Commit566f0cf

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Add note that make_kyword_only() must be the outer most decorator

... to the error message, that gets thrown if it is not.

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Lines changed: 2 additions & 1 deletion

Original file line number	Diff line number	Diff line change
`@@ -437,7 +437,8 @@ def make_keyword_only(since, name, func=None):`
`437`	`437`	`assert (nameinsignature.parameters`
`438`	`438`	`andsignature.parameters[name].kind==POK), (`
`439`	`439`	`f"Matplotlib internal error:{name!r} must be a positional-or-keyword "`
`440`		`-f"parameter for{func.__name__}()")`
	`440`	`+f"parameter for{func.__name__}(). If this happens on a function with a "`
	`441`	`+f"pyplot wrapper, make sure make_keyword_only() is the outermost decorator.")`
`441`	`442`	`names= [*signature.parameters]`
`442`	`443`	`name_idx=names.index(name)`
`443`	`444`	`kwonly= [namefornameinnames[name_idx:]`

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