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Commite6a50a7

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Use strict subtype relation ingetCommonSupertype (microsoft#61903)
1 parentdca7170 commite6a50a7

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‎src/compiler/checker.ts‎

Lines changed: 11 additions & 1 deletion
Original file line numberDiff line numberDiff line change
@@ -25340,11 +25340,21 @@ export function createTypeChecker(host: TypeCheckerHost): TypeChecker {
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// right is a supertype.
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const superTypeOrUnion = literalTypesWithSameBaseType(primaryTypes) ?
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getUnionType(primaryTypes) :
25343-
reduceLeft(primaryTypes, (s, t) => isTypeSubtypeOf(s, t) ? t : s)!;
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getSingleCommonSupertype(primaryTypes);
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// Add any nullable types that occurred in the candidates back to the result.
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return primaryTypes === types ? superTypeOrUnion : getNullableType(superTypeOrUnion, getCombinedTypeFlags(types) & TypeFlags.Nullable);
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}
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function getSingleCommonSupertype(types: Type[]) {
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// First, find the leftmost type for which no type to the right is a strict supertype, and if that
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// type is a strict supertype of all other candidates, return it. Otherwise, return the leftmost type
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// for which no type to the right is a (regular) supertype.
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const candidate = reduceLeft(types, (s, t) => isTypeStrictSubtypeOf(s, t) ? t : s)!;
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return every(types, t => t === candidate || isTypeStrictSubtypeOf(t, candidate)) ?
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candidate :
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reduceLeft(types, (s, t) => isTypeSubtypeOf(s, t) ? t : s)!;
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}
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// Return the leftmost type for which no type to the right is a subtype.
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function getCommonSubtype(types: Type[]) {
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return reduceLeft(types, (s, t) => isTypeSubtypeOf(t, s) ? t : s)!;

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