Chatgpt disagrees: Great question — you're close, but the change you've made is not correct from a geometric and mathematical standpoint. Let’s clarify: ✅ Original (correct) version: You can see that this set of points is exactly the set of points for which the projection onto 𝑎 a is the point 𝐶 ⋅ 𝑎 ∣ 𝑎 ∣ C⋅ ∣a∣ a , and they form a hyperplane orthogonal to 𝑎 a. This is correct, because: The projection length is constant (equal to 𝐶 C), so the actual point on the line of 𝑎 a is at a distance of 𝐶 C units along the direction of 𝑎 a. The unit vector in the direction of 𝑎 a is 𝑎 ∣ 𝑎 ∣ ∣a∣ a , so scaling it by 𝐶 C gives you the fixed projection point. ❌ Your modified version: ... the projection onto 𝑎 a is the point 𝐶 ⋅ 𝑎 ∣ 𝑎 ∣ 2 C⋅ ∣a∣ 2 a This is incorrect, because: 𝑎 ∣ 𝑎 ∣ 2 ∣a∣ 2 a is not a unit vector — it's a scaled-down version of 𝑎 a. This form appears in a different context: when you’re projecting a vector onto another vector, the formula for projection is: proj 𝑎 ( 𝑟 )𝑟 ⋅ 𝑎 ∣ 𝑎 ∣ 2 ⋅ 𝑎 proj a (r)= ∣a∣ 2 r⋅a ⋅a But here you're describing the set of vectors whose dot product with 𝑎 a is constant, not projecting a specific vector onto another. ✅ TL;DR: Keep the original form: 𝐶 ⋅ 𝑎 ∣ 𝑎 ∣ C⋅ ∣a∣ a It is geometrically meaningful and correct — describing a point lying at a fixed distance 𝐶 C along the direction of 𝑎 a, which is how the hyperplane is constructed. Let me know if you'd like a visual explanation of this with an example or diagram. You said: Yes ChatGPT said: Great! Let’s walk through a visual explanation of the statement: “The set of points 𝑟 r such that 𝑟 ⋅ 𝑎𝐶 r⋅a=C form a hyperplane orthogonal to 𝑎 a, and the projection of any such 𝑟 r onto 𝑎 a is the point 𝐶 ⋅ 𝑎 ∣ 𝑎 ∣ C⋅ ∣a∣ a .” 🧠 Step-by-step Visual Intuition: - What does
𝑟 ⋅ 𝑎 = 𝐶 r⋅a=C mean? The dot product 𝑟 ⋅ 𝑎 r⋅a is:
∣ 𝑟 ∣ ⋅ ∣ 𝑎 ∣ ⋅ cos 𝜃 ∣r∣⋅∣a∣⋅cosθ where 𝜃 θ is the angle between 𝑟 r and 𝑎 a. So fixing 𝑟 ⋅ 𝑎𝐶 r⋅a=C means all such vectors 𝑟 r have the same projection onto 𝑎 a. - Geometric meaning of constant projection
Imagine you have a vector 𝑎 a, and you're projecting various points in space (vectors 𝑟 r) onto the direction of 𝑎 a. If all those projections land at the same spot on the line of 𝑎 a, those points form a flat surface (or line, in 2D) that is perpendicular to 𝑎 a.
That surface is called a hyperplane orthogonal to 𝑎 a. - Where does the point
𝐶 ⋅ 𝑎 ∣ 𝑎 ∣ C⋅ ∣a∣ a come from? This is the actual point on the vector 𝑎 a's line that is:
Distance 𝐶 C away in the direction of 𝑎 a (since 𝑎 a is a vector), Scaled by the unit vector in that direction: 𝑎 ∣ 𝑎 ∣ ∣a∣ a So: Projection point𝐶 ⋅ 𝑎 ∣ 𝑎 ∣ Projection point=C⋅ ∣a∣ a This point is where all the projections of 𝑟 r's in the set fall. It's the foot of the perpendicular from the hyperplane onto the vector 𝑎 a. 📐 Diagram (conceptual) pgsql Copy code * / | <-- vector r / | / | / | <-- All these r's project to the same spot / | ------------------------> ^ ^ origin projection point = C * (a / |a|) --> direction of vector a
✅ Summary The correct projection point is: 𝐶 ⋅ 𝑎 ∣ 𝑎 ∣ C⋅ ∣a∣ a because it describes a fixed location on the line in direction of 𝑎 a. The set of all vectors 𝑟 r with dot product 𝑟 ⋅ 𝑎𝐶 r⋅a=C form a hyperplane orthogonal to 𝑎 a, and all of them project onto the same point. Let me know if you'd like an actual drawn diagram or want to see this in code or coordinate form! |
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I guess for$\mathbf r\cdot \mathbf a = C$ the point of projection is$\mathbf r \cos \theta$ which is of magnitude$C/|\mathbf a|$ and has direction of$\hat{a}$ (unit vec along${\mathbf a}$ ) so the point is$C \cdot \dfrac{ \hat{\mathbf{a}}}{|\mathbf a|}$ which evaluates to the point$C \cdot \dfrac{\mathbf a}{|\mathbf a|^2}$