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Subhajit Sahu edited this pageMay 3, 2023 ·22 revisions

Examine if there are no duplicate values.

Similar:isUnique,isDisjoint,intersection.


functionisUnique(x,fc,fm)// x:  an array// fc: compare function (a, b)// fm: map function (v, i, x)

⏱️ Compare function ⇒ O(n²).

constxarray=require('extra-array');varx=[1,2,-1,-2];xarray.isUnique(x);// → truexarray.isUnique(x,(a,b)=>Math.abs(a)-Math.abs(b));// → falsexarray.isUnique(x,null,v=>Math.abs(v));// → false


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