@@ -8435,7 +8435,7 @@ SELECT t1.a,t1.b FROM fprt1 t1, LATERAL (SELECT t2.a, t2.b FROM fprt2 t2 WHERE t
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400 | 400
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(4 rows)
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-- with PHVs,partition-wise join selected but no join pushdown
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-- with PHVs,partitionwise join selected but no join pushdown
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EXPLAIN (COSTS OFF)
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SELECT t1.a, t1.phv, t2.b, t2.phv FROM (SELECT 't1_phv' phv, * FROM fprt1 WHERE a % 25 = 0) t1 FULL JOIN (SELECT 't2_phv' phv, * FROM fprt2 WHERE b % 25 = 0) t2 ON (t1.a = t2.b) ORDER BY t1.a, t2.b;
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QUERY PLAN

‎contrib/postgres_fdw/sql/postgres_fdw.sql

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@@ -2291,7 +2291,7 @@ EXPLAIN (COSTS OFF)
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SELECTt1.a,t1.bFROM fprt1 t1, LATERAL (SELECTt2.a,t2.bFROM fprt2 t2WHEREt1.a=t2.bANDt1.b=t2.a) qWHEREt1.a%25=0ORDER BY1,2;
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SELECTt1.a,t1.bFROM fprt1 t1, LATERAL (SELECTt2.a,t2.bFROM fprt2 t2WHEREt1.a=t2.bANDt1.b=t2.a) qWHEREt1.a%25=0ORDER BY1,2;
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-- with PHVs,partition-wise join selected but no join pushdown
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-- with PHVs,partitionwise join selected but no join pushdown
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EXPLAIN (COSTS OFF)
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SELECTt1.a,t1.phv,t2.b,t2.phvFROM (SELECT't1_phv' phv,*FROM fprt1WHERE a %25=0) t1 FULLJOIN (SELECT't2_phv' phv,*FROM fprt2WHERE b %25=0) t2ON (t1.a=t2.b)ORDER BYt1.a,t2.b;
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SELECTt1.a,t1.phv,t2.b,t2.phvFROM (SELECT't1_phv' phv,*FROM fprt1WHERE a %25=0) t1 FULLJOIN (SELECT't2_phv' phv,*FROM fprt2WHERE b %25=0) t2ON (t1.a=t2.b)ORDER BYt1.a,t2.b;

‎src/backend/optimizer/README

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@@ -1106,8 +1106,8 @@ PartitionSchemeData object. This reduces memory consumed by
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PartitionSchemeData objects and makes it easy to compare the partition schemes
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of joining relations.
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Partition-wise aggregates/grouping
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----------------------------------
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Partitionwise aggregates/grouping
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---------------------------------
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If the GROUP BY clause has contains all of the partition keys, all the rows
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that belong to a given group must come from a single partition; therefore,

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