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Translated the if statements#77

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meilune merged 24 commits intojavascript-tutorial:masterfrommeilune:master
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The answer is`2`,that's the firsttruthyvalue.
Atsakymas yra`2`,pirmojitruthyvertė.

```js run
alert( null || 2 || undefined );
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Expand Up@@ -2,9 +2,9 @@ importance: 5

---

#What's the result of OR?
#Koks bus ARBA rezultatas?

What is the code below going to output?
Ką atiduos žemiau esantis kodas?

```js
alert( null || 2 || undefined );
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The answer: first `1`,then `2`.
Atsakymas yra: pirma `1`,tada `2`.

```js run
alert( alert(1) || 2 || alert(3) );
```

The call to`alert`does not return a value. Or, in other words, it returns `undefined`.
Šaukimas`alert`negrąžina jokios vertės. Arba kitaip sakant, jis grąžina `undefined`.

1.The first OR`||`evaluates it's left operand `alert(1)`.That shows the first message with `1`.
2.The`alert`returns `undefined`,so OR goes on to the second operand searching for atruthyvalue.
3.The second operand`2`is truthy,so the execution is halted,`2`is returned and then shown by the outer alert.
1.Pirmasis ARBA`||`įvertina kairėje esantį operandą `alert(1)`.Jis parodo žinutę su `1`.
2. `alert`grąžina `undefined`,tad ARBA eina prie sekančio operando ieškodamastruthyvertės.
3.Antrasis operandas`2`yra truthy,tad operacija sustabdoma, grąžinamas`2`ir parodomas per išorinį alert.

There will be no`3`,because the evaluation does not reach `alert(3)`.
Nebebus`3`,nes įvertinimas nepasiekia `alert(3)`.
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---

#What's the result of OR'ed alerts?
#Koks bus ARBA alert rezultatas?

What will the code below output?
Ką atiduos žemiau esantis kodas?

```js
alert( alert(1) || 2 || alert(3) );
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The answer: `null`,because it's the first falsyvalue from the list.
Atsakymas: `null`,nes tai yra pirmoji falsyvertė sąraše.

```js run
alert( 1 && null && 2 );
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---

#What is the result of AND?
#Koks yra IR rezultatas?

What is this code going to show?
Ką parodys žemiau esantis kodas?

```js
alert( 1 && null && 2 );
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The answer: `1`,and then `undefined`.
Atsakymas: `1`,ir tada `undefined`.

```js run
alert( alert(1) && alert(2) );
```

The call to`alert`returns `undefined` (it just shows a message, so there's no meaningful return).
Šaukimas`alert`grąžina `undefined` (tiesiog parodo žinutę, tad nebus prasmingo grąžinimo).

Because of that,`&&`evaluates the left operand (outputs `1`),and immediately stops, because `undefined`is afalsyvalue. And `&&`looks for afalsyvalue and returns it, so it's done.
Dėl to`&&`įvertina kairį operandą (parodo `1`),ir iš karto sustoja, nes `undefined`yrafalsyvertė. O `&&`ieškofalsyvertės ir ją grąžina, ir sustoja.

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---

#What is the result of AND'edalerts?
#Koks yra IRalerts rezultatas?

What will this code show?
Kas parodys kodas esantis žemiau?

```js
alert( alert(1) && alert(2) );
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The answer: `3`.
Atsakymas: `3`.

```js run
alert( null || 2 && 3 || 4 );
```

The precedence of AND`&&`is higher than`||`,so it executes first.
IR`&&`pirmenybė yra aukštesnė už`||`,tad jis įvykdomas pirmiau.

The result of`2 && 3 = 3`,so the expression becomes:
Rezultatas yra`2 && 3 = 3`,tad išraiška tampa:

```
null || 3 || 4
```

Now the result is the firsttruthyvalue: `3`.
Dabar rezultatas yra pirmojitruthyvertė: `3`.

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---

#The result of OR AND OR
#ARBA IR ARBA rezultatas

What will the result be?
Koks bus rezultatas?

```js
alert( null || 2 && 3 || 4 );
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---

#Check the range between
#Patikrinkite intervalą

Write an"if"condition to check that `age`is between `14`and `90`inclusively.
Parašykite"if"sąlygą, kuri patikrintų ar `age`yra tarp `14`ir `90`įskaitant.

"Inclusively" means that `age`can reach the edges`14`or `90`.
"Įskaitant" reiškia, kad `age`gali pasiekti`14`ir `90` ribas.
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The first variant:
Pirmas variantas:

```js
if (!(age >= 14 && age <= 90))
```

The second variant:
Antras variantas:

```js
if (age < 14 || age > 90)
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---

#Check the range outside
#Patikrinkite už intervalo ribų

Write an`if`condition to check that `age`is NOT between14and 90inclusively.
Parašykite`if`sąlygą, kuri patikrintų ar `age`nėra tarp14ir 90įskaitant.

Create two variants: the first one using NOT`!`,the second one -- without it.
Sukurkite du variantus: vieną naudojant NE`!`,kitą nenaudojant jo.
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The answer: the first and the third will execute.
Atsakymas: pirma ir antra bus įvykdytos.

Details:

```js run
//Runs.
//The result of -1 || 0 = -1, truthy
if (-1 || 0) alert( 'first' );
//Paleidžiama.
//Rezultatas iš -1 || 0 = -1, truthy
if (-1 || 0) alert( 'pirmas' );

//Doesn't run
//Nepaleidžiamas
// -1 && 0 = 0, falsy
if (-1 && 0) alert( 'second' );
if (-1 && 0) alert( 'antras' );

//Executes
//Operator &&has a higher precedence than ||
//so -1 && 1executes first, giving us the chain:
//Įvykdomas
//Operatorius &&turi aukštesnį prioritetą negu ||
//tad -1 && 1įvykdomas pirmiau, sukurdamas mums grandinę:
// null || -1 && 1 -> null || 1 -> 1
if (null || -1 && 1) alert( 'third' );
if (null || -1 && 1) alert( 'trečias' );
```

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---

#A question about "if"
#Klausimas apie "if"

Which of these `alert`sare going to execute?
Kurie iš šių `alert`sbus įvykdyti?

What will the results of the expressions be inside `if(...)`?
Koks bus išraiškų rezultatas viduje `if(...)`?

```js
if (-1 || 0) alert( 'first' );
if (-1 && 0) alert( 'second' );
if (null || -1 && 1) alert( 'third' );
if (-1 || 0) alert( 'pirmas' );
if (-1 && 0) alert( 'antras' );
if (null || -1 && 1) alert( 'trečias' );
```

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```js run demo
let userName = prompt("Who's there?", '');
let userName = prompt("Kas čia?", '');

if (userName == 'Admin') {

let pass = prompt('Password?', '');
let pass = prompt('Slaptažodis?', '');

if (pass == 'TheMaster') {
alert( 'Welcome!' );
alert( 'Sveiki!' );
} else if (pass == '' || pass == null) {
alert( 'Canceled' );
alert( 'Atšaukta' );
} else {
alert( 'Wrong password' );
alert( 'Neteisingas slaptažodis' );
}

} else if (userName == '' || userName == null) {
alert( 'Canceled' );
alert( 'Atšaukta' );
} else {
alert( "I don't know you" );
alert( "Aš jūsų nepažįstu" );
}
```

Note the vertical indents inside the `if`blocks. They are technically not required, but make the code more readable.
Atkreipkite dėmesį į vertikalius įgilėjimus viduje `if`rinkinio. Techniškai jie nėra būtini, bet jie paverčia kodą lengviau skaitomu.
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