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Improved tasks 175-184#1982

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Merged
javadev merged 1 commit intojavadev:mainfromjscrdev:improve-175-184
May 22, 2025
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12 changes: 10 additions & 2 deletionssrc/main/java/g0101_0200/s0175_combine_two_tables/script.sql
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@@ -1,4 +1,12 @@
# Write your MySQL query statement below
# #Easy #Database #SQL_I_Day_5_Union #2022_06_26_Time_491_ms_(32.30%)_Space_0B_(100.00%)
SELECT FirstName, LastName, City, State
FROM Person LEFT JOIN Address USING (PersonId)
SELECT
FirstName,
LastName,
City,
State
FROM
Person
LEFT JOIN
Address
USING (PersonId);
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@@ -1,9 +1,13 @@
# Write your MySQL query statement below
# #Medium #Database #SQL_I_Day_4_Union_and_Select
# #2022_07_10_Time_225_ms_(73.10%)_Space_0B_(100.00%)
SELECT ifnull(
(SELECT distinct(Salary)
FROM Employee
ORDER BY Salary DESC
LIMIT 1
OFFSET 1), NULL) SecondHighestSalary;
SELECT
IFNULL(
(
SELECT DISTINCT Salary
FROM Employee
ORDER BY Salary DESC
LIMIT 1 OFFSET 1
),
NULL
) AS SecondHighestSalary;
9 changes: 8 additions & 1 deletionsrc/main/java/g0101_0200/s0178_rank_scores/script.sql
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@@ -1,3 +1,10 @@
# Write your MySQL query statement below
# #Medium #Database #2022_06_26_Time_290_ms_(66.73%)_Space_0B_(100.00%)
select Score, DENSE_RANK() OVER(order by Score Desc) as "Rank" from Scores order by "Rank" Asc;
SELECT
Score,
DENSE_RANK() OVER (ORDER BY Score DESC) AS Rank
FROM
Scores
ORDER BY
Rank ASC;

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@@ -1,7 +1,11 @@
# Write your MySQL query statement below
# #Medium #Database #2024_07_15_Time_469_ms_(89.19%)_Space_0B_(100.00%)
SELECT DISTINCT l1.num AS ConsecutiveNums
FROM Logs l1
JOIN Logs l2 ON l1.id = l2.id - 1
JOIN Logs l3 ON l1.id = l3.id - 2
WHERE l1.num = l2.num AND l2.num = l3.num;
SELECT DISTINCT
l1.num AS ConsecutiveNums
FROM
Logs l1
JOIN Logs l2 ON l1.id = l2.id - 1
JOIN Logs l3 ON l1.id = l3.id - 2
WHERE
l1.num = l2.num
AND l2.num = l3.num;
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@@ -1,4 +1,10 @@
# Write your MySQL query statement below
# #Easy #Database #2022_06_27_Time_315_ms_(94.44%)_Space_0B_(100.00%)
select a.Name as Employee from Employee a left join Employee b on a.ManagerId=b.Id
where a.Salary > b.Salary and a.ManagerId is not null
SELECT
a.Name AS Employee
FROM
Employee a
LEFT JOIN Employee b ON a.ManagerId = b.Id
WHERE
a.Salary > b.Salary
AND a.ManagerId IS NOT NULL;
10 changes: 9 additions & 1 deletionsrc/main/java/g0101_0200/s0182_duplicate_emails/script.sql
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@@ -1,3 +1,11 @@
# Write your MySQL query statement below
# #Easy #Database #SQL_I_Day_10_Where #2022_06_27_Time_303_ms_(92.08%)_Space_0B_(100.00%)
SELECT Email FROM Person GROUP BY Email HAVING COUNT(Email) > 1;
SELECT
Email
FROM
Person
GROUP BY
Email
HAVING
COUNT(Email) > 1;

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@@ -1,7 +1,9 @@
# Write your MySQL query statement below
# #Easy #Database #SQL_I_Day_1_Select #2022_06_27_Time_376_ms_(98.73%)_Space_0B_(100.00%)
SELECT c.Name as Customers
FROM Customers as c
LEFT JOIN Orders as o
ON c.Id = o.CustomerId
WHERE o.CustomerId is null
SELECT
c.Name AS Customers
FROM
Customers AS c
LEFT JOIN Orders AS o ON c.Id = o.CustomerId
WHERE
o.CustomerId IS NULL;
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Expand Up@@ -5,13 +5,18 @@ SELECT
Sel.Name AS Employee,
Sel.Salary AS Salary
FROM
(
SELECT
Name,
Salary,
DepartmentId,
DENSE_RANK() OVER (PARTITION BY DepartmentId ORDER BY Salary DESC) AS dr
FROM Employee
) AS Sel
INNER JOIN Department d ON d.Id = Sel.DepartmentId
WHERE Sel.dr = 1
(
SELECT
Name,
Salary,
DepartmentId,
DENSE_RANK() OVER (
PARTITION BY DepartmentId
ORDER BY Salary DESC
) AS dr
FROM
Employee
) AS Sel
INNER JOIN Department d ON d.Id = Sel.DepartmentId
WHERE
Sel.dr = 1;
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