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Commit73860ac

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tniessenmarco-ippolito
authored andcommitted
doc: clarify that fs.exists() may return false for existing symlink
Given that this API is problematic in any case, we should be preciseabout its (perhaps surprising) behavior.PR-URL:#53566Reviewed-By: Jithil P Ponnan <jithil@outlook.com>Reviewed-By: Moshe Atlow <moshe@atlow.co.il>Reviewed-By: Yagiz Nizipli <yagiz.nizipli@sentry.io>Reviewed-By: Marco Ippolito <marcoippolito54@gmail.com>Reviewed-By: Luigi Pinca <luigipinca@gmail.com>Reviewed-By: Ulises Gascón <ulisesgascongonzalez@gmail.com>
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‎doc/api/fs.md

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@@ -2656,7 +2656,7 @@ changes:
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* `callback` {Function}
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* `exists` {boolean}
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Test whether or not the given path exists by checking with the file system.
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Test whether or not theelement at thegiven`path` exists by checking with the file system.
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Then call the `callback` argument with either true or false:
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```mjs
@@ -2673,6 +2673,9 @@ parameter, optionally followed by other parameters. The `fs.exists()` callback
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has only one boolean parameter. This is one reason `fs.access()` is recommended
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instead of `fs.exists()`.
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If `path` is a symbolic link, it is followed. Thus, if `path` exists but points
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to a non-existent element, the callback will receive the value `false`.
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Using `fs.exists()` to check for the existence of a file before calling
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`fs.open()`, `fs.readFile()`, or `fs.writeFile()` is not recommended. Doing
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so introduces a race condition, since other processes may change the file's

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