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Commit8073930

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add distinct subseq
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‎distinct-subsequences/README.md

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##Guessing
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Lets start with`rabbbit` and`rabbit`.
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To make the problem easier, start from one char,`distinct subsequences` of`rabbbit` and`r`.
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`distinct subsequences` below, by eyeball:
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*`r` and`r` has 1`distinct subsequences`
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*`a` and`r` has 0`distinct subsequences`
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These two are easy to be understood.
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*`ra` and`r` has 1`distinct subsequences`
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*`rab` and`r` has 1`distinct subsequences`
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*`rabbbbbbbbbbbb` and`r` has 1`distinct subsequences`
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These three show that`r` plus any junk chars will not change`distinct subsequences`
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*`rr` and`r` has 2`distinct subsequences`
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*`rar` and`r` has 2`distinct subsequences`
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*`rara` and`r` has 2`distinct subsequences`
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*`rarar` and`r` has 3`distinct subsequences`
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`rar` and`r` is same as`rr` and`r`, because`a` there has nothing to do with the number of`distinct subsequences`, it is a junk like above.
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In another word,`rar` and`r` can be converted to`ra` +`r` and`r`, that is`1 + 1`.
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###Put them into table
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the value`P[i][j]` means that`S[0..i]` and`T[0..j]` has`P[i][j]``distinct subsequences`.
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the table with only one char
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```
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+---+---+---+---+---+---+---+---+
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| | r | a | b | b | b | i | t |
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+---+---+---+---+---+---+---+---+
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| r | 1 | 1 | 1 | 1 | 1 | 1 | 1 |
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+---+---+---+---+---+---+---+---+
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```
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Enlarge the table
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```
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+---+---+---+---+---+---+---+---+
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| | r | a | b | b | b | i | t |
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+---+---+---+---+---+---+---+---+
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| r | 1 | 1 | 1 | 1 | 1 | 1 | 1 |
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+---+---+---+---+---+---+---+---+
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| a | | | | | | | |
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+---+---+---+---+---+---+---+---+
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| b | | | | | | | |
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+---+---+---+---+---+---+---+---+
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| b | | | | | | | |
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+---+---+---+---+---+---+---+---+
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| i | | | | | | | |
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+---+---+---+---+---+---+---+---+
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| t | | | | | | | |
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+---+---+---+---+---+---+---+---+
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```
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Some grids here are easy to be filled, the grids which`j > i`.
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That is, T is longer than S, there will be no`distinct subsequences`.
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```
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+---+---+---+---+---+---+---+---+
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| | r | a | b | b | b | i | t |
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+---+---+---+---+---+---+---+---+
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| r | 1 | 1 | 1 | 1 | 1 | 1 | 1 |
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+---+---+---+---+---+---+---+---+
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| a | 0 | | | | | | |
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+---+---+---+---+---+---+---+---+
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| b | 0 | 0 | | | | | |
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+---+---+---+---+---+---+---+---+
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| b | 0 | 0 | 0 | | | | |
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+---+---+---+---+---+---+---+---+
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| i | 0 | 0 | 0 | 0 | | | |
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+---+---+---+---+---+---+---+---+
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| t | 0 | 0 | 0 | 0 | 0 | | |
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+---+---+---+---+---+---+---+---+
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```
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`j == i` grids are easy too, the S and T must be the same if it wants to have 1`distinct subsequences`.
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```
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+---+---+---+---+---+---+---+---+
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| | r | a | b | b | b | i | t |
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+---+---+---+---+---+---+---+---+
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| r | 1 | 1 | 1 | 1 | 1 | 1 | 1 |
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+---+---+---+---+---+---+---+---+
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| a | 0 | 1 | | | | | |
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+---+---+---+---+---+---+---+---+
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| b | 0 | 0 | 1 | | | | |
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+---+---+---+---+---+---+---+---+
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| b | 0 | 0 | 0 | 1 | | | |
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+---+---+---+---+---+---+---+---+
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| i | 0 | 0 | 0 | 0 | 0 | | |
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+---+---+---+---+---+---+---+---+
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| t | 0 | 0 | 0 | 0 | 0 | 0 | |
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+---+---+---+---+---+---+---+---+
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```
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This pictrue is just encouraging you, as there is only a few grids left to be filled.
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###`rab` and`ra`
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This problem looks familiar. It is the`ra` and`r`.
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as`b` is a junk char,`rab` should have the same number as`ra` and`ra`.
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Then the table is like
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```
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+---+---+---+---+---+---+---+---+
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| | r | a | b | b | b | i | t |
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+---+---+---+---+---+---+---+---+
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| r | 1 | 1 | 1 | 1 | 1 | 1 | 1 |
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+---+---+---+---+---+---+---+---+
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| a | 0 | 1 | 1 | 1 | 1 | 1 | 1 |
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+---+---+---+---+---+---+---+---+
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| b | 0 | 0 | 1 | | | | |
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+---+---+---+---+---+---+---+---+
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| b | 0 | 0 | 0 | 1 | | | |
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+---+---+---+---+---+---+---+---+
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| i | 0 | 0 | 0 | 0 | 0 | | |
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+---+---+---+---+---+---+---+---+
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| t | 0 | 0 | 0 | 0 | 0 | 0 | |
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+---+---+---+---+---+---+---+---+
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```
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###`rabb` and`rab`
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This time, add a new`b` to both`rab` and`ra`.
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####Use the new`b` in subsequences
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This time they have same letter,`b` , at the end. It is not a junk.
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This time, remove`b` from both S and T, then they become`rab` and`ra`.
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that is, this will take`rab` and`ra``distinct subsequences`.
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####Dont use the new`b`
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Treat`b` as junk, it has`rab` and`rab``distinct subsequences`.
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####Sum up two choices
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Use or not will result two set of`distinct subsequences`, so sum them up.
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`rabb` and`rab` =`rab` and`ra` +`rab` and`rab`.
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```
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+---+---+---+---+---+---+---+---+
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| | r | a | b | b | b | i | t |
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+---+---+---+---+---+---+---+---+
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| r | 1 | 1 | 1 | 1 | 1 | 1 | 1 |
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+---+---+---+---+---+---+---+---+
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| a | 0 | 1 | 1 | 1 | 1 | 1 | 1 |
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+---+---+---+---+---+---+---+---+
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| b | 0 | 0 | 1 | 2 | | | |
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+---+---+---+---+---+---+---+---+
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| b | 0 | 0 | 0 | 1 | | | |
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+---+---+---+---+---+---+---+---+
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| i | 0 | 0 | 0 | 0 | 0 | | |
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+---+---+---+---+---+---+---+---+
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| t | 0 | 0 | 0 | 0 | 0 | 0 | |
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+---+---+---+---+---+---+---+---+
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```
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##General form
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the grid`P[i][j]` has 1 choice when`S[i] != T[j]`, this only adds some junk chars.
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```
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P[i][j] = P[i - 1][j]
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```
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the grid`P[i][j]` has 2 choice when`S[i] == T[j]`
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```
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P[i][j] =
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P[i - 1][j] // adds as junk chars.
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P[i - 1][j - 1] // use the new char in the new subsequence
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```
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Fill up the table and the bottom right grid is the answer.
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##TODO
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* write down thinking
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