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Commitfdee9bf

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‎notes/LeetCode第877号问题:石子游戏.md‎

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喜羊羊先开始拿石头,随便拿!然后比较石头数量:
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1. 如果石头数量多于对手,赢了;
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2. 如果石头数量少于对手,自己拿石头的顺序和对手拿石头的顺序对调,还是赢。
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2. 如果石头数量少于对手,自己拿石头的顺序和对手拿石头的顺序对调**因为是偶数堆石头,所以可以全部对调**,还是赢。
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所以代码如下:
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