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refactor: js - intervals#449

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Merged
mitchellirvin merged 1 commit intoneetcode-gh:mainfromaakhtar3:intervals
Jul 30, 2022
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34 changes: 25 additions & 9 deletionsjavascript/252-Meeting-Rooms.js
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Original file line numberDiff line numberDiff line change
@@ -1,14 +1,30 @@
/**
* @param {number[]} intervals
* https://leetcode.com/problems/meeting-rooms/
* Time O(N * logN) | Space O(1)
* @param {number[][]} intervals
* @return {boolean}
*/
var canAttendMeetings = function (intervals) {
intervals.sort((a, b) => a[0] - b[0]);
var canAttendMeetings = function(intervals) {
intervals.sort(([ aStart, aEnd ], [ bStart, bEnd ]) => aStart !== bStart
? aStart - bStart
: aEnd - bEnd
);

for (let i = 0; i < intervals.length - 1; i++) {
if (intervals[i][1] > intervals[i + 1][0]) {
return false;
}
}
return true;
return canAttend(intervals)
};

const canAttend = (intervals) => {
let prev = intervals.shift();

for (const curr of intervals) {
const [ prevStart, prevEnd ] = prev;
const [ currStart, currEnd ] = curr;

const hasOverlap = currStart < prevEnd;
if (hasOverlap) return false;

prev = curr;
}

return true;
}
39 changes: 39 additions & 0 deletionsjavascript/253-Meeting-Rooms-ii.js
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@@ -0,0 +1,39 @@
/**
* https://leetcode.com/problems/meeting-rooms-ii/
* Time O((N * logN) + (M * logM)) | Space O(1)
* @param {number[][]} intervals
* @return {number}
*/
var minMeetingRooms = function(intervals) {
const { start, end } = splitIntervals(intervals);
let [ minRooms, startIndex, endIndex ] = [ 0, 0, 0 ];

while (startIndex < intervals.length) {
const [ currStart, prevEnd ] = [ start[startIndex], end[endIndex] ];

const hasGap = prevEnd <= currStart;
if (hasGap) {
minRooms--;
endIndex++;
}

minRooms++;
startIndex++;
}

return minRooms;
};

const splitIntervals = (intervals, start = [], end = []) => {
for (const [ startTime, endTime ] of intervals) {
start.push(startTime);
end.push(endTime);
}

const comparator = ((a, b) => a - b);

start.sort(comparator);
end.sort(comparator);

return { start, end };
};
40 changes: 27 additions & 13 deletionsjavascript/435-Non-overlapping-Intervals.js
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@@ -1,17 +1,31 @@
let eraseOverlapIntervals = function (intervals) {
intervals = intervals.sort((a, b) => a[0] - b[1]);
/**
* https://leetcode.com/problems/non-overlapping-intervals/
* Time O(N * logN) | Space O(1)
* @param {number[][]} intervals
* @return {number}
*/
var eraseOverlapIntervals = function(intervals) {
intervals.sort(([ aStart, aEnd ], [ bStart, bEnd ]) => aEnd !== bEnd
? aEnd - bEnd
: aStart - bStart
);

let currentEnd = intervals[0][1];
let res = 0;
return getGaps(intervals)
};

const getGaps = (intervals, gaps = 1) => {
const prev = intervals.shift();

for (const curr of intervals) {
const [ prevStart, prevEnd ] = prev;
const [ currStart, currEnd ] = curr;

for (let i = 1; i < intervals.length; i++) {
if (currentEnd > intervals[i][0]) {
res += 1;
currentEnd = Math.min(intervals[i][1], currentEnd);
} else {
currentEnd = intervals[i][1];
}
const hasGap = prevEnd <= currStart;
if (!hasGap) continue;

prev[1] = curr[1];
gaps++;
}

returnres;
};
return(intervals.length + 1) - gaps;
}
40 changes: 29 additions & 11 deletionsjavascript/56-Merge-Intervals.js
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@@ -1,16 +1,34 @@
var merge = function (intervals) {
intervals.sort((a, b) => a[0] - b[0]);
/**
* https://leetcode.com/problems/merge-intervals/
* Time O(N * logN) | Space O(N)
* @param {number[][]} intervals
* @return {number[][]}
*/
var merge = function(intervals) {
intervals.sort(([ aStart, aEnd ], [ bStart, bEnd ]) => aStart !== bStart
? aStart - bStart
: aEnd - bEnd
);

let res = [intervals[0]];
return mergerInterval(intervals)
};

const mergerInterval = (intervals, merged = []) => {
let prev = intervals.shift();

for (let i = 1; i < intervals.length; i++) {
let prev = res[res.length - 1];
for (const curr of intervals) {
const [ prevStart, prevEnd ] = prev;
const [ currStart, currEnd ] = curr;

if (prev[1] >= intervals[i][0]) {
prev[1] = Math.max(prev[1], intervals[i][1]);
} else {
res.push(intervals[i]);
const hasOverlap = currStart <= prevEnd;
if (hasOverlap) {
prev[1] = Math.max(prev[1], curr[1]);
continue;
}

merged.push(prev);
prev = curr;
}
return res;
};

return [ ...merged, prev ];
}
65 changes: 41 additions & 24 deletionsjavascript/57-Insert-Interval.js
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@@ -1,26 +1,43 @@
let insert = function (intervals, newInterval) {
let res = [];
let isAdded = false;

intervals.forEach((int) => {
if (int[0] > newInterval[1]) {
if (!isAdded) {
res.push(newInterval);
isAdded = true;
}

res.push(int);
} else if (int[1] < newInterval[0]) {
res.push(int);
} else {
newInterval[0] = Math.min(newInterval[0], int[0]);
newInterval[1] = Math.max(newInterval[1], int[1]);
}
});

if (!isAdded) {
res.push(newInterval);
}
/**
* https://leetcode.com/problems/insert-interval/
* Time O(N) | Space O(N)
* @param {number[][]} intervals
* @param {number[]} newInterval
* @return {number[][]}
*/
var insert = function(intervals, newInterval) {
const { beforeIndex, before } = getBefore(intervals, newInterval);
const afterIndex = mergeIntervals(intervals, newInterval, beforeIndex);
const after = intervals.slice(afterIndex);

returnres;
return[ ...before, newInterval, ...after ];
};

const getBefore = (intervals, newInterval, index = 0, before = []) => {
const hasGap = ([ prevStart, prevEnd ], [ currStart, currEnd ]) =>
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same as others

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@mitchellirvin
Since this in a while loop, we can either leave as is

consthasOverlap=()=> ...while(hasOverlap())

Move out of scoop

consthasOverlap=()=> ...constloop=()=>{while(hasOverlap())}

or add inline with comment

// hasOverlap = intervals[index] <= newInterval[1]while(intervals[index]<=newInterval[1])

prevEnd < currStart;

while (index < intervals.length && hasGap(intervals[index], newInterval)) {
const current = intervals[index];

before.push(current);
index++;
}

return { beforeIndex: index, before };
}

const mergeIntervals = (intervals, newInterval, index) => {
const hasOverlap = ([ prevStart, prevEnd ], [ currStart, currEnd ]) =>
currStart <= prevEnd;

while (index < intervals.length && hasOverlap(newInterval, intervals[index])) {
const current = intervals[index];

newInterval[0] = Math.min(newInterval[0], current[0]);
newInterval[1] = Math.max(newInterval[1], current[1]);
index++;
}

return index;
}

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