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WDFT REMOTE MAR22 Fevi#2932
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| num += number; | ||
| } | ||
| return num / numbersAvg.length; | ||
| }; | ||
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Really good work, Fevi!
| const wordsArr = ['seat', 'correspond', 'linen', 'motif', 'hole', 'smell', 'smart', 'chaos', 'fuel', 'palace']; | ||
| function averageWordLength() { } | ||
| averageWordLength = wordsArr.join('').length / wordsArr.length | ||
| console.log(averageWordLength); | ||
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I think here you just had a wrong thinking, if you look at the solution in the Student Portal, then you will understand it quickly!
| ]; | ||
| function uniquifyArray() {} | ||
| function uniquifyArray(wordsUnique) { | ||
| const uniqueArray = []; | ||
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here you miss the if condition:
if (wordsUnique.length == 0){ return null }| const uniqueNames = uniquifyArray(wordsUnique); | ||
| console.log(uniqueNames); | ||
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For the last tasks I would say: look at the solution in your own time and if you have any questions, ask Karina, Marian or me (Joanne).
| function doesWordExist(wordsFind, word) { | ||
| if (wordsFind.length === 0) return null; | ||
| for (let el of wordsFind) { | ||
| if (el === 'disobedience') return true; |
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But one more thing: you never know which words you really have in the array. So you can't compare with specific words. It should work for any array of words.
This pull request has been automatically marked as stale because it didn't have any recent activity. It will be closed if no further activity occurs. Thank you for your contributions. |
This pull request is closed. Thank you. |
I couldn't solve Iteration#4 Level 2 with a function.
Iteration#5 was also a bit tricky.