Jul 26, 2021 · Jul 26, 2021 · Jul 26, 2021 · Jul 26, 2021 · Jul 26, 2021 · Jul 26, 2021
diff --git a/1-js/02-first-steps/10-ifelse/1-if-zero-string/solution.md b/1-js/02-first-steps/10-ifelse/1-if-zero-string/solution.md
 **Yes, it will.**
 **Taip, bus.**

 Any string except an empty one (and `"0"`is not empty) becomes `true`in the logical context.
 Bet kokia eilutė išskyrus tuščią (o `"0"`nėra tuščia) tampa `true`loginiame kontekste.

 We can run and check:
 Mes galime paleisti ir patikrinti:

 ```js run
 if ("0") {
  alert( 'Hello' );
  alert( 'Labas' );
 }
 ```

diff --git a/1-js/02-first-steps/10-ifelse/1-if-zero-string/task.md b/1-js/02-first-steps/10-ifelse/1-if-zero-string/task.md

 ---

 # if (a string with zero)
 # if (eilutė su nuliu)

 Will`alert` be shown?
 Ar bus parodytas`alert`?

 ```js
 if ("0") {
  alert( 'Hello' );
  alert( 'Labas' );
 }
 ```

diff --git a/1-js/02-first-steps/10-ifelse/2-check-standard/ifelse_task2.svg b/1-js/02-first-steps/10-ifelse/2-check-standard/ifelse_task2.svg
diff --git a/1-js/02-first-steps/10-ifelse/2-check-standard/ifelse_task2/index.html b/1-js/02-first-steps/10-ifelse/2-check-standard/ifelse_task2/index.html
  <script>
    'use strict';

    let value = prompt('What is the "official" name ofJavaScript?', '');
    let value = prompt('Koks yra "oficialusJavaScript pavadinimas?', '');

    if (value == 'ECMAScript') {
      alert('Right!');
      alert('Teisingai!');
    } else {
      alert("You don't know? ECMAScript!");
      alert("Nežinote? ECMAScript!");
    }
  </script>

diff --git a/1-js/02-first-steps/10-ifelse/2-check-standard/task.md b/1-js/02-first-steps/10-ifelse/2-check-standard/task.md

 ---

 #The name ofJavaScript
 # JavaScript pavadinimas

 Using the `if..else` construct, write the code which asks: 'What is the "official" name ofJavaScript?'
 Naudodami konstruktą `if..else`, parašykite kodą, kuris klausia: 'Koks yra "oficialusJavaScript pavadinimas?'

 If the visitor enters"ECMAScript",then output "Right!",otherwise--output: "Didn't know? ECMAScript!"
 Jeigu lankytojas įveda"ECMAScript",tada gaunamas "Teisingai!",kitu atveju--gaunamas: "Nežinojote? ECMAScript!"

 ![](ifelse_task2.svg)

diff --git a/1-js/02-first-steps/10-ifelse/3-sign/if_sign/index.html b/1-js/02-first-steps/10-ifelse/3-sign/if_sign/index.html
  <script>
    'use strict';

    let value = prompt('Type a number', 0);
    let value = prompt('Įrašykite skaičių', 0);

    if (value > 0) {
      alert(1);
diff --git a/1-js/02-first-steps/10-ifelse/3-sign/solution.md b/1-js/02-first-steps/10-ifelse/3-sign/solution.md


 ```js run
 let value = prompt('Type a number', 0);
 let value = prompt('Įveskite skaičių', 0);

 if (value > 0) {
  alert( 1 );
diff --git a/1-js/02-first-steps/10-ifelse/3-sign/task.md b/1-js/02-first-steps/10-ifelse/3-sign/task.md

 ---

 #Show the sign
 #Parodykite ženklą

 Using `if..else`,write the code which gets a number via`prompt`and then shows in `alert`:
 Naudodami `if..else`,parašykite kodą, kuris gauna numerį per`prompt`ir tada parodo jį per `alert`:

 - `1`,if the value is greater than zero,
 - `-1`,if less than zero,
 - `0`,if equals zero.
 - `1`,jeigu vertė yra didesnė nei nulis,
 - `-1`,jeigu mažesnė nei nulis,
 - `0`,jeigu lygus nuliui.

 In this task we assume that the input is always a number.
 Šioje užduotyje mes tariame, kad visada yra įvedamas numeris.

 [demo src="if_sign"]
diff --git a/1-js/02-first-steps/10-ifelse/5-rewrite-if-question/solution.md b/1-js/02-first-steps/10-ifelse/5-rewrite-if-question/solution.md


