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A typo in the article#3539
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@@ -50,7 +50,7 @@ let mсs = 0.000001; | |||
Just like before, using `"e"` can help. If we'd like to avoid writing the zeroes explicitly, we could write the same as: | |||
```js | |||
let mcs = 1e-6; //five zeroes to the left from 1 | |||
let mcs = 1e-6; //six zeroes to the left from 1 |
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not helpful. perhaps:
let mcs = 1e-6; // five zeroes to the left of 1 (to the right of the decimal point)
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There is no such “up to the decimal point” condition here. Besides, literally after this sentence comes the following:
If we count the zeroes in
0.000001
, there are6 of them. So naturally it's1e-6
.
shallow-beachAug 27, 2024 • edited
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edited
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Besides, literally after this sentence
then fix that too:
If we count the zeroes in
0.000001
, there are5 of them after the decimal point. So naturally it's1e-6
.
(also note i edited first suggestion to specifyto the right of decimal point, i figure you saw original through email or smt.)
same confusion as#3541 |
I never liked the "zeroes count" explanation. We have decimal notation. It comes with a key property: 1.23e-9 moves the decimal point 9 places to the left. "Naturally" for real, no need for extra steps I couldn't figure out how to change the text without ruining it. |
shallow-beach commentedSep 8, 2024 • edited
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zeros count makes sense in that |
It's easier to think that way, don't you think?applying directly |
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Numbers
There are six zeroes to the left from$\large1$ in$\large0.000001$ , not five.