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0027: Remove Element#3
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30 changes: 30 additions & 0 deletions0027-Remove_Element/main.ts
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// let nums = [3, 2, 2, 3], | ||
// val = 3, | ||
// expectedNums = [2, 2]; | ||
let nums = [0, 1, 2, 2, 3, 0, 4, 2], | ||
val = 2, | ||
expectedNums = [0, 1, 3, 0, 4]; | ||
function removeElement(nums: number[], val: number): number { | ||
let slowIndex = 0; | ||
for (let fastIndex = 0; fastIndex < nums.length; fastIndex++) { | ||
if (nums[fastIndex] !== val) { | ||
nums[slowIndex] = nums[fastIndex]; | ||
slowIndex++; | ||
} | ||
} | ||
return slowIndex; | ||
} | ||
let k = removeElement(nums, val); | ||
console.assert(k === expectedNums.length, "Length mismatch"); | ||
nums.slice(0, k).sort((a, b) => a - b); | ||
for (let i = 0; i < k; i++) { | ||
console.assert(nums[i] === expectedNums[i], `Element mismatch at index ${i}`); | ||
} | ||
console.log(k); | ||
console.log(nums); |
50 changes: 50 additions & 0 deletions0027-Remove_Element/readme.md
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# 27. Remove Element | ||
Given an integer array `nums` and an integer `val`, remove all occurrences of `val` in `nums` [in-place](https://en.wikipedia.org/wiki/In-place_algorithm). The order of the elements may be changed. Then return the number of elements in `nums` which are not equal to `val`. | ||
Consider the number of elements in `nums` which are not equal to `val` be `k`, to get accepted, you need to do the following things: | ||
- Change the array `nums` such that the first `k` elements of `nums` contain the elements which are not equal to `val`. The remaining elements of `nums` are not important as well as the size of `nums`. | ||
- Return `k`. | ||
### Custom Judge: | ||
The judge will test your solution with the following code: | ||
``` | ||
int[] nums = [...]; // Input array | ||
int val = ...; // Value to remove | ||
int[] expectedNums = [...]; // The expected answer with correct length. | ||
// It is sorted with no values equaling val. | ||
int k = removeElement(nums, val); // Calls your implementation | ||
assert k == expectedNums.length; | ||
sort(nums, 0, k); // Sort the first k elements of nums | ||
for (int i = 0; i < actualLength; i++) { | ||
assert nums[i] == expectedNums[i]; | ||
} | ||
``` | ||
If all assertions pass, then your solution will be accepted. | ||
### Example 1: | ||
> <span style="color: white;">Input: </span>nums = [3, 2, 2, 3], val = 3<br> | ||
> <span style="color: white;">Output: </span>2, nums = [2, 2, _, _]<br> | ||
> <span style="color: white;">Explanation: </span>Your function should return k = 2, with the first two elements of nums being 2.<br> | ||
> It does not matter what you leave beyond the returned k (hence they are underscores). | ||
### Example 2: | ||
> <span style="color: white;">Input: </span>nums = [0, 1, 2, 2, 3, 0, 4, 2], val = 2<br> | ||
> <span style="color: white;">Output: </span>5, nums = [0, 1, 4, 0, 3, _, _, _]<br> | ||
> <span style="color: white;">Explanation: </span>Your function should return k = 5, with the first five elements of nums containing 0, 0, 1, 3, and 4.<br> | ||
Note that the five elements can be returned in any order.<br> | ||
It does not matter what you leave beyond the returned k (hence they are underscores). | ||
### Constraints: | ||
- `0 <= nums.length <= 100` | ||
- `0 <= nums[i] <= 50` | ||
- `0 <= val <= 100` |
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