 ```js
 let result = (a + b < 4) ? 'Below' : 'Over';
 let result = (a + b < 4) ? 'Žemiau' : 'Aukščiau';
 ```

diff --git a/1-js/02-first-steps/10-ifelse/5-rewrite-if-question/task.md b/1-js/02-first-steps/10-ifelse/5-rewrite-if-question/task.md

 ---

 #Rewrite 'if'into '?'
 #Perrašykite 'if'į '?'

 Rewrite this `if`using the conditional operator `'?'`:
 Perrašykite šį `if`naudodami sąlygos operatorių `'?'`:

 ```js
 let result;

 if (a + b < 4) {
  result = 'Below';
  result = 'Žemiau';
 } else {
  result = 'Over';
  result = 'Aukščiau';
 }
 ```
diff --git a/1-js/02-first-steps/10-ifelse/6-rewrite-if-else-question/solution.md b/1-js/02-first-steps/10-ifelse/6-rewrite-if-else-question/solution.md


 ```js
 let message = (login == 'Employee') ? 'Hello' :
  (login == 'Director') ? 'Greetings' :
  (login == '') ? 'No login' :
 let message = (login == 'Darbuotojas') ? 'Labas' :
  (login == 'Direktorius') ? 'Sveiki' :
  (login == '') ? 'Nėra prisijungimo' :
  '';
 ```

diff --git a/1-js/02-first-steps/10-ifelse/6-rewrite-if-else-question/task.md b/1-js/02-first-steps/10-ifelse/6-rewrite-if-else-question/task.md

 ---

 #Rewrite 'if..else'into '?'
 #Perrašykite 'if..else'į '?'

 Rewrite `if..else`using multiple ternary operators `'?'`.
 Perrašykite `if..else`naudodami daugybinius ternarinius operatorius `'?'`.

 For readability, it's recommended to split the code into multiple lines.
 Dėl skaitomo rekomenduoja išskirti kodą į kelias eiles.

 ```js
 let message;

 if (login == 'Employee') {
  message = 'Hello';
 } else if (login == 'Director') {
  message = 'Greetings';
 if (login == 'Darbuotojas') {
  message = 'Labas';
 } else if (login == 'Direktorius') {
  message = 'Sveiki';
 } else if (login == '') {
  message = 'No login';
  message = 'Nėra prisijungimo';
 } else {
  message = '';
 }
Original file line number	Diff line number	Diff line change
		@@ -1,12 +1,12 @@
		Yes, it will.
		Taip, bus.

		Any string except an empty one (and `"0"`is not empty) becomes `true`in the logical context.
		Bet kokia eilutė išskyrus tuščią (o `"0"`nėra tuščia) tampa `true`loginiame kontekste.

		We can run and check:
		Mes galime paleisti ir patikrinti:

		```js run
		if ("0") {
		alert( 'Hello' );
		alert( 'Labas' );
		}
		```
Original file line number	Diff line number	Diff line change
Expand Up		@@ -2,13 +2,13 @@ importance: 5

		---

		# if (a string with zero)
		# if (eilutė su nuliu)

		Will`alert` be shown?
		Ar bus parodytas`alert`?

		```js
		if ("0") {
		alert( 'Hello' );
		alert( 'Labas' );
		}
		```
Original file line number	Diff line number	Diff line change
Expand Up		@@ -5,12 +5,12 @@
		<script>
		'use strict';

		let value = prompt('What is the "official" name ofJavaScript?', '');
		let value = prompt('Koks yra "oficialusJavaScript pavadinimas?', '');

		if (value == 'ECMAScript') {
		alert('Right!');
		alert('Teisingai!');
		} else {
		alert("You don't know? ECMAScript!");
		alert("Nežinote? ECMAScript!");
		}
		</script>

Expand Down
Original file line number	Diff line number	Diff line change
Expand Up		@@ -2,11 +2,11 @@ importance: 2

		---

		#The name ofJavaScript
		# JavaScript pavadinimas

		Using the `if..else` construct, write the code which asks: 'What is the "official" name ofJavaScript?'
		Naudodami konstruktą `if..else`, parašykite kodą, kuris klausia: 'Koks yra "oficialusJavaScript pavadinimas?'

		If the visitor enters"ECMAScript",then output "Right!",otherwise--output: "Didn't know? ECMAScript!"
		Jeigu lankytojas įveda"ECMAScript",tada gaunamas "Teisingai!",kitu atveju--gaunamas: "Nežinojote? ECMAScript!"

		![](ifelse_task2.svg)

Expand Down
Original file line number	Diff line number	Diff line change
Expand Up		@@ -6,7 +6,7 @@
		<script>
		'use strict';

		let value = prompt('Type a number', 0);
		let value = prompt('Įrašykite skaičių', 0);

		if (value > 0) {
		alert(1);
Expand Down
Original file line number	Diff line number	Diff line change
		@@ -1,7 +1,7 @@


		```js run
		let value = prompt('Type a number', 0);
		let value = prompt('Įveskite skaičių', 0);

		if (value > 0) {
		alert( 1 );
Expand Down
Original file line number	Diff line number	Diff line change
Expand Up		@@ -2,14 +2,14 @@ importance: 2

		---

		#Show the sign
		#Parodykite ženklą

		Using `if..else`,write the code which gets a number via`prompt`and then shows in `alert`:
		Naudodami `if..else`,parašykite kodą, kuris gauna numerį per`prompt`ir tada parodo jį per `alert`:

		- `1`,if the value is greater than zero,
		- `-1`,if less than zero,
		- `0`,if equals zero.
		- `1`,jeigu vertė yra didesnė nei nulis,
		- `-1`,jeigu mažesnė nei nulis,
		- `0`,jeigu lygus nuliui.

		In this task we assume that the input is always a number.
		Šioje užduotyje mes tariame, kad visada yra įvedamas numeris.

		[demo src="if_sign"]
Original file line number	Diff line number	Diff line change
		@@ -1,6 +1,6 @@


		```js
		let result = (a + b < 4) ? 'Below' : 'Over';
		let result = (a + b < 4) ? 'Žemiau' : 'Aukščiau';
		```
Original file line number	Diff line number	Diff line change
Expand Up		@@ -2,16 +2,16 @@ importance: 5

		---

		#Rewrite 'if'into '?'
		#Perrašykite 'if'į '?'

		Rewrite this `if`using the conditional operator `'?'`:
		Perrašykite šį `if`naudodami sąlygos operatorių `'?'`:

		```js
		let result;

		if (a + b < 4) {
		result = 'Below';
		result = 'Žemiau';
		} else {
		result = 'Over';
		result = 'Aukščiau';
		}
		```
Original file line number	Diff line number	Diff line change
		@@ -1,9 +1,9 @@


		```js
		let message = (login == 'Employee') ? 'Hello' :
		(login == 'Director') ? 'Greetings' :
		(login == '') ? 'No login' :
		let message = (login == 'Darbuotojas') ? 'Labas' :
		(login == 'Direktorius') ? 'Sveiki' :
		(login == '') ? 'Nėra prisijungimo' :
		'';
		